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Statistical Mechanics - Physics at Oregon State University

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6.3. MAXIMUM ENTROPY PRINCIPLE. 127<br />

and <strong>at</strong> an extremum this should be zero for all vari<strong>at</strong>ions ∆ρ, which gives us<br />

the condition mentioned before. The changes in the quantity X are rel<strong>at</strong>ed to<br />

changes in the oper<strong>at</strong>or ρ, and ultim<strong>at</strong>ely to changes in the density m<strong>at</strong>rix Rij.<br />

Suppose we only change one m<strong>at</strong>rix element, hence only ∆Rmn is non-zero for<br />

a specific value of m and n. This gives:<br />

∆X = 〈n| δX<br />

δρ<br />

but we also have in terms of simple partial deriv<strong>at</strong>ives<br />

which leads to<br />

<br />

∂X<br />

∆X =<br />

〈n| δX<br />

δρ<br />

∂Rmn<br />

|m〉 〈m| ∆ρ |n〉 (6.38)<br />

<br />

〈m| ∆ρ |n〉 (6.39)<br />

<br />

∂X<br />

|m〉 =<br />

∂Rmn<br />

<br />

(6.40)<br />

where we note th<strong>at</strong> the order in which n and m appear is interchanged left and<br />

right.<br />

In our particular case we have<br />

and hence<br />

∂X<br />

∂Rnm<br />

<br />

X = −kB 〈i| ρ |j〉 〈j| log(ρ) |i〉 + λkB( <br />

〈i| ρ |i〉 − 1) (6.41)<br />

ij<br />

<br />

<br />

<br />

∂ 〈j| log(ρ) |i〉<br />

= −kB 〈m| log(ρ) |n〉 + λkBδnm − kB 〈i| ρ |j〉<br />

ij<br />

i<br />

∂Rnm<br />

(6.42)<br />

It is the last term th<strong>at</strong> causes problems in the calcul<strong>at</strong>ions. This task can<br />

be reformul<strong>at</strong>ed as follows. Suppose the oper<strong>at</strong>or ρ depends on some complex<br />

variable x. Calcul<strong>at</strong>e Tr ρ . This can be done by using the definition of a<br />

logarithm. We have<br />

∂ρ<br />

∂x<br />

log(ρ) = τ ⇐ e τ = ρ (6.43)<br />

We can rel<strong>at</strong>e deriv<strong>at</strong>ives of ρ to deriv<strong>at</strong>ives of τ. In general we have<br />

and since the series converges uniformly, this gives<br />

∂<br />

∂x eτ(x) = ∂ 1<br />

∂x n!<br />

n<br />

τ n (x) (6.44)<br />

∂<br />

∂x eτ(x) = <br />

n<br />

1 ∂<br />

n! ∂x τ n (x) (6.45)

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