Dynamics of Machines - Part II - IFS.pdf
Dynamics of Machines - Part II - IFS.pdf
Dynamics of Machines - Part II - IFS.pdf
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1.3 Data <strong>of</strong> the Mechanical System<br />
ρ material density <strong>of</strong> the beam 7, 800 Kg/m 3<br />
E elasticity modulus 2 × 10 11 N/m 2<br />
L total length <strong>of</strong> the beam 0.600 m<br />
b width <strong>of</strong> the beam 0.030 m<br />
h thickness 0.0012 m<br />
mi concentrated mass (i = 1, ...,6) 0.191 Kg<br />
Table 1: Data <strong>of</strong> the mass-spring system ”A”.<br />
ρ material density <strong>of</strong> the beam 7, 800 Kg/m 3<br />
E elasticity modulus 2 × 10 11 N/m 2<br />
L total length <strong>of</strong> the beam 0.300 m<br />
b width <strong>of</strong> the beam 0.025 m<br />
h thickness 0.0010 m<br />
ρ material density (steel) 7, 800 Kg/m 3<br />
mi concentrated mass (i = 1, ...,6) 0.191 Kg<br />
Table 2: Data <strong>of</strong> the mass-spring system ”B”.<br />
1.4 Calculating Equivalent Stiffness Coefficients – Beam Theory<br />
(a) (b)<br />
Figure 3: (a) Flexible beam – clamped-free boundary condition case with force applied to the end<br />
L; (b) clamped-free boundary condition case with force applied to a general position L ∗ ;<br />
By applying a vertical force F at the end <strong>of</strong> the beam as shown in figure 3(a) and using Beam<br />
Theory, one can write:<br />
EI d4y(x) = 0 (1)<br />
dx4 Integrating in X once, one has:<br />
EI d3 y(x)<br />
dx 3 = F(x) = C1 (2)<br />
5