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Untitled - Cdm.unimo.it

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Special Families of Polynomials 17<br />

a(x) = w(x) = e −x2<br />

, b(x) = 0, ∀x ∈ I ≡ R.<br />

Therefore, one easily gets the differential equation<br />

(1.7.1) H ′′<br />

n(x) − 2xH ′ n(x) + 2nHn(x) = 0, n ∈ N, x ∈ R.<br />

The normalizing cond<strong>it</strong>ion is<br />

(1.7.2) Hn(0) := (−1) n/2 n!<br />

(n/2)!<br />

(1.7.3) H ′ n(0) := (−1) (n−1)/2 (n + 1)!<br />

((n + 1)/2)!<br />

if n is even,<br />

if n is odd.<br />

The n th degree polynomial Hn is an even or odd function according to the par<strong>it</strong>y of n.<br />

As usual, we have the Rodrigues’ formula<br />

(1.7.4) Hn(x) = (−1) n dn x2<br />

e e−x2,<br />

n ∈ N, x ∈ R.<br />

dxn More explic<strong>it</strong>ly, we can wr<strong>it</strong>e<br />

(1.7.5) Hn(x) = n!<br />

[n/2] <br />

m=0<br />

(−1) m<br />

m!<br />

(2x) n−2m<br />

(n − 2m)!<br />

= 2 n x n − n(n − 1)2 n−2 x n−2 + n(n − 1)(n − 2)(n − 3)2 n−5 x n−4 − · · ·,<br />

The corresponding three-term recursion formula is<br />

(1.7.6) Hn(x) = 2xHn−1(x) − 2(n − 1)Hn−2(x), ∀n ≥ 2,<br />

where H0(x) = 1 and H1(x) = 2x.<br />

By differentiating (1.7.4) we also get<br />

(1.7.7) H ′ n(x) = 2xHn(x) − Hn+1(x), n ∈ N, x ∈ R.<br />

n ∈ N, x ∈ R.

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