STUDIES OF ENERGY RECOVERY LINACS AT ... - CASA

STUDIES OF ENERGY RECOVERY LINACS AT ... - CASA STUDIES OF ENERGY RECOVERY LINACS AT ... - CASA

casa.jlab.org
from casa.jlab.org More from this publisher
04.08.2013 Views

187 Ez(z) = A sin kz + B cos(kz) (A.16) The boundary conditions require that the tangential components of E must vanish at z = 0 and z = d. These conditions are satisfied when Ez(ρ, φ, z) = Eo cos pπz ψ(ρ, φ) (p = 0, 1, 2, ...) (A.17) d where ψ(ρ, φ) describes the azimuthal dependence of the fields. It follows from Eq. (A.14) and Eq. (A.15) that the transverse components of the electric and magnetic field are given by Et = − pπ sin dγ2 Ht = iɛoω cos γ2 pπz d pπz d ∇tψ(ρ, φ) (A.18) [ˆz × ∇tψ(ρ, φ)] (A.19) The problem can be simplified further by taking advantage of the azimuthal sym- metry in the problem and writing ψ(ρ, φ) = ψ(ρ)e ±imφ where m is an integer. Substituting Eq. (A.20) into Eq. (A.10) yields (A.20) d2ψ 1 dψ + dρ2 ρ dρ + γ 2 − m2 ρ2 ψ = 0 (A.21) which is Bessel’s equation and whose solutions are Bessel functions of order m and denoted as Jm(γρ). One of the solutions diverges for ρ = 0 which is physically unacceptable and so this solution is disregarded. as From Eq. (A.17), Eq. (A.20) and the solution to Eq. (A.21), Ez can be written

Ez(ρ, φ) = ψ(ρ, φ) = E0Jm(γρ)e imφ 188 (A.22) Applying the condition that at Ez(ρ = R) = 0 requires Jm(γR) = 0. Define xmn ≡ γmnR as the n th root of the Bessel function of order m. Finally, the two components of primary interest, Ez and Hφ for TMmn0 modes, are given by Ez(ρ, φ, z) = E0Jm Hφ(ρ, φ, z) = = iE0 xmnρ iɛoωmn0 cos(mφ) R ∂Ez ∂ρ (A.23) (A.24) cos(mφ) (A.25) γ2 mn ɛ0ωmn0R J xmn ′ xmnρ m R where the eigenfrequencies are determined by combining Eq. (A.11) and the defini- tion of xmn to give ωmn0 = 1 xmn √ µoɛo R The two important properties of TM110 modes in particular, are that 1. Ez ∝ ρ 2. Hφ is nonzero for ρ = 0 (A.26) The first property is due to the fact that J1 is linear for small values of ρ which means that Ez grows linearly with off-axis displacement. The second property implies that a beam bunch traveling on-axis can still be deflected by the magnetic field since J ′ 1(0) = 0.

Ez(ρ, φ) = ψ(ρ, φ) = E0Jm(γρ)e imφ<br />

188<br />

(A.22)<br />

Applying the condition that at Ez(ρ = R) = 0 requires Jm(γR) = 0. Define<br />

xmn ≡ γmnR as the n th root of the Bessel function of order m. Finally, the two<br />

components of primary interest, Ez and Hφ for TMmn0 modes, are given by<br />

Ez(ρ, φ, z) = E0Jm<br />

Hφ(ρ, φ, z) =<br />

= iE0<br />

xmnρ<br />

iɛoωmn0<br />

<br />

cos(mφ)<br />

R<br />

∂Ez<br />

∂ρ<br />

<br />

(A.23)<br />

(A.24)<br />

cos(mφ) (A.25)<br />

γ2 mn <br />

ɛ0ωmn0R<br />

J<br />

xmn<br />

′ <br />

xmnρ<br />

m<br />

R<br />

where the eigenfrequencies are determined by combining Eq. (A.11) and the defini-<br />

tion of xmn to give<br />

ωmn0 = 1 xmn<br />

√<br />

µoɛo R<br />

The two important properties of TM110 modes in particular, are that<br />

1. Ez ∝ ρ<br />

2. Hφ is nonzero for ρ = 0<br />

(A.26)<br />

The first property is due to the fact that J1 is linear for small values of ρ which means<br />

that Ez grows linearly with off-axis displacement. The second property implies that<br />

a beam bunch traveling on-axis can still be deflected by the magnetic field since<br />

J ′ 1(0) = 0.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!