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Statistical Mechanics - Physics at Oregon State University

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230 APPENDIX A. SOLUTIONS TO SELECTED PROBLEMS.<br />

Therefore in the limit N → ∞ we have<br />

(I) lim<br />

N→∞ ɛ1 = ∞<br />

(II) lim<br />

N→∞ ɛ1 = 1<br />

(III) lim<br />

N→∞ ɛ1 = 1 − 1<br />

√ 2π<br />

(IV) lim<br />

N→∞ ɛ1 = 0<br />

and only in the last case will the rel<strong>at</strong>ive error become small. For a 1% error<br />

1 1 + we need e 12 N −R(N) = 0.99 or approxim<strong>at</strong>ely (using ex ≈ 1 + x ) we need<br />

1 1 = 0.01 which will be true if N > 8.<br />

12 N<br />

Problem 5.<br />

This is a problem which shows how probabilities change when you add inform<strong>at</strong>ion.<br />

This one is called the principle of restricted choice. Bridge players should<br />

be familiar with it!<br />

Label the door you chose with A, the others with B and C. When you make<br />

your first choice, your chance of finding the car is of course 1<br />

3 . Hence there are<br />

three equally probable scenarios.<br />

(1) A = car, B = 0, C = 0 Probability 1<br />

3<br />

(2) A = 0, B = car, C = 0 Probability 1<br />

3<br />

(3) A = 0, B = 0, C = car Probability 1<br />

3<br />

Next, the game show host points <strong>at</strong> a door. Now there are six scenarios:<br />

(1a) A = car, B = 0, C = 0 Host chooses B Probability 1<br />

6<br />

(1b) A = car, B = 0, C = 0 Host chooses C Probability 1<br />

6<br />

(2a) A = 0, B = car, C = 0 Host chooses B Probability 1<br />

6<br />

(2b) A = 0, B = car, C = 0 Host chooses C Probability 1<br />

6<br />

(3a) A = 0, B = 0, C = car Host chooses B Probability 1<br />

6<br />

(3b) A = 0, B = 0, C = car Host chooses C Probability 1<br />

6<br />

which are all equally probable. But now we introduce the fact th<strong>at</strong> the host<br />

cannot open the door behind which the car is hidden, which elimin<strong>at</strong>es sequences<br />

2a and 3b. In scenario 2 where the car is behind door B, the host has to choose<br />

door C! His choice is restricted! Hence the four possible sequences of events<br />

are:

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