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Statistical Mechanics - Physics at Oregon State University

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166 CHAPTER 8. MEAN FIELD THEORY: CRITICAL TEMPERATURE.<br />

−4<br />

−2<br />

m<br />

2.0<br />

1.6<br />

1.2<br />

0.8<br />

0.4<br />

0.0<br />

0<br />

−0.4<br />

−0.8<br />

y<br />

−1.2<br />

−1.6<br />

−2.0<br />

Figure 8.1: β ∗ = 1<br />

2 , h∗ = 2<br />

and right hand sides of this equ<strong>at</strong>ion, it is easy to see th<strong>at</strong> one either has one<br />

or three solutions. In figure 8.2 we show the results for β ∗ = 2 and h ∗ = 0.1,<br />

and now we see three solutions.<br />

−4<br />

2.0<br />

1.6<br />

1.2<br />

0.8<br />

0.4<br />

0.0<br />

−2 0<br />

−0.4<br />

m<br />

−0.8<br />

y<br />

−1.2<br />

−1.6<br />

−2.0<br />

Figure 8.2: β ∗ = 2 , h ∗ = 0.1<br />

When there is only one solution, we have found the function m(β ∗ , h ∗ ) and<br />

are able to calcul<strong>at</strong>e the internal energy and the partition function from. In case<br />

there are three solutions, we need to compare the magnetic Gibbs energy for<br />

the three solutions and find the lowest energy solution. Note th<strong>at</strong> when |h ∗ | > 1<br />

there is only one solution, the model system is always magnetized. In a strong<br />

magnetic field the spins are always aligned in a ferromagnetic manner.<br />

Spontaneous magnetic order.<br />

2<br />

2<br />

4<br />

4

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