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Dynamics of Machines - Part II - IFS.pdf

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(a) Amplitude [m/s 2 ]<br />

(b) Amplitude [m/s 2 ]<br />

1<br />

0.5<br />

0<br />

−0.5<br />

−1<br />

x 10 −4 Signal (a) in Time Domain − (b) in Frequency Domain<br />

0 5 10 15<br />

time [s]<br />

20 25 30<br />

0.8<br />

0.6<br />

0.4<br />

0.2<br />

x 10−5<br />

1<br />

0<br />

0 5 10 15 20 25<br />

frequency [Hz]<br />

Figure 14: Free vibration – Spring-mass systems with 1 D.O.F. One mass m = m1 = 0.191 Kg<br />

fixed at the middle <strong>of</strong> the beam L1 = 0.155 m, resulting in a system ”B” natural frequency <strong>of</strong><br />

4.94 Hz<br />

• Damping Factor <strong>of</strong> the system ”B” – From fig.13, one gets: yo = 0.95 · 10 −4 [m/s 2 ],<br />

yN = y14 = 0.50 · 10 −4 [m/s 2 ] and N = 14:<br />

ξ = <br />

1 +<br />

1<br />

2π·14 ln<br />

1<br />

2π·14 ln<br />

0.95·10 −4<br />

0.50·10 −4<br />

<br />

0.95·10 −4<br />

0.50·10 −4<br />

• Equivalent Viscous Damping (d)<br />

<br />

=<br />

2 0.007296<br />

≈ 0.007<br />

1.000026<br />

d = 2 · ξ · ωn · m = 2 · 0.007 · (4.94 · 2 · π) · 0.191 ≈ 0.08 [N · s/m]<br />

IMPORTANT CONCLUSION: THE DAMPING FACTOR IS A CHARACTER-<br />

ISTIC OF THE GLOBAL MECHANICAL SYSTEM AND SIMULTANEOUSLY DE-<br />

PENDS ON MASS m, STIFFNESS k AND DAMPING d COEFFICIENTS, NOT<br />

ONLY ON THE DAMPING COEFFICIENT, AS YOU CAN SEE IN THE DEFINI-<br />

TION:<br />

• ξ = d<br />

2·m·ωn<br />

= d1<br />

2· √ m·k<br />

IT IS POSSIBLE TO INCREASE THE DAMPING FACTOR OF A MECHANICAL<br />

SYSTEM EITHER BY DECREASING THE MASS m, OR BY DECREASING THE<br />

STIFFNESS k OR BY INCREASING THE DAMPING COEFFICIENT d. THE<br />

DAMPING FACTOR IS A VERY USEFUL PARAMETER FOR DEFINING THE<br />

RESERVE OF STABILITY IN MACHINERY DYNAMICS.<br />

23

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