The GNSS integer ambiguities: estimation and validation
The GNSS integer ambiguities: estimation and validation
The GNSS integer ambiguities: estimation and validation
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oundary of the aperture pull-in region Ω0,E could be chosen as:<br />
y = ϱ · 1<br />
arg min<br />
2 z∈Zn \{0} z2Qâ with ϱ =<br />
1<br />
2<br />
µ<br />
min<br />
z∈Zn \{0} zQâ<br />
(5.59)<br />
since then y 2 Qâ = µ2 . Again the aperture parameter for OIA <strong>estimation</strong> is approximated<br />
with equation (5.58), so that y is also an element of the boundary of Ω0,OIA. It<br />
is important to note that this approach will not work in the case the ellipsoidal pull-in<br />
regions overlap, since then y /∈ S0. In that case ϱ in equation (5.59) should be set equal<br />
to one, so that y is on the boundary of S0.<br />
Figure 5.18 also shows the OIA aperture parameter as function of the fail rate as approximated<br />
using EIA. Instead of choosing y as in equation (5.59), one could also choose<br />
y = ϱ· 1<br />
2u with u the adjacent <strong>integer</strong> with the largest distance to the true <strong>integer</strong> a = 0.<br />
With the first option, the approximated aperture parameter will be too large, with the<br />
second option the approximated aperture parameter will be too small. For this example,<br />
approximation with IAB <strong>estimation</strong> works better, but still not good.<br />
5.7.2 Determination of the aperture parameter using simulations<br />
As explained at the beginning of this section, computation of the aperture parameter µ<br />
for a fixed fail rate is not possible for most IA estimators. An alternative is to determine<br />
µ numerically. <strong>The</strong>refore, simulated data are required. <strong>The</strong> procedure will be described<br />
here for the OIA estimator, but a similar approach can be followed for other IA estimators.<br />
<strong>The</strong> procedure is as follows:<br />
1. Generate N samples of normally distributed float <strong>ambiguities</strong>:<br />
âi ∼ N(0, Qâ), i = 1, . . . , N<br />
2. Determine the ILS solution:<br />
ǎi, ˇɛi = âi − ǎi, ri = fˇɛ(ˇɛi)<br />
fâ(ˇɛi)<br />
3. Choose the fail rate: Pf = β ≤ Pf,LS<br />
<strong>The</strong> fail rate as function of µ is given by: Pf (µ) = Nf<br />
N<br />
with Nf = N<br />
<br />
1 if ri ≤ µ ∧ ǎi = 0<br />
ω(ri, ǎi) <strong>and</strong> ω(ri, ǎi,) =<br />
0 otherwise<br />
4. Choose:<br />
i=1<br />
µ1 = (min(ri) − 10 −16 ) since this results in: Nf = 0 ⇒ Pf (µ1) = 0<br />
µ2 = max(ri) since this results in: Pf (µ2) = Pf,LS<br />
5. Use a root finding method to find µ ∈ [µ1, µ2] so that Pf (µ) − β = 0.<br />
This will give the solution since Pf (µ1) − β < 0 <strong>and</strong> Pf (µ2) − β > 0, <strong>and</strong> the fail<br />
rate is monotonically increasing for increasing µ, as will be shown below.<br />
118 Integer Aperture <strong>estimation</strong>