Survey 1979: Equational Logic - Department of Mathematics ...
Survey 1979: Equational Logic - Department of Mathematics ...
Survey 1979: Equational Logic - Department of Mathematics ...
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32 EQUATIONAL LOGIC<br />
conversely, every finite distributive lattice with unique atom can be represented in this<br />
way (H. P. Gumm, unpublished). T. Evans informed the author that there exists a<br />
finite commutative semigroup with A(Z) infinite.<br />
13.3. For F = group theory, A(F) is modular, but very complicated, and<br />
moreover can be given structure beyond the lattice-theoretic (see [330] and 17.9<br />
below). At and near the top A(F) contains<br />
ß<br />
ß<br />
x=y<br />
(x rn= I, xy=yx)<br />
xy = yx<br />
with m > 1, ordered by divisibility - the Abelian part. It turned out to be difficult to<br />
prove that IA(F)I = 2 0. This was established by Vaughan-Lee [434] who found 0<br />
irredundant equations (as in õ11), and independently, by Ol'shanski¾ [337] who<br />
found 0 "independent" subdirectly irreducible groups. (Cf. 9.18 above.) The variety<br />
<strong>of</strong> 3-nilpotent groups has been completely described - see J6nsson [220] or<br />
Remeslennikov [ 376].<br />
13.4. For Z = semigroup theory, many results are known; consult the survey by<br />
Evans [124] for more detailed information. Biryukov (1965) and later Evans [120]<br />
first proved that [A(;)I = 2 0 (also see [198] for a nice infinite irredundant set <strong>of</strong><br />
semigroup laws). Dean and Evans [106] proved that x(yz)= (xy)z is finitely<br />
meet-irreducible in A, i.e., that A(Z) has a f'mitely meet-irreducible least element.<br />
Burris and Nelson [79] (and later Jeek [211 ] ) proved that A(Z) contains a copy <strong>of</strong><br />
Iloo, the lattice <strong>of</strong> partitions on an infinite set, and hence obeys no special lattice laws.<br />
The fact that A(Z) is non-modular can be seen from this sublattice - due to Jezek -<br />
isomorphic to the smallest non-modular lattice, NS:<br />
xy = zw<br />
xy = xz ß I<br />
xyz = xzy<br />
xy = yx<br />
/ xyz = xzy = zxy