The GNSS integer ambiguities: estimation and validation
The GNSS integer ambiguities: estimation and validation
The GNSS integer ambiguities: estimation and validation
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Since H3 ⊂ H1 ⊂ H2, starting point is to test H1 against H2. This will answer the<br />
question whether or not the model on the basis of which the float solution is computed<br />
may be considered valid or not. This is important, since the data may be contaminated<br />
by undetected errors <strong>and</strong>/or the model may not represent reality because some physical<br />
or geometrical effects are not captured correctly (e.g. multipath, atmospheric delays).<br />
<strong>The</strong> test statistic that allows to test H1 against H2 is given by ˆσ2<br />
σ 2 , <strong>and</strong> H1 is accepted<br />
when<br />
ˆσ 2<br />
σ 2 < Fα(m − n − p, ∞, 0) (3.73)<br />
where Fα(m − n − p, ∞, 0) is the critical value that corresponds to the central F -<br />
distribution, F (m − n − p, ∞, 0), <strong>and</strong> the chosen level of significance α. This test is<br />
identical to the overall model test in section 2.5.2.<br />
If the value of the test statistic has passed the test in expression (3.73), the next step<br />
is to verify whether or not hypothesis H3 may be considered valid. This means testing<br />
H3 against H1. Alternatively, one could test H3 against H2 in the case one is not sure<br />
if the first hypothesis is true. This would result in the following test:<br />
ˇσ 2<br />
σ 2 < Fα(m − p, ∞, 0) (3.74)<br />
However, testing H3 against H1 is more powerful <strong>and</strong> focuses on the question whether<br />
the fixed ambiguity vector ǎ may be considered valid. <strong>The</strong> test statistic is given by<br />
(â−ǎ) T G −1<br />
â (â−ǎ)<br />
nσ2 , which is distributed under H3 as F (n, ∞, 0). Hence, the fixed <strong>ambiguities</strong><br />
are considered valid if:<br />
(â − ǎ) T G −1<br />
â (â − ǎ)<br />
nσ2 = R1<br />
nσ2 < Fα(n, ∞, 0) (3.75)<br />
Note that from equation (3.14), with the last term equal to zero, it follows that:<br />
R1 = (â − ǎ) T G −1<br />
â (â − ǎ) = ěT G −1<br />
y ě − ê T G −1<br />
y ê = ˇ Ω − ˆ Ω<br />
This shows that test (3.75) can also be expressed in terms of the test statistics of (3.73)<br />
<strong>and</strong> (3.74).<br />
<strong>The</strong> test in (3.75) is based on the distance - as measured by the metric Qâ - between the<br />
float <strong>and</strong> fixed solution. This is reasonable, since one would not have much confidence<br />
in the fixed solution if the distance to the float solution is large. In that case one should<br />
not use the fixed solution <strong>and</strong> instead stick to the float solution <strong>and</strong>/or gather more data<br />
so that the <strong>estimation</strong> <strong>and</strong> <strong>validation</strong> process can be repeated.<br />
<strong>The</strong> value of the variance factor is not always known. In that case σ 2 can be replaced<br />
by ˆσ 2 , so that the test becomes:<br />
R1<br />
nˆσ 2 < Fα(n, m − n − p, 0) (3.76)<br />
<strong>The</strong> means of the test statistics of (3.73), (3.74) <strong>and</strong> (3.75) are all equal to one, whereas<br />
the mean of the test statistic of (3.76) equals (m − n − p)/(m − n − p − 2), which is<br />
Validation of the fixed solution 59