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MODELING CHAR OXIDATION AS A FUNCTION OF PRESSURE ...

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Table 4.10. Summary of the Uncorrected and Corrected General Asymptotic<br />

Solutions for Predicting the Effectiveness Factor for m-th Order Rate Equations<br />

and Langmuir Rate Equations<br />

Rate Equation r ′ = kmC m<br />

Differential Equation<br />

and Boundary<br />

Conditions<br />

General Asymptotic<br />

Solution (within<br />

17%)<br />

m-th Order Rate Equation Langmuir rate Equation<br />

d 2 C 2 dC<br />

2 +<br />

dr r dr − Ok C = Cs at r = rs m<br />

mC De = 0<br />

dC/dr = 0 at r = 0<br />

= 1 1 1<br />

( − )<br />

MT tanh(3MT ) 3MT M T = r s<br />

3<br />

Thiele Modulus at<br />

First Order Extreme M T = r s<br />

3<br />

Thiele Modulus at<br />

Zeroth Order<br />

Extreme<br />

Corrected General<br />

Asymptotic Solution<br />

(within 2%)<br />

Correction Function<br />

f c<br />

m obs<br />

M T = r s<br />

3<br />

= f c<br />

1<br />

M T<br />

M T = r s<br />

3<br />

f c (M T ,m) = (1+<br />

(m + 1)<br />

2<br />

Ok1 De O k 0<br />

2D e C s<br />

1<br />

(<br />

tanh(3MT )<br />

(m + 1)<br />

2<br />

1<br />

2M T<br />

m<br />

Ok m −1<br />

mC De 44<br />

r ′ = k1C 1 + KC<br />

d 2 C 2 dC<br />

2 +<br />

dr r dr −<br />

Ok1C = 0<br />

De (1 + KC)<br />

C = Cs at r = rs dC/dr = 0 at r = 0<br />

= 1 1 1<br />

( − )<br />

MT tanh(3MT ) 3MT M T = r s<br />

3<br />

Ok 1<br />

2D e<br />

KC s<br />

1+ KC s<br />

1<br />

−<br />

2<br />

[KC − ln(1+ KC )] s s<br />

Two approximate M T forms:<br />

M T = r s<br />

3<br />

or<br />

M T = r s<br />

3<br />

when m=1 M T = r s<br />

3<br />

when m=0 M T = r s<br />

3<br />

1/ 2<br />

1<br />

− )<br />

3MT Ok m −1<br />

mC De 1<br />

(1− m )2<br />

2<br />

2 + 2M 2<br />

T<br />

)<br />

= f c<br />

M T = r s<br />

3<br />

1<br />

M T<br />

Ok1 / De 1<br />

2KCs +<br />

1+ KCs O k 1 / D e<br />

2KC s +1<br />

Ok1 De O k 0<br />

2D e C s<br />

when KC s=0<br />

1<br />

(<br />

tanh(3MT )<br />

Ok 1<br />

2D e<br />

KC s<br />

1+ KC s<br />

1<br />

1/2<br />

f (M , ) = (1+<br />

c T<br />

1 + KC 1<br />

s<br />

2MT when KC s=∞<br />

1<br />

1 + KC s<br />

1<br />

− )<br />

3MT 1<br />

−<br />

2<br />

[KC − ln(1+ KC )] s s<br />

2 +2M 1<br />

2<br />

)<br />

2<br />

T<br />

(1−<br />

1<br />

)<br />

1+ KCs 2

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