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pdf-file - Institut für Theoretische Physik

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Q D i = −(µ + c 2 ) j D i − µc j D c,i − Tf D i<br />

+c <br />

E D × H 0 + E 0 × H D<br />

i − vj Π D ij , (48)<br />

which in conjunction with Eq(45) leads to<br />

(µ + c 2 ) j D i = −µc j D c,i − Tf D i<br />

+c <br />

E D × H 0 + E 0 × H D<br />

. (49)<br />

i<br />

(It is now plain that jD i ∼ c−2 is relativistically small, and it is well justified<br />

to ignore it in non-relativistic theories.)<br />

The entropy production is<br />

R = f D ·∇ 0 T +Π D ij vij + j D c ·∇ 0 µc + j D ·∇ 0 µ + j D el E 0<br />

+E D · c <br />

∇ 0 × H 0<br />

− H D · c <br />

∇ 0 × E 0<br />

. (50)<br />

Inserting Eq (49), the number of independent thermodynamic forces is reduced<br />

by one,<br />

R = f D <br />

· ∇ 0 T − 1<br />

µ + c2 T ∇0 <br />

µ +Π D ij vij<br />

+j D <br />

c · ∇ 0 µc − 1<br />

µ + c2 µc ∇ 0 <br />

µ + j D el E 0<br />

+E D <br />

· c ∇ 0 × H 0 + 1<br />

µ + c2 H0 ×∇ 0 <br />

µ<br />

−H D <br />

· c ∇ 0 × E 0 + 1<br />

µ + c2 E0 ×∇ 0 <br />

µ . (51)<br />

It is instructive to compare this equation with Eq(27). Clearly, the thermodynamic<br />

forces there appear here again. If they vanish, we have equilibrium,<br />

and the entropy production R is zero. If they do not, the leading terms in R,<br />

being a positive definite function, must be quadratic in these forces. In this<br />

order, the dissipative currents, f D ,Π D ij, j D c , E D , H D , j D el, are proportional to<br />

the forces, with the coefficients obeying the Onsager symmetry relations.<br />

3 The Hydrodynamic Theory for Conductors<br />

If the electrical conductivity is large enough, such that the displacement current<br />

∂tD in<br />

10

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