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Statistical Mechanics - Physics at Oregon State University

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8.6. BETHE APPROXIMATION. 187<br />

which leads to<br />

In the limit q ≫ 1 we have log( q<br />

e βJ (2 − q) = e −βJ (−q) (8.135)<br />

q<br />

2βJ = log( ) (8.136)<br />

q − 2<br />

kBTc = J<br />

q−2<br />

2<br />

log( q<br />

q−2 )<br />

) ≈ log(1 + 2<br />

q<br />

(8.137)<br />

) ≈ 2<br />

q and hence kBTc ≈ qJ<br />

like in mean field. The mean field results is best when the number of neighbors<br />

is large, which is certainly true in high dimensional systems. As we saw in<br />

Thermodynamics, mean field theory is exact for high dimensions.<br />

The final, important, question is the following. When there is a solution<br />

with a non-zero value of h ′ , does this solution have the lowest energy? Now we<br />

need to address the question of finding f(h ′ ). The energy of the cluster is given<br />

by<br />

〈Ec〉 = −Jq〈σ0σj〉 − h(q + 1)m − h ′ m + f(h ′ ) (8.138)<br />

and the correl<strong>at</strong>ion function 〈σ0σj〉 follows from<br />

〈σ0σj〉 = 1<br />

<br />

Zc<br />

{σ0,···,σq}<br />

Following the calcul<strong>at</strong>ion for Sj we find th<strong>at</strong><br />

σ0σje −βEc(σ0,···,σq) = S0j<br />

S0j = e βh [2 cosh(β(J + h + h ′ ))] q−1 [2 sinh(β(J + h + h ′ ))]−<br />

Zc<br />

(8.139)<br />

e −βh [2 cosh(β(−J + h + h ′ ))] q−1 [2 sinh(β(−J + h + h ′ ))] (8.140)<br />

where the only difference with Sj is the minus sign in front of the second term.<br />

So here we see another advantage of the Bethe approxim<strong>at</strong>ion, we do have an<br />

estim<strong>at</strong>e for the correl<strong>at</strong>ion function.<br />

The value of f(h ′ ) can be determined by considering a situ<strong>at</strong>ion where all<br />

spins are equal to m and are uncorrel<strong>at</strong>ed, in which case we know the energy.<br />

This is too tedious, though. But if we think in terms of Landau theory and<br />

consider h ′ to be a parameter in the energy expression, we can deduce th<strong>at</strong> with<br />

three solutions for h ′ the order has to be minimum-maximum-minimum, and<br />

hence the h ′ = 0 solution, which is always the middle one, has to be a maximum.

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