Rasmus ÿstergaard forside 100%.indd - Solid Mechanics
Rasmus ÿstergaard forside 100%.indd - Solid Mechanics Rasmus ÿstergaard forside 100%.indd - Solid Mechanics
z1 z2 M = 0 M =0. ψ = arctan λ sin ω − cos(ω + γ) , λ cos ω +sin(ω + γ) λ = V Ph U M ψ = ω ℓ = h ω P M. ω K, Δu1 Δu2, Δu1 + iΔu2 = |Δu|e iφ = c1 + c2 2 √ 2π √ 1+4ɛ 2 cosh πɛ Kriɛ+1/2 e −iϕ , ϕ = arctan 2ɛ |Δu| = Δu2 1 +Δu2 2 iɛ ℓ Δu1 φ = arctan Δu2 Kℓiɛ = |Kℓiɛ |eψ . ψ ∗ = φ − ɛ ln(r/ℓ) + arctan 2ɛ, ∗ ψ G ∗ = Δu2 2 +Δu2 1 r ( 1 2 +2ɛ2 )π . c1 + c2 Δu1 ∗ G Δu2 ∗ ψ r r
G P ω r =0 ψNUM = ψ∗ (r → 0) GNUM = G∗ (r → 0). ∗ G G G GNUM 0.5% ω M =0 P = 0 ω = ψ
- Page 1: Technical University of Denmark Dep
- Page 4 and 5: £ ¥ § © ¥ § £ § ¥
- Page 6 and 7: £ ¥ § © ¥ § £ § ¥
- Page 8 and 9: ¢ ¢ ¥ § ©
- Page 10 and 11: Sandwich columns Composite Structur
- Page 12 and 13: γ
- Page 14 and 15: μi, Ei νi (i =1, 2)
- Page 16 and 17: K K = σCL iɛ+1
- Page 18 and 19: sij = ⎡ ⎢ ⎣ ν21 ν31 − −
- Page 20 and 21: ρ ρ
- Page 22 and 23: σn
- Page 24 and 25: utip,∗
- Page 26 and 27: σn ˆσ ˙λ
- Page 28 and 29: σ I n = un u∗ σ(λmax) n λmax
- Page 30 and 31: ˙δi
- Page 32 and 33: • •
- Page 34 and 35: M ∗ = Phχ+ M χ
- Page 38 and 39: ω
- Page 40 and 41: σ12H/P =0.1, 0.05, 0.01
- Page 42 and 43: B, G = (s′ 11 )#2 2B2 2 2 P M +
- Page 44 and 45: P ΔPFB Initiation ψ = −45 ◦
- Page 46 and 47: Jc [J/m 2 ] Jc [J/m 2 ] 1000 800 60
- Page 48 and 49: 2
- Page 50 and 51: Outward buckling of initially debon
- Page 52 and 53: Pcr P gl 1 0.8 0.6 0.4 0.2 0.01 0.0
- Page 54 and 55: 0.6 0.5 0.4 0.3 0.2 0.1 initial cra
- Page 56 and 57: P P gl P P gl 1 0.8 0.6 0.4 0.2 1 5
- Page 58 and 59: ˆσ
- Page 60 and 61: JR σn σt U ∗ n JR
- Page 62 and 63: E
- Page 64 and 65: σn(Un/H)ℓ EfH = Pn EfH σt(Ut
- Page 66 and 67: (Ut ≡ 0)
- Page 68 and 69: Γ/HEf.
- Page 70 and 71: α
- Page 72 and 73: ϕ = −30 ◦ ◦ −60 , ϕ = −
- Page 74 and 75: β0,
- Page 76 and 77: β0,
- Page 78 and 79: ˆσi < ˆσcore ˆσi ˆσcore
- Page 80 and 81: © ©
- Page 82 and 83: ¥
- Page 84 and 85: £
G<br />
P<br />
ω <br />
<br />
r =0 ψNUM = ψ∗ (r → 0) GNUM = G∗ <br />
<br />
(r<br />
<br />
→ 0).<br />
<br />
∗ G G<br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
G<br />
<br />
GNUM<br />
0.5%<br />
<br />
<br />
<br />
ω M =0 P = 0<br />
ω = ψ