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Statistical Mechanics - Physics at Oregon State University

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92 CHAPTER 5. FERMIONS AND BOSONS<br />

tnx,ny,nz e µm<br />

kB T − 2 π 2<br />

2ML2 mk (n2<br />

B Tm x +n2y<br />

+n2z<br />

)<br />

(5.12)<br />

which means th<strong>at</strong> the series for arbitrary values of T , µ, and L converges faster<br />

than for the maximal values. Hence we can use the maximal values of T , µ ,<br />

and L to describe the convergence of the series in general, and hence the series<br />

converges uniformly on 0 T Tm , −∞ µ µm, and 0 L Lm.<br />

Next we consider a domain for (T, µ, L) space with T ′ m T , L ′ m L , and<br />

−∞ µ µm. The argument of the exponent in (5.7) is<br />

ɛ(nx, ny, nz) <br />

=<br />

kBT<br />

2π2 2MkBT L2 (n2x + n 2 y + n 2 z) = x 2 nx + y2 ny + z2 nz (5.13)<br />

<br />

2π2 with xnx = nx 2MkBT L2 and similar for the y and z components. The size of<br />

the steps therefore approaches zero when the temper<strong>at</strong>ure becomes very large or<br />

when L becomes very large. Therefore, if we can replace the sum by an integral<br />

with a certain error <strong>at</strong> a certain temper<strong>at</strong>ure or length, the error will be smaller<br />

<strong>at</strong> all higher temper<strong>at</strong>ures and lengths.<br />

We now make the following observ<strong>at</strong>ion. Suppose we choose a tolerance<br />

ɛ. Because of the uniform convergence of the series we can find a value Nɛ<br />

independent of T , µ , and L ( but with 0 T Tm , −∞ µ µm, and<br />

0 L Lm ) such th<strong>at</strong>:<br />

<br />

<br />

<br />

<br />

−(2S<br />

+ 1)kBT<br />

<br />

N<br />

N<br />

nx=1 ny=1 nz=1<br />

<br />

N<br />

<br />

<br />

log(Znx,ny,nz (T, µ, V )) − S(T, µ, V ) <br />

< ɛ (5.14)<br />

<br />

for all values of N with N > Nɛ. Next, use I(T, µ, V ) for the result of the<br />

integral. We can find values of T ′ m and L ′ m in such a manner th<strong>at</strong><br />

<br />

<br />

<br />

<br />

−(2S<br />

+ 1)kBT<br />

<br />

∞<br />

∞<br />

nx=1 ny=1 nz=1<br />

<br />

∞<br />

<br />

<br />

log(Znx,ny,nz(T, µ, V )) − I(T, µ, V ) <br />

< ɛ (5.15)<br />

<br />

for all values of the temper<strong>at</strong>ure with T T ′ m and L L ′ m. The last equ<strong>at</strong>ion<br />

implies th<strong>at</strong> the series converges, which we already knew, but does not require<br />

uniform convergence.<br />

We are now able to make the following st<strong>at</strong>ement. Consider a domain −∞ <br />

µ µm , T ′ m T Tm , and V ′ m V Vm. On this domain the series for<br />

the grand partition function converges uniformly and the sum is close to the<br />

value of the integral. We will choose both Tm and Vm very large. We will also<br />

choose T ′ m very small. Since temper<strong>at</strong>ure and volume are multiplied together<br />

(via the term T L 2 ), this means th<strong>at</strong> we need to consider very large values of<br />

the volume only. Hence for any value of µ and T in any interval −∞ µ µm,

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