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STUDIES OF ENERGY RECOVERY LINACS AT ... - CASA

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187<br />

Ez(z) = A sin kz + B cos(kz) (A.16)<br />

The boundary conditions require that the tangential components of E must vanish<br />

at z = 0 and z = d. These conditions are satisfied when<br />

Ez(ρ, φ, z) = Eo cos<br />

<br />

pπz<br />

<br />

ψ(ρ, φ) (p = 0, 1, 2, ...) (A.17)<br />

d<br />

where ψ(ρ, φ) describes the azimuthal dependence of the fields. It follows from Eq.<br />

(A.14) and Eq. (A.15) that the transverse components of the electric and magnetic<br />

field are given by<br />

Et = − pπ<br />

sin<br />

dγ2 Ht = iɛoω<br />

cos<br />

γ2 pπz<br />

d<br />

pπz<br />

d<br />

<br />

∇tψ(ρ, φ) (A.18)<br />

<br />

[ˆz × ∇tψ(ρ, φ)] (A.19)<br />

The problem can be simplified further by taking advantage of the azimuthal sym-<br />

metry in the problem and writing<br />

ψ(ρ, φ) = ψ(ρ)e ±imφ<br />

where m is an integer. Substituting Eq. (A.20) into Eq. (A.10) yields<br />

(A.20)<br />

d2ψ 1 dψ<br />

+<br />

dρ2 ρ dρ +<br />

<br />

γ 2 − m2<br />

ρ2 <br />

ψ = 0 (A.21)<br />

which is Bessel’s equation and whose solutions are Bessel functions of order m and<br />

denoted as Jm(γρ). One of the solutions diverges for ρ = 0 which is physically<br />

unacceptable and so this solution is disregarded.<br />

as<br />

From Eq. (A.17), Eq. (A.20) and the solution to Eq. (A.21), Ez can be written

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