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Dynamics of Machines - Part II - IFS.pdf

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⎧ ⎫<br />

⎪⎨<br />

˙y1(t)<br />

⎪⎬<br />

˙y(t) ˙y2(t)<br />

z(t) = =<br />

y(t) ⎪⎩<br />

y1(t) ⎪⎭<br />

y2(t)<br />

→ velocity<br />

→ velocity<br />

→ displacement<br />

→ displacement<br />

The analytical solution can be divided into three steps: (I) homogeneous solution (transient analysis);<br />

(<strong>II</strong>) permanent solution (steady-state analysis) and (<strong>II</strong>I) general solution (homogeneous<br />

+ permanent).<br />

Homogeneous Solution and Transient Analysis – The homogeneous differential equation<br />

is achieved when the right side <strong>of</strong> the equation is set zero (see eq.(55)), or in other words, when<br />

no force is acting on the system.<br />

A˙zh(t) + Bzh(t) = 0 (55)<br />

(54)<br />

zh(t) = ue λt , (assumption) (56)<br />

˙zh(t) = λue λt<br />

The assumption (56) and its derivative are introduced into the differential equation (55), leading<br />

to an eigenvalue-eigenvector problem:<br />

[λA + B]ue λt = 0 ⇒ [λA + B]u = 0 (57)<br />

• Eigenvalues λi can be calculated by using eq.(58):<br />

determinant(λA + B) = 0 ⇒ λ1 , λ2 , λ3 , λ4 (58)<br />

• Eigenvectors ui can be calculated by using eq.(59):<br />

λ1Au = −Bu ⇒ u1<br />

λ2Au = −Bu ⇒ u2<br />

λ3Au = −Bu ⇒ u3<br />

λ4Au = −Bu ⇒ u4<br />

• The homogeneous solution can be written as:<br />

zh(t) = C1u1e λ1t + C2u2e λ2t + C3u3e λ3t + C4u4e λ4t<br />

where C1, C2, C3 and C4 are constants depending on the initial displacement and velocities <strong>of</strong><br />

the coordinates y1 and y2, when t = 0.<br />

33<br />

(59)

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