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Theory of the Fireball

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with C = 14.<br />

and find<br />

On this basis we calculate <strong>the</strong> outer radius R <strong>of</strong> <strong>the</strong> warm layer<br />

2<br />

Using (6.17) we can <strong>the</strong>n calculate €$/Rae We give t'nis quantity in <strong>the</strong><br />

second last line <strong>of</strong> Table IX. In Yne last line, we nave given <strong>the</strong> mate-<br />

rial thickness <strong>of</strong> <strong>the</strong> warm layer, in relative units,<br />

L' = p2 - R2 - R1<br />

'a Ra<br />

It is seen from <strong>the</strong> table that R increases only sluwly; <strong>the</strong> main<br />

2<br />

change in R - R1 at later times is <strong>the</strong>refore due to <strong>the</strong> decrease <strong>of</strong> R<br />

2 I'<br />

The material thickness L' first decreases very slightly; this continues<br />

about as long as R increases, and is due to <strong>the</strong> fact that about <strong>the</strong> same<br />

1<br />

mass <strong>of</strong> warm material gets distributed over a larger area. Later on, L'<br />

increases while R decreases. Until x = 2.5 <strong>the</strong> chaage <strong>of</strong> L' remains<br />

1<br />

less than lo%, and after x = 2.5 <strong>the</strong> calculation is probably meaningless<br />

because <strong>the</strong> bomb debris comes into view. Therefore, we 'may assume L'<br />

constant, and thus <strong>the</strong> optical mass slbsorption coefficient (in cm 2 /gm)<br />

at <strong>the</strong> radiating layer will also be constant. In contrast with this<br />

79<br />

.. .<br />

. ..<br />

- .

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