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Statistical Mechanics - Physics at Oregon State University

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5.3. BOSE-EINSTEIN CONDENSATION. 113<br />

limit, however, the contribution of these terms will go to zero! For finite volumes<br />

these terms can give some contributions, leading to rounding off of sharp<br />

curves near the phase transition.<br />

By splitting the range in these two parts, we can show th<strong>at</strong> on each part the<br />

convergence is uniform. Hence we have<br />

V > Vɛ ⇒<br />

<br />

<br />

<br />

<br />

<br />

error(T, µ, V )<br />

Ω<br />

V<br />

<br />

<br />

<br />

< ɛ (5.131)<br />

<br />

with Vɛ independent of T and µ. Therefore, in all cases the error term is small<br />

compared with the value of Ω, assuming a large volume. A value of 1 m 3 for<br />

the volume certainly s<strong>at</strong>isfies the criteria of being large. Hence for all practical<br />

applic<strong>at</strong>ions we can ignore the error term. Keep in mind, though, th<strong>at</strong> if you<br />

do experiments on a small container of helium gas with only 1000 <strong>at</strong>oms <strong>at</strong><br />

normal pressure and temper<strong>at</strong>ure, you will find devi<strong>at</strong>ions from this formula.<br />

To analyze such experiments you really have to calcul<strong>at</strong>e the sum of the series.<br />

5.3 Bose-Einstein condens<strong>at</strong>ion.<br />

The expression for the density N<br />

V is<br />

n =<br />

2S + 1<br />

fBE(ɛ111) +<br />

V<br />

2S + 1<br />

λ 3 T<br />

g 3 (λ) (5.132)<br />

2<br />

We now take the thermodynamic limit of this expression. For large values of<br />

the volume we may replace ɛ111 by zero. This gives us<br />

n =<br />

2S + 1<br />

V<br />

It is easy to show th<strong>at</strong> g 3<br />

2<br />

the deriv<strong>at</strong>ive is proportional to g 1<br />

2<br />

λ<br />

1 − λ + (2S + 1)nQ(T )g 3<br />

2<br />

(λ) (5.133)<br />

(λ) is a monotonically increasing function of λ, since<br />

which is always positive for 0 λ 1. As<br />

a result, the particle density is an monotonically increasing function of λ. We<br />

define G = g 3 (1) = 2.612 · · ·.<br />

2<br />

It is possible to distinguish two regimes. If<br />

n<br />

< (2S + 1)G (5.134)<br />

nQ(T )<br />

it is possible to find a value of λ < 1 s<strong>at</strong>isfying n = (2S +1)nQ(T )g 3 (λ) . In the<br />

2<br />

expression for n we therefore are able to take the thermodynamic limit V → ∞,<br />

and the first term in equ<strong>at</strong>ion (5.133) is zero. This means th<strong>at</strong> in the density<br />

regime n < nQ(T ) the ground st<strong>at</strong>e orbital does not play an important role,<br />

and the gas behaves like a normal gas.<br />

On the other hand, if<br />

n<br />

> (2S + 1)G (5.135)<br />

nQ(T )

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