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18<br />

Remark: Our assumptions (B1) and (B2) are not needed to prove (1). For (2) we<br />

just need (B1). Similarly, one can check that the rst seven paragraphs <strong>in</strong> B.13<br />

below do not require the assumptions while (B1) su ces for the rema<strong>in</strong>der <strong>of</strong> B.13<br />

and for B.14.<br />

B.13. In this and the next subsection we drop our assumption that (b + )=0<br />

and consider arbitrary 2 g .(Butwe shall soon assume to be <strong>nilpotent</strong>.) Let<br />

C( ) denote the category <strong>of</strong> all nite dimensional U (g){modules; as before we just<br />

write C when it is clear which we consider.<br />

Let g 2 G. We write Ad(g) for the adjo<strong>in</strong>taction<strong>of</strong>g on g and for the <strong>in</strong>duced<br />

action on U(g). If M is a g{module, then we write g M for M \twisted by g", i.e.,<br />

we take g M = M as a vector space and let any x 2 g (or <strong>in</strong> U(g)) act on g M as<br />

Ad(g ,1 )(x) doesonM. (See also the more general discussion at the beg<strong>in</strong>n<strong>in</strong>g <strong>of</strong><br />

[10], 1.13.)<br />

Clearly M 7! g M is an exact functor that takes simple modules to simple<br />

modules. If M is a G{module considered as a g{module via the derived action, then<br />

we have an isomorphism g M ,! M given by m 7! gm. IfM is a U (g){module,<br />

then g M is a Ug (g){module where g is the image <strong>of</strong> under the coadjo<strong>in</strong>t action<br />

<strong>of</strong> g given by (g )(x) = (Ad(g ,1 )x). The functor M 7! g M is an equivalence <strong>of</strong><br />

categories from C( )toC(g ). It takes simple modules to simple modules.<br />

Assume now that is <strong>nilpotent</strong>. This means that vanishes on a Borel<br />

subalgebra <strong>of</strong> g, or, equivalently, that there exists g 2 G with (g )(b + ) = 0, see<br />

[13].<br />

If M is a U (g){module, then each u 2 U(g) G acts on each g M as it does on<br />

M. Suppose for the moment that (g )(b + )=0;ifM is simple, then U(g) G acts<br />

on g M (and hence also on M) as on some Zg ( )with 2 X. Set C( ) equal to<br />

the full subcategory <strong>of</strong> C( ) consist<strong>in</strong>g <strong>of</strong> those N <strong>in</strong> C( ) such thatU(g) G acts<br />

on each composition factor <strong>of</strong> N as on Zg ( ). Then C( ) is the direct sum <strong>of</strong> all<br />

C( ) with <strong>in</strong> a suitable set <strong>of</strong> representatives.<br />

Note: If we have already (b + ) = 0, then the de nition <strong>of</strong> C( ) given above<br />

co<strong>in</strong>cides with that one that we get by apply<strong>in</strong>g B.1 directly, because each u 2<br />

U(g) G acts on Z ( ) and on Zg ( )by the same scalar (for each 2 X), cf.<br />

[10], 1.7. This observation imp<strong>lie</strong>s for arbitrary that the de nition <strong>of</strong> C( ) is<br />

<strong>in</strong>dependent <strong>of</strong> the choice <strong>of</strong> g with (g )(b + )=0.<br />

We have (foreach <strong>nilpotent</strong> ) projection functors pr : C( ) !C( ) and<br />

translation functors T : C( ) !C( ) de ned as <strong>in</strong> B.1/2.<br />

Let g 2 G. IfM is a U (g){module <strong>in</strong> C( ) ,then g M belongs to C(g ) . The<br />

functor M 7! g M restricts to an equivalence <strong>of</strong> categories from C( ) to C(g ) .<br />

We get for arbitrary M <strong>in</strong> C( ) that<br />

This imp<strong>lie</strong>s for M <strong>in</strong> C( ) that<br />

pr ( g M)= g (pr M): (1)<br />

g (T M) ' T ( g M): (2)

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