Notes with answers - Summit Schools
Notes with answers - Summit Schools
Notes with answers - Summit Schools
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Your <strong>Notes</strong><br />
Homework<br />
y 2 y 1 5 m(x 2 x 1 ) Use point-slope form.<br />
y 2 1 5 22 [x 2 (21) ] Substitute 1 for y 1 , 22<br />
for m, and 21 for x 1 .<br />
y 2 1 5 22x 2 2 Distributive property<br />
y 5 22x 2 1 Slope-intercept form<br />
Example 4 Write Equations of Perpendicular Lines<br />
Write an equation of the line that passes through<br />
(23, 5) and is perpendicular to the line y 5 4x 2 1.<br />
solution<br />
The given line has a slope of 4 . The slope of any<br />
line perpendicular to this line will be the negative<br />
reciprocal of 4 , which is 2 1<br />
} .<br />
4<br />
Use point-slope form <strong>with</strong> (x1 , y1 ) 5 (23, 5) and<br />
m 5 2 1<br />
} to write the equation of the line.<br />
4<br />
y 2 y 1 5 m(x 2 x 1 ) Use point-slope form.<br />
y 2 5 5 2 1<br />
} [x 2 (23) ]<br />
4<br />
Substitute 5 for y1 , 2 1<br />
}<br />
4<br />
for m, and 23 for x1 .<br />
1<br />
y 2 5 5 2 } x 2<br />
4 3<br />
}<br />
4<br />
Distributive property<br />
1<br />
y 5 2 } x 1<br />
4 17<br />
}<br />
4<br />
Checkpoint Write an equation of the line.<br />
3. The line through<br />
(22, 3) parallel to<br />
y 5 4x 2 6<br />
y 5 4x 1 11<br />
Slope-intercept form<br />
4. The line through<br />
(22, 3) perpendicular<br />
to y 5 4x 2 6<br />
y 5 2 1<br />
} x 1<br />
4 5<br />
}<br />
2<br />
Copyright © McDougal Littell/Houghton Mifflin Company Lesson 2.5 • Algebra 2 C&S Notetaking Guide 39