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Statistical Mechanics - Physics at Oregon State University

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52 CHAPTER 3. VARIABLE NUMBER OF PARTICLES<br />

, this combin<strong>at</strong>ion<br />

is often abbrevi<strong>at</strong>ed by defining β = 1<br />

kBT . Using β simplifies many superscripts<br />

to simple products in stead of r<strong>at</strong>ios. Of course, this β should not be confused<br />

with the critical exponent describing the disappearance of the order parameter<br />

Since the temper<strong>at</strong>ure in many formulas appears as 1<br />

kBT<br />

near the critical temper<strong>at</strong>ure! Also, the chemical potential often occurs in the<br />

combin<strong>at</strong>ion e µ<br />

k B T . This exponential is called the absolute activity (often de-<br />

noted by λ = e µ<br />

k B T ) or the fugacity (often denoted by z = e µ<br />

k B T ). The not<strong>at</strong>ion<br />

in the l<strong>at</strong>ter case is not the same in all books, unlike the conventional abbrevi<strong>at</strong>ion<br />

β, which is used almost uniformly. In terms of β, one finds immedi<strong>at</strong>ely<br />

th<strong>at</strong><br />

<br />

∂Z<br />

∂β µ,V<br />

since U =< ɛs >. This gives<br />

= <br />

(µns − ɛs)e β(µns−ɛs)<br />

= Z(µN − U) (3.41)<br />

<br />

∂ log(Z)<br />

U = µN −<br />

∂β<br />

s<br />

µ,V<br />

=<br />

µ<br />

β<br />

∂ ∂<br />

−<br />

∂µ ∂β<br />

<br />

log(Z) (3.42)<br />

The recipe for calcul<strong>at</strong>ions <strong>at</strong> specified values of µ, T, and V is now clear. Calcul<strong>at</strong>e<br />

the grand partition function Z(µ, T, V ) and then the number of particles,<br />

internal energy, etc. The construct the grand potential. There is a better and<br />

direct way, however, as one might expect.<br />

Since the grand potential is the correct measure of energy available to do<br />

work <strong>at</strong> constant V, µ and T, it should be rel<strong>at</strong>ed to the grand partition function.<br />

The correct formula can be guessed directly when we remember th<strong>at</strong>:<br />

<br />

∂Ω<br />

∂µ T,V<br />

= −N (3.43)<br />

After comparing this partial deriv<strong>at</strong>ive with the expression for N in 3.40 we<br />

conclude th<strong>at</strong>:<br />

Ω = −kBT log(Z) + f(T, V ) (3.44)<br />

where the function f(T,V) is still unknown. We will show th<strong>at</strong> it is zero. This<br />

last formula can be inverted to give an expression for log(Z). Inserting this<br />

expression in the formula for U leads to<br />

U =<br />

µ<br />

β<br />

∂ ∂<br />

−<br />

∂µ ∂β<br />

U = Ω − f − µ<br />

<br />

µ<br />

log(Z) =<br />

β<br />

∂ ∂<br />

−<br />

∂µ ∂β<br />

<br />

(β(f − Ω)) (3.45)<br />

<br />

U = Ω − f + µ ∂<br />

<br />

∂<br />

− β (f − Ω) (3.46)<br />

∂µ ∂β<br />

<br />

∂Ω<br />

− β<br />

∂µ β,V<br />

<br />

∂f<br />

+ β<br />

∂β µ,V<br />

<br />

∂Ω<br />

∂β µ,V<br />

(3.47)

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