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Preparing for the Regents Examination Geometry, AK

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6 Given: BA bisects CBE<br />

1 2<br />

2 4<br />

Prove: 3 4<br />

Narrative Proof: A bisector divides an angle<br />

into two congruent angles, so 1 2.<br />

Using <strong>the</strong> transitive property of congruence,<br />

1 4. By substitution, 3 4.<br />

7 4x 3 2x 21<br />

x 12<br />

mBCA 4x 3<br />

4(12) 3<br />

45<br />

mBCE 2(45) 90<br />

8 4x 4 2(3x 21)<br />

x 23<br />

AB 4x 4<br />

4(23) 4<br />

96<br />

9 Since DE CE, <strong>the</strong>n 2x y 5y, and<br />

x 2y.<br />

AC BD<br />

6 5y (2x y) (x y)<br />

6 5y 3x 2y<br />

6 5y 3(2y) 2y<br />

6 5 y 6y 2y<br />

6 3y<br />

2 y<br />

x 2(2) 4<br />

BD 2(4) 2 4 2 16<br />

10 AB DE 8, so BD 4 and CD 2. There<strong>for</strong>e,<br />

CE 8 2 10.<br />

4-2 Proving Theorems<br />

About Angles<br />

(pages 59–61)<br />

1 If two angles are right angles, <strong>the</strong>y both have<br />

a measurement of 90. Angles with <strong>the</strong> same<br />

measure are congruent.<br />

2 If two angles are straight angles, <strong>the</strong>y both<br />

have a measurement of 180. Angles with <strong>the</strong><br />

same measure are congruent.<br />

3 If 1 is a complement of A, <strong>the</strong>n m1 <br />

90 mA. If 2 is a complement of A,<br />

<strong>the</strong>n m2 90 mA. Then m1 m2<br />

by <strong>the</strong> symmetric property and transition,<br />

and 1 2 by definition of congruence.<br />

14 Chapter 4: Congruence of Lines, Angles, and Triangles<br />

4 If 1 2, 3 is <strong>the</strong> complement of<br />

1, and 4 is <strong>the</strong> complement of 2, <strong>the</strong>n<br />

m3 90 m1 and m4 90 m2.<br />

Since m1 m2 by congruence, m3 <br />

m4 by symmetric property and transition,<br />

and 3 4 by congruence.<br />

5 If 1 is a supplement of A, <strong>the</strong>n m1 <br />

180 mA. If 2 is a supplement of A,<br />

<strong>the</strong>n m2 180 mA. Then m1 m2<br />

by <strong>the</strong> symmetric property and transition,<br />

and 1 2 by definition of congruence.<br />

6 If 1 2 and 3 is <strong>the</strong> supplement of<br />

1 and 4 is <strong>the</strong> supplement of 2, <strong>the</strong>n<br />

m3 90 m1 and m4 90 m2.<br />

Since m1 m2 by congruence, m3 <br />

m4 by symmetric property and transition,<br />

and 3 4 by congruence.<br />

7 By definition <strong>the</strong> sum of <strong>the</strong>ir measures is a<br />

straight angle or 180.<br />

8 The two angles are a linear pair so <strong>the</strong> sum<br />

of <strong>the</strong>ir measures is 180. If <strong>the</strong>y are congruent,<br />

each measure is 90; <strong>the</strong>y <strong>for</strong>m right<br />

angles and are <strong>the</strong>re<strong>for</strong>e perpendicular.<br />

9 Each angle <strong>for</strong>ms a linear pair with <strong>the</strong> same<br />

angle. They are supplementary to <strong>the</strong> same<br />

angle and are <strong>the</strong>re<strong>for</strong>e congruent.<br />

10 m2 m3 because <strong>the</strong>y are vertical angles.<br />

By substitution, 1 is complementary<br />

to 3. 1 4 because complements of <strong>the</strong><br />

same angle are congruent.<br />

11 3 <strong>for</strong>ms a linear pair with 1, 3 is supplementary<br />

to 1. Since 1 2, 3 is<br />

supplementary to 2. 4 <strong>for</strong>ms a linear pair<br />

with 2, 4 is supplementary to 2.<br />

3 4 because supplements of <strong>the</strong> same<br />

angle are congruent.<br />

12 Since <strong>the</strong>y <strong>for</strong>m a linear pair, 2 is supplementary<br />

to EDG. Since 1 and 2 have<br />

<strong>the</strong> same measure (<strong>the</strong>y are congruent), 1 is<br />

supplementary to EGD.<br />

13 Since 1 is complementary to 3,<br />

m1 m3 90. Since ACB is a right<br />

angle, m1 m2 90. By subtraction and<br />

substitution, m2 m3, so <strong>the</strong>y are congruent<br />

angles.<br />

14 By <strong>the</strong> transitive postulate, 1 3.<br />

Because <strong>the</strong>y are vertical angle pairs,<br />

1 4, and 3 6. By substitution<br />

and transition, 4 6.

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