The GNSS integer ambiguities: estimation and validation
The GNSS integer ambiguities: estimation and validation
The GNSS integer ambiguities: estimation and validation
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probability<br />
1<br />
0.8<br />
0.6<br />
0.4<br />
0.2<br />
0<br />
200<br />
20<br />
0 0.2 0.4 0.6<br />
ε<br />
0.8 1 1.2<br />
Figure 4.6: Probabilities P (| ˆ b − b| ≤ ε) (dashed), P (| ˇ b − b| ≤ ε) (solid), P (| ˜ b − b| ≤ ε)<br />
(+-signs) for different number of epochs.<br />
<strong>The</strong> probabilities shown in figure 4.6 are determined by counting the number of solutions<br />
that fall within a certain interval, but it is also interesting to compare the estimators on<br />
a sample by sample basis. In order to do so, one could determine for each sample which<br />
of the three estimators is closest to the true b, <strong>and</strong> then count for each estimator how<br />
often it was better than the other estimators.<br />
In table 4.1 the probabilities<br />
P1 = P (| ˇ b−b| ≤ | ˆ b−b|), P2 = P (| ˜ b−b| ≤ | ˆ b−b|), <strong>and</strong> P3 = P (| ˜ b−b| ≤ | ˇ b−b|)<br />
are given for different number of epochs. It follows that the probability that ˜ b is better<br />
than the corresponding ˆ b is larger or equal to the probability that ˇ b is better than ˆ b. That<br />
is because the ambiguity residuals that are used to compute the fixed <strong>and</strong> BIE baseline<br />
estimator, see equations (3.4) <strong>and</strong> (4.8), have the same sign, <strong>and</strong> |â−ã| ≤ |â−ǎ| as was<br />
shown in figure 4.5. If the float baseline solution is already close to the true solution,<br />
it is possible that ˜ b is closer to b, but that ˇ b is pulled ’over’ the true solution such that<br />
ˇ b − b has the opposite sign as ˆ b − b <strong>and</strong> | ˇ b − b| > | ˆ b − b|.<br />
From the relationships between the BIE <strong>and</strong> the fixed ambiguity residuals it follows that<br />
if ˇ b is better than ˆ b, then also ˜ b will be better than ˆ b. In the case of very low precision<br />
ã ≈ â <strong>and</strong> ˜ b ≈ ˆ b, so that P2 is approximately equal to one – in the example this is the<br />
case for k = 1 <strong>and</strong> k = 2. If the precision is high, ã ≈ ǎ <strong>and</strong> as a result P3 becomes<br />
very high.<br />
Note that these results do not necessarily hold true for the higher dimensional case<br />
(n > 1).<br />
Comparison of the float, fixed, <strong>and</strong> BIE estimators 77<br />
2