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Preparing for the Regents Examination Geometry, AK

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6. mDAB mCAD <br />

mDCB mACD<br />

7. mCAB mACB (Postulate of<br />

inequality)<br />

13 1. PQRS is a parallelogram.<br />

2. SP RQ (Definition of<br />

parallelogram)<br />

3. ST TP RQ<br />

4. ST TP QU RU<br />

or ST RU QU TP<br />

5. TP QU<br />

6. 0 QU TP (Subtraction<br />

postulate of<br />

inequality)<br />

7. 0 ST RU<br />

8. ST RU (Addition<br />

postulate of<br />

inequality)<br />

14 ___<br />

ST<br />

15 ___<br />

AB<br />

16 ___<br />

AB<br />

17 ___<br />

BC<br />

18 −−<br />

DE<br />

19 AD BD<br />

20 mB 120<br />

Note: Since <strong>the</strong>re are many variations of proofs,<br />

<strong>the</strong> following is simply one set of acceptable<br />

statements to complete each proof. Depending<br />

on <strong>the</strong> textbook used, <strong>the</strong> wording and <strong>for</strong>mat<br />

of reasons may differ, so <strong>the</strong>y have not been<br />

supplied <strong>for</strong> <strong>the</strong> method of congruence applied<br />

in each problem. (These solutions are intended<br />

to be used as a guide—o<strong>the</strong>r possible solutions<br />

may vary.)<br />

21 1. ___<br />

AD bisects CAB.<br />

2. ___<br />

BE bisects CBA.<br />

3. mDAB mEBA<br />

4. mDAB 2 mEBA 2 (Multiplication<br />

postulate of<br />

inequality)<br />

5. mCAB 2(mDAB) (Definition<br />

of bisector)<br />

6. mCBA 2(mEBA) (Definition<br />

of bisector)<br />

7. mCAB mCBA<br />

38 Chapter 7: Polygon Sides and Angles<br />

22 1. CF AE<br />

2. CF 2 AE 2 (Multiplication postlate<br />

of inequality)<br />

3. F is <strong>the</strong> midpoint of ___<br />

CD .<br />

4. CF 2 CD (Definition of<br />

midpoint)<br />

5. CD AE 2<br />

6. E is <strong>the</strong> midpoint of ___<br />

AB .<br />

7. AB AE 2 (Definition of<br />

midpoint)<br />

8. CD AB (Multiplication postulate<br />

of inequality)<br />

23 1. AC CB<br />

2. AC _<br />

2<br />

CB<br />

_<br />

2<br />

3. AD AC _<br />

2<br />

4. AD CB _<br />

2<br />

5. BE CB _<br />

2<br />

(Division postulate of<br />

inequality)<br />

(Definition of<br />

midpoint)<br />

(Definition of<br />

midpoint)<br />

6. AD BE<br />

24 Let A be <strong>the</strong> acute angle and let B be<br />

its supplement. mB 180 mA. Since<br />

mA 90, mB 90 and is <strong>the</strong>re<strong>for</strong>e<br />

obtuse by <strong>the</strong> subtraction postulate of<br />

inequality.<br />

25 Let C be <strong>the</strong> complement of A, and<br />

let D be <strong>the</strong> complement of B. mC <br />

90 mA and mC mD by <strong>the</strong> subtraction<br />

postulate of inequality.<br />

26 m1 m3 because an exterior angle is<br />

greater than ei<strong>the</strong>r nonadjacent interior angle<br />

and m1 m2. So m2 m3 by <strong>the</strong><br />

substitution postulate of inequality.<br />

27 mABC mABD because a whole is<br />

greater than its parts. mBAC mABC<br />

because <strong>the</strong>y are opposite congruent sides<br />

of a triangle. So mBAC mABD by <strong>the</strong><br />

substitution postulate of inequality, and<br />

DB DA because <strong>the</strong> greater side lies<br />

opposite <strong>the</strong> greater angle.

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