Dynamics of Machines - Part II - IFS.pdf
Dynamics of Machines - Part II - IFS.pdf
Dynamics of Machines - Part II - IFS.pdf
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
⎧ ⎫<br />
⎪⎨<br />
˙y1(t)<br />
⎪⎬<br />
˙y(t) ˙y2(t)<br />
z(t) = =<br />
y(t) ⎪⎩<br />
y1(t) ⎪⎭<br />
y2(t)<br />
→ velocity<br />
→ velocity<br />
→ displacement<br />
→ displacement<br />
The analytical solution can be divided into three steps: (I) homogeneous solution (transient analysis);<br />
(<strong>II</strong>) permanent solution (steady-state analysis) and (<strong>II</strong>I) general solution (homogeneous<br />
+ permanent).<br />
Homogeneous Solution and Transient Analysis – The homogeneous differential equation<br />
is achieved when the right side <strong>of</strong> the equation is set zero (see eq.(55)), or in other words, when<br />
no force is acting on the system.<br />
A˙zh(t) + Bzh(t) = 0 (55)<br />
(54)<br />
zh(t) = ue λt , (assumption) (56)<br />
˙zh(t) = λue λt<br />
The assumption (56) and its derivative are introduced into the differential equation (55), leading<br />
to an eigenvalue-eigenvector problem:<br />
[λA + B]ue λt = 0 ⇒ [λA + B]u = 0 (57)<br />
• Eigenvalues λi can be calculated by using eq.(58):<br />
determinant(λA + B) = 0 ⇒ λ1 , λ2 , λ3 , λ4 (58)<br />
• Eigenvectors ui can be calculated by using eq.(59):<br />
λ1Au = −Bu ⇒ u1<br />
λ2Au = −Bu ⇒ u2<br />
λ3Au = −Bu ⇒ u3<br />
λ4Au = −Bu ⇒ u4<br />
• The homogeneous solution can be written as:<br />
zh(t) = C1u1e λ1t + C2u2e λ2t + C3u3e λ3t + C4u4e λ4t<br />
where C1, C2, C3 and C4 are constants depending on the initial displacement and velocities <strong>of</strong><br />
the coordinates y1 and y2, when t = 0.<br />
33<br />
(59)