Schmucker-Weidelt Lecture Notes, Aarhus, 1975 - MTNet

Then the discontinuity between cell (i, j) and 1 j contribu-tes
to the integral
It has been used that H and p E are continuous across interfaces.
an
The contributioll frcm the i + i j + I interface is
The integral equation is decomposed into a set of linear equations
for the Ha-values at each cell. The electric fLeld is then obtained
by differentiating (3.56) with respect to the coordinates of E ~ .
-
It remains to calculate Gn. At z = 0 G has to sat.i.sfy the boundary
n
condition of Ha, i.e. Ha = 0, : Gn = 0. The boundary condi.tions at
interfaces are G and(l/cr)a~~/az continuous. Assume aqain L uniform
n
layers with conductivities ol, 02, . . . , and upper edges at
OL
hl = 0, h2, ...I hLI h -
~4.1
- -'.
Let the field in the m-th layer be
where