The GNSS integer ambiguities: estimation and validation
The GNSS integer ambiguities: estimation and validation
The GNSS integer ambiguities: estimation and validation
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C.4 Best <strong>integer</strong> equivariant unbiased baseline <strong>estimation</strong><br />
In practice the interest is not so much in the ambiguity solution, but in the baseline<br />
solution. Let T (â, ˆ b) with F : R n × R p ↦→ R p be the baseline estimator. Two types of<br />
restrictions will be put on the function T (x, y). <strong>The</strong> first requirement is that the if an<br />
arbitrary constant ς ∈ R p is added to the float baseline ˆ b, the fixed baseline is shifted<br />
by the same amount, i.e.<br />
T (x, y + ς) = T (x, y) + ς ∀y, ς ∈ R p<br />
It follows that if the constant is chosen ς = −y that<br />
(C.6)<br />
T (x, y) = y + f(x, 0) (C.7)<br />
<strong>The</strong> second requirement is that the fixed baseline should not change if an arbitrary<br />
<strong>integer</strong> z ∈ Z n is added to the float <strong>ambiguities</strong>:<br />
T (x + z, y) = T (x, y) ∀x ∈ R n , z ∈ Z n<br />
This is equivalent to the <strong>integer</strong> remove-restore condition of (C.1).<br />
From (C.7) <strong>and</strong> (C.8) the following representation of the baseline estimator is found:<br />
(C.8)<br />
T (x, y) = y + h(x) with h(x) periodic (C.9)<br />
Along similar lines as in section C.3 the BIE baseline estimator can be obtained.<br />
<strong>The</strong>orem C.4.1<br />
ˆT (x, y) = y + b −<br />
<br />
E{ ˆb|x + z}fâ(x + z)<br />
<br />
fâ(x + z)<br />
z∈Z n<br />
z∈Z n<br />
(C.10)<br />
is the unique minimizer of T (x, y) − b 2 f â ˆ b (x, y)dxdy within the class of <strong>integer</strong><br />
equivariant estimators, T (x, y) = y + h(x) <strong>and</strong> h(x + z) = h(x)<br />
Proof:<br />
<br />
T (x, y) − b 2 fâˆb (x, y)dxdy<br />
<br />
= y + h(x) − b 2 fâˆb (x, y)dxdy<br />
<br />
= {y − b 2 + 2h(x) T Q −1 (y − b) + h(x) 2 }fâˆb (x, y)dxdy<br />
<strong>The</strong> first term on between the braces on the right-h<strong>and</strong> side of the last equation is<br />
independent of h(x). If the remaining part is called L <strong>and</strong> q = x − z ∈ S0, the following<br />
156 <strong>The</strong>ory of BIE <strong>estimation</strong>