04.08.2013 Views

Statistical Mechanics - Physics at Oregon State University

Statistical Mechanics - Physics at Oregon State University

Statistical Mechanics - Physics at Oregon State University

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

4.5. FERMI GAS. 83<br />

N({n1, n2, . . .}) = <br />

o<br />

no<br />

(4.62)<br />

The energy is in general harder to find. But we now make again the assumption<br />

th<strong>at</strong> the particles are independent. This allows us to write for the energy:<br />

E({n1, n2, . . .}) = <br />

o<br />

noɛo<br />

(4.63)<br />

where the many body energy E({n1, n2, . . .}) simply is equal to the sum of<br />

the single particle energies ɛo corresponding to occupied st<strong>at</strong>es. The grand<br />

partition function can now be written in the form<br />

Z(T, µ, V ) =<br />

Z(T, µ, V ) = <br />

Z(T, µ, V ) =<br />

1<br />

n1=0<br />

1<br />

n1=0 n2=0<br />

{n1,n2,...}<br />

1<br />

· · ·<br />

e 1<br />

k B T (µ−ɛ1)n1<br />

e 1<br />

k B T o (µ−ɛo)no<br />

1<br />

· · · <br />

ni=0<br />

1<br />

n2=0<br />

o<br />

e 1<br />

k B T (µ−ɛo)no<br />

e 1<br />

k B T (µ−ɛ2)n2<br />

<br />

(4.64)<br />

(4.65)<br />

· · · (4.66)<br />

Since the summ<strong>at</strong>ion variables are just dummy variables, this is equal to<br />

Z(T, µ, V ) = <br />

<br />

1<br />

e 1<br />

kB T (µ−ɛo)n<br />

<br />

= <br />

Zo(T, µ, V ) (4.67)<br />

orb<br />

n=0<br />

where we have defined the orbital grand partition function Zo as before by:<br />

Zo =<br />

1<br />

n=0<br />

orb<br />

µ−ɛo n k e B T (4.68)<br />

The grand partition function for a subsystem with a single orbital is therefore<br />

given by Zo = 1 + e µ−ɛo<br />

kB T .<br />

Note th<strong>at</strong> there is no factor N! in front of the product in (4.67), unlike we<br />

had before for the ideal gas partition function. The essential difference is th<strong>at</strong> in<br />

the formula above the product is over orbitals and these are distinguishable.<br />

Previously we had a product over particles and those are identical.<br />

Grand Energy.<br />

The grand energy follows from<br />

Ω(T, µ, V ) = −kBT log(Zo) = −kBT <br />

log(Zo(T, µ, V )) (4.69)<br />

orb

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!