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Fundamental Statistical Mechanics

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Define a reduced distribution function that depends on x only:<br />

1<br />

∫<br />

W n (x) = dyρ n (x, y)<br />

0<br />

1<br />

2<br />

= ∫ dyρ n−1 (x 2,2y) + ∫ dyρ n −1 ((x +1) 2,2y −1)<br />

0<br />

1<br />

1<br />

2<br />

Change to a variable y ′ = 2y in the first integral and to y ′ = 2y −1 in the second integral:<br />

Wn (x) = 1<br />

2<br />

1<br />

∫<br />

0<br />

d ′ y ρn−1 ( x 2 , ′ y ) +ρ x +1<br />

( n−1 ( 2 , y ′ ) )<br />

= 1<br />

2 W ⎛ x<br />

n−1⎝<br />

2<br />

⎞<br />

⎠ + W ⎛<br />

⎛ x +1⎞<br />

⎞<br />

n−1<br />

⎝<br />

⎝ 2 ⎠ ⎠<br />

This is the model Boltzmann equation that is associated with the baker's transformation. We<br />

notice that the time is discrete rather than continuous, and that we have selected the x coordinate<br />

for some reason that is not yet clear. It is easy to check that if Wn does not depend on x then<br />

Wn remains constant in time. Thus there is an equilibrium distribution W 0 = constant , which<br />

corresponds to a uniform distribution on the unit x interval.<br />

The H -theorem is constructed in the same way as is done for the Boltzmann equation itself. We<br />

define<br />

1<br />

∫<br />

( )<br />

H n = dxW n (x)ln W n (x)<br />

0<br />

Then H develops in time as<br />

1<br />

Hn +1 = dx 1 2 Wn ( x ( 2 ) + Wn ( )ln<br />

∫<br />

0<br />

.<br />

x +1<br />

2 )<br />

1<br />

2 Wn ( x x +1<br />

[ ( 2 ) + Wn ( 2 ) ) ]<br />

as the function F(y) = y ln y is convex, it follows that 1 a +b<br />

2 ( F(a) + F(b) )≥F( 2 ) . Setting<br />

a = Wn ( x x +1<br />

2) and b = Wn ( 2 ) we have:<br />

Hn +1 ≤ 1 2 dx W n ( x 2)ln Wn ( x 1<br />

∫<br />

2)<br />

0<br />

x +1<br />

x +1<br />

( ( )+ Wn ( 2 )ln( W n ( 2 ) ) )<br />

Change to ′<br />

x = x 2 in the first term, and to ′<br />

x = x +1<br />

2 in the second term, we find:<br />

<strong>Statistical</strong> <strong>Mechanics</strong> Page 42

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