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Statistical Mechanics - Physics at Oregon State University

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5.2. BOSONS IN A BOX. 109<br />

0 < T Tm. Also, in case T → ∞ the sum approaches the integral again, and<br />

there are no convergence problems for the series.<br />

The next question is if the series always converges to the integral ˜ Ω. The<br />

integrant in k-space is again steepest for values of k near zero, and we expect<br />

problems in the first few terms of the series.<br />

Simple example.<br />

Consider the following series:<br />

Define xn = n<br />

L<br />

F (α) = 1<br />

√ L<br />

1<br />

and ∆x = L . We have:<br />

F (α) =<br />

∞<br />

n=0<br />

∞<br />

n=0<br />

n − e L<br />

√<br />

n + αL<br />

and in the limit L → ∞ this approaches the integral:<br />

<br />

F (α) =<br />

(5.109)<br />

e−xn √ ∆x (5.110)<br />

xn + α<br />

dx e−x<br />

√ x + α<br />

(5.111)<br />

If we now take the limit α → 0 we get a well defined result. But we did take<br />

the thermodynamic limit L → ∞ first, and th<strong>at</strong> is not correct. If we take the<br />

1<br />

limit α → 0 in the series the very first term, which is equal to √αL blows up!<br />

We can find a way out. Write the series in the following form:<br />

F (α) = 1<br />

L √ 1<br />

+ √<br />

α L<br />

∞<br />

n=1<br />

n − e L<br />

√<br />

n + αL<br />

(5.112)<br />

Now we can replace the series by an integral for all values of α, since the divergent<br />

term is isol<strong>at</strong>ed outside the series. Hence we have<br />

L ≫ 1 ⇒ F (α) ≈ 1<br />

L √ α +<br />

<br />

dx e−x<br />

√ x + α<br />

(5.113)<br />

where the first term can be ignored only if L ≫ 1<br />

α ! Hence in the limit α → 0<br />

this first term can never be ignored.<br />

The low temper<strong>at</strong>ure limit for bosons.<br />

We now return to the question of the magnitude of the error term <strong>at</strong> low<br />

temper<strong>at</strong>ure. The easiest way to discuss the n<strong>at</strong>ure of the low temper<strong>at</strong>ure limit<br />

is to consider the expansion for N in terms of orbitals:

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