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STUDIES OF ENERGY RECOVERY LINACS AT ... - CASA

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consider an HOM polarized at an arbitrary angle, α, with respect to the x-axis.<br />

The unit vector describing the HOM polarization is êHOM = (sin α, cos α) and the<br />

bunch displacement is given by<br />

r = r · êHOM = x cos α + y sin α (4.8)<br />

On the first pass through the cavity the bunch deposits an energy to the HOM<br />

given by inserting Eq. (4.8) into Eq. (4.7)<br />

85<br />

∆U1 = −q Va<br />

a (x1 cos α + y1 sin α) cos φ (4.9)<br />

The bunch’s contribution to the energy of the HOM on the second pass through the<br />

cavity can be written in a similar manner<br />

∆U2 = −q Va<br />

a (x2 cos α + y2 sin α) cos(φ + ωTr) (4.10)<br />

where x2 and y2 denote the second pass displacements, ω is the HOM angular<br />

frequency and Tr is the recirculation time of the machine. The additional phase<br />

term includes the effects of the beam recirculation. Note that this derivation assumes<br />

that the variation of the HOM voltage on the time scale of the recirculation time is<br />

negligible.<br />

The horizontal displacement on the second pass can be rewritten in terms of<br />

the first pass coordinates and the HOM imparted angular kick as<br />

x2 = M11x1 + M12x ′<br />

1 + M13y1 + M14y ′<br />

1 − qVa<br />

and likewise for the vertical plane<br />

y2 = M31x1 + M32x ′<br />

1 + M33y1 + M34y ′<br />

1 − qVa<br />

(M12 cos α + M14 sin α) sin φ (4.11)<br />

ωapb<br />

(M32 cos α + M34 sin α) sin φ (4.12)<br />

ωapb

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