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Dynamics of Machines - Part II - IFS.pdf

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1 yini − A<br />

det<br />

λ1 vini − A<br />

C2 = =<br />

1 1<br />

det<br />

−λ1(yini − A) + (vini − iωA)<br />

λ2 − λ1<br />

λ1 λ2<br />

Summarizing, below is the analytical solution <strong>of</strong> second order differential equation, which is<br />

responsible for describing the movements <strong>of</strong> the mass-damping-spring system in time domain,<br />

as a function <strong>of</strong> the excitation force and initial condition <strong>of</strong> displacement and velocity:<br />

y(t) = C1e λ1t + C2e λ2t + Ae iωt<br />

where<br />

<br />

λ1 = −ξωn − ωn 1 − ξ2 · i<br />

<br />

λ2 = −ξωn + ωn 1 − ξ2 · i<br />

A =<br />

f/m<br />

−ω 2 + ω 2 n + i2ξωnω<br />

C1 = λ1(yini − A) − (vini − iωA)<br />

λ2 − λ1<br />

C2 = −λ1(yini − A) + (vini − iωA)<br />

λ2 − λ1<br />

Numerical Solution According to Taylor’s expansion, an equation can be approximated by:<br />

f(t) ⋍ f(t0) + df<br />

<br />

<br />

<br />

<br />

dt<br />

t=t0<br />

(t − t0) + d2 f<br />

dt 2<br />

<br />

<br />

<br />

<br />

t=t0<br />

(t − t0)... + dn f<br />

dt n<br />

<br />

<br />

<br />

<br />

t=t0<br />

(40)<br />

(t − t0) (41)<br />

Assuming a very small time step t −t0 ≪ 1, the higher order terms <strong>of</strong> eq.(42) can be neglected.<br />

It turns:<br />

f(t) ⋍ f(t0) + df<br />

<br />

<br />

<br />

<br />

dt<br />

t=t0<br />

(t − t0) (42)<br />

Knowing the initial conditions <strong>of</strong> the movement when t = 0,<br />

y(0) = y0 = yini<br />

˙y(0) = ˙y0 = vini<br />

and the equation <strong>of</strong> motion, which has to be solved,<br />

¨y(t) = − 2ξωn ˙y(t) − ω 2 ny(t) + f<br />

m eiωt<br />

13<br />

(43)

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