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Preparing for the Regents Examination Geometry, AK

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22 Label arcs with degree measures that sum<br />

to 360, as with x, 2x, 3x, 4x. Then find <strong>the</strong><br />

values of <strong>the</strong> inscribed angles.<br />

23 Parallel lines cut congruent arcs x and y.<br />

There<strong>for</strong>e,<br />

2x 2y 360<br />

x y 180<br />

Each inscribed angle is equal to one-half <strong>the</strong><br />

intercepted arc: 90.<br />

13-4 Tangents and Secants<br />

(pages 363–365)<br />

1 a<br />

b<br />

c<br />

d<br />

2 a 12 b 3<br />

3 a 3.25 b 1<br />

4 a disjoint b externally tangent<br />

c intersecting twice<br />

d internally tangent<br />

e disjoint internally<br />

f concentric<br />

5 a Sketch of two circles externally disjoint<br />

b Sketch of two intersecting circles, not<br />

tangent<br />

c Sketch of externally tangent circles<br />

d Sketch of internally tangent circles<br />

6 a 1 b 3<br />

c 2 d 4<br />

7 a 160 b 130 c 90<br />

d 40 e 180 x<br />

8 a 60 b 45 c 35<br />

d 51 e 67.5<br />

180 n<br />

9 a _ b 90 2n c<br />

n<br />

2 _<br />

2<br />

d 45 n e __<br />

180 m n<br />

2<br />

10 16<br />

11 80<br />

12 48<br />

13 234<br />

14 a 18 b 72 c 29.25<br />

15 a 11, 17, 18 b no sides equal<br />

16 a 12, 16, 20<br />

b Satisfies Pythagorean <strong>the</strong>orem:<br />

12 2 16 2 20 2<br />

17 a 10, 15, 15 b two sides are equal<br />

18 BE 4, EC 5, CF 5, AF 6, AC 11,<br />

AB 10<br />

19 AB 20, CB 20, RB 10<br />

20 AB 24, DR 14, DB 32<br />

21 OB 26, DB 36, RB 16<br />

22 OB 20, AB 2 √ 91 , CB 2 √ 91<br />

23 OB 22, CB 8 √ 6 , AB 8 √ 6 <br />

24 AB 20, CB 20, OC 15, OB 25<br />

25 Tangent segments from <strong>the</strong> same point are<br />

congruent. Base angles are equal, each measuring<br />

60. There<strong>for</strong>e, APB is equilateral.<br />

Note: Since <strong>the</strong>re are many variations of proofs,<br />

<strong>the</strong> following is simply one set of acceptable<br />

statements to complete each proof. Depending<br />

on <strong>the</strong> textbook used, <strong>the</strong> wording and <strong>for</strong>mat<br />

of reasons may differ, so <strong>the</strong>y have not been<br />

supplied <strong>for</strong> <strong>the</strong> method of congruence applied<br />

in each problem. (These solutions are intended<br />

to be used as a guide—o<strong>the</strong>r possible solutions<br />

may vary.)<br />

26 1. Let E be <strong>the</strong> point of intersection of −−<br />

AB<br />

and −−−<br />

CD .<br />

2. −−<br />

EB and −−<br />

ED are tangent segments to<br />

circle P.<br />

3. −−<br />

EB −−<br />

ED (Two tangent segments<br />

drawn from an external<br />

point are congruent.)<br />

4. −−<br />

EA and −−<br />

EC are tangent segments to<br />

circle O.<br />

5. −−<br />

EA −−<br />

EC<br />

6. −−<br />

EA −−<br />

EB ( Addition postulate)<br />

−−<br />

EC −−−<br />

CD<br />

or −−<br />

AB −−−<br />

CD<br />

13-4 Tangents and Secants 81

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