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with
H D z = αc
A e−x/λ
λ
A =
(156)
σβζ1
(αc 2 /λ + ζ1)(1+βσ) E0 . (157)
5.2.2 the conducting theory
The stationary Maxwell equation (65) is reduced to
with
∇×E D =0, (158)
E D = βc c∇×H , (159)
cf Eq (76). The connecting conditions are
E D t = E0 ey , (160)
n × E D = −βs c Ht ; (161)
the first being a result of putting E2 ≡ 0 and E D 1 ≡ 0 in Eq(110), the second
follows from Eq(126). The solutions are
E D y ≡ E0 , (162)
Hz = − 1
βc c E0 x − 1
βs c E0 . (163)
Now, comparing both results, we have finally
βc = 1+βσ
,
σ
(164)
λσ
1/βs =
2 βζ1
(αc2 .
/λ + ζ1)(1+βσ)
(165)
References
[1] K. Henjes and M. Liu, Ann. Phys. 223, 243 (1993); M. Liu, Phys. Rev. Lett.
70, 3580 (1993); Phys. Rev. E50, 2925 (1994); Phys. Rev. Lett. 74, 1884 (1995)
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