Schmucker-Weidelt Lecture Notes, Aarhus, 1975 - MTNet

There are several ways to determine C:
a) From the ratio bctween two orthogonal components - of tj>h
- horizonha1 electric and magnetj.~ fisld -
*
Vectorial multiplication of (2.47a) with z and use of (2.43) yields
* A A
E = -iwu C z x H
.- 0 - -
A
or with any horizontal unit vector - e
A A
- -
e - E
C = .. A*- (2.48)
iwyo'(~xg) *' - K .
A * A A
In particular - e = - x and - e L- yields
b) Prom the ratio of vertical and horizontal - l~agne'iic fi~ld
components
(2.47a) yields immediately
c) Froln the ratiq of internal to external -- part of. a lnagnetj-c
horizontal component
i
In z - < 0 f reads,
(2.49a
- -KZ -,- f+
. , f = f e (2.51
0 0
A
A A
Let Xxe and H be the source part and internal part of Hx. Then
xi
from (2.47a) and (2.51)
Defining
A *
s (K, w) = Hxi (5,'" //IS'xe (5, (6)