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Statistical Mechanics - Physics at Oregon State University

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234 APPENDIX A. SOLUTIONS TO SELECTED PROBLEMS.<br />

the probability th<strong>at</strong> a student who bought a copy of Jackson also bought a copy<br />

of Liboff is four out of eight, or 50%. Similarly, the probability th<strong>at</strong> a student<br />

who bought a copy of Liboff also bought a copy of Jackson is four out of six, or<br />

66.67%.<br />

Problem 8.<br />

For an ideal gas we have U = 3<br />

2 NkBT , where N is the number of particles. Use<br />

the rel<strong>at</strong>ion between the entropy S(U, N) and the multiplicity function g(U, N)<br />

to determine how g(U, N) depends on U.<br />

From<br />

we find<br />

which gives<br />

and with<br />

we get<br />

1<br />

T =<br />

<br />

∂S<br />

∂U N<br />

<br />

∂S<br />

=<br />

∂U N<br />

3<br />

2 NkB<br />

1<br />

U<br />

S = 3<br />

2 NkB log(U) + C(N)<br />

g(U, N) = e S<br />

k B<br />

g(U, N) = C ′ (N)U 3<br />

2 N<br />

Does this make sense? The kinetic energy of one particle is 2 k 2<br />

total kinetic energy is given by:<br />

Ek = 2<br />

2m<br />

N<br />

z<br />

i=1 j=x<br />

k 2 ij<br />

2m<br />

and hence the<br />

A surface of constant energy U is a hypersphere in 3N dimensions, with radius<br />

R given by U = 2R 2<br />

. The number of st<strong>at</strong>es with a given energy is proportional<br />

2m<br />

to the surface area of th<strong>at</strong> sphere, which is proportional to R3N−1 . For large N<br />

we ignore the -1 and hence the area is proportional to U 3<br />

2 N .<br />

Problem 9.

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