Contents, cont'd. - Intermec

DATEADD$
Chapter 2 Program Instructions
Field of Application Function returning a new date after a number of days have been added
to, or subtracted from, the current date or optionally a specified date.
Syntax DATEADD$([,][,])
1 2
1 is any date given according to the DATE$ format, which a
certain number of days should be added to or subtracted
from.
is the number of days to be added to (or subtracted from) the
2
current date or optionally the date specified by . 1
is an optional flag "F", indicating that the date will be returned
according to the format specified by FORMAT DATE$.
Remarks The original date () should be entered according to the syntax for the
1
DATE$ variable, i.e. in the order YYMMDD, where:
YY = Year Last two digits (e.g. 1999 = 99)
MM = Month Two digits (01–12)
DD = Day Two digits (01–28|29|30|31)
Example: June 1, 1999 is entered as "990601".
The built-in calendar corrects illegal values for the years 1980 – 2048, e.g. the
illegal date 991232 will be corrected to 000101.
The number of days to be added or subtracted should be specified as a positive
or negative numeric expression respectively.
If no "F" flag is included in the DATEADD$ function, the result will be
returned according to the DATE$ format, see above.
If the DATEADD$ function includes an "F" flag, the result will be returned
in the format specified by FORMAT DATE$.
Example 10 DATE$ = "990610"
20 A%=15
30 B%=-10
40 FORMAT DATE$ "DD/MM/YY"
50 PRINT DATEADD$("990101",A%)
60 PRINT DATEADD$("990101",A%,"F")
70 PRINT DATEADD$(B%,"F")
RUN
990116
16/01/99
31/05/99
yields:
Intermec Fingerprint 7.2 – Reference Manual Ed. 3 56