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CAHSEE on Target<br />

UC Davis, School and University Partnerships<br />

CAHSEE on Target<br />

Mathematics Curriculum<br />

Published by<br />

The University of California, Davis,<br />

School/University Partnerships Program<br />

2006<br />

Director<br />

Sarah R. Martinez, School/University Partnerships, UC Davis<br />

Developed and Written by<br />

Syma Solovitch, School/University Partnerships, UC Davis<br />

Editor<br />

Nadia Samii, UC Davis Nutrition Graduate<br />

Reviewers<br />

Faith Paul, School/University Partnerships, UC Davis<br />

Linda Whent, School/University Partnerships, UC Davis<br />

The CAHSEE on Target curriculum was made possible by<br />

funding and support from the California Academic Partnership Program,<br />

GEAR UP, and the University of California Office of the President.<br />

We also gratefully acknowledge the contributions of teachers<br />

and administrators at Sacramento High School and Woodland High School<br />

who piloted the CAHSEE on Target curriculum.<br />

© Copyright The Regents of the University of California, Davis campus, 2005-06<br />

All Rights Reserved. Pages intended to be reproduced for students activities<br />

may be duplicated for classroom use. All other text may not be reproduced in any form<br />

without the express written permission of the copyright holder.<br />

For further information,<br />

please visit the School/University Partnerships Web site at:<br />

http://sup.ucdavis.edu


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Introduction to the CAHSEE<br />

The CAHSEE stands for the California High School Exit Exam. The<br />

mathematics section of the CAHSEE consists of 80 multiple-choice<br />

questions that cover 53 standards across 6 strands. These strands<br />

include the following:<br />

<strong>Number</strong> <strong>Sense</strong> (14 Questions)<br />

Statistics, Data Analysis & Probability (12 Questions)<br />

Algebra & Functions (17 Questions)<br />

Measurement & Geometry (17 Questions)<br />

Mathematical Reasoning (8 Questions)<br />

Algebra 1 (12 Questions)<br />

What is CAHSEE on Target?<br />

CAHSEE on Target is a tutoring course specifically designed for the<br />

California High School Exit Exam (CAHSEE). The goal of the program<br />

is to pinpoint each student’s areas of weakness and to then address<br />

those weaknesses through classroom and small group instruction,<br />

concentrated review, computer tutorials and challenging games.<br />

Each student will receive a separate workbook for each strand and will<br />

use these workbooks during their tutoring sessions. These workbooks<br />

will present and explain each concept covered on the CAHSEE, and<br />

introduce new or alternative approaches to solving math problems.<br />

What is <strong>Number</strong> <strong>Sense</strong>?<br />

<strong>Number</strong> <strong>Sense</strong> is the understanding of numbers and their<br />

relationships. The <strong>Number</strong> <strong>Sense</strong> Strand concepts that are tested on<br />

the CAHSEE can be divided into five major topics: Integers &<br />

Fractions; Exponents; Word Problems; Percents; and Interest. These<br />

topics are presented as separate units in this workbook.<br />

1


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Unit 1: Integers & Fractions<br />

On the CAHSEE, you will be given several problems involving rational<br />

numbers (integers, fractions and decimals).<br />

Integers are whole numbers; they include . . .<br />

• positive whole numbers {1, 2, 3, . . . }<br />

• negative whole numbers {−1, −2, −3, . . . } and<br />

• zero {0}.<br />

Positive and negative integers can be thought of as opposites of one<br />

another.<br />

A. Signs of Integers<br />

All numbers are signed (except zero). They are either positive or<br />

negative.<br />

When adding, subtracting, multiplying and dividing integers, we need<br />

to pay attention to the sign (+ or -) of each integer.<br />

Example: 5 ● -3 = ____<br />

Example: -5 + 4 = ___<br />

Example: -3 ● 12 = ___<br />

Whether it’s written or not, every number has a sign:<br />

Example: 5 means +5<br />

2


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Signed <strong>Number</strong>s in Everyday Life<br />

Signed numbers are used in everyday life to describe various<br />

situations. Often, they are used to indicate opposites:<br />

Altitude: The elevator went up 3 floors (+3) and then went down 5<br />

floors (-5).<br />

Weight: I lost 20 pounds (-20) but gained 10 back (+10).<br />

Money: I earned $60 (+60) and spent $25 (-25).<br />

Temperature: The temperature rose 5 degrees (+5) and then fell 2<br />

degrees (-2).<br />

Sea Level: Jericho, the oldest inhabited town in the world, lies 853<br />

feet below sea level (-853), making it the lowest town on earth.<br />

Mount Everest is the highest mountain in the world, standing at<br />

8850 meters (+8850), nearly 5.5 miles above sea level.<br />

Can you think of any other examples of how signed numbers are used<br />

in life?<br />

________________________________________________________<br />

________________________________________________________<br />

________________________________________________________<br />

________________________________________________________<br />

________________________________________________________<br />

________________________________________________________<br />

3


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

i. Adding Integers<br />

When adding two or more integers, it is very important to pay<br />

attention to the sign of each integer. Are we adding a positive or<br />

negative integer? We can demonstrate this concept with a number<br />

line.<br />

Look at the two examples below. In the first example, we add a<br />

positive 3 (+3) to 2.<br />

Example: 2 + 3 = __<br />

In this second example, we add a negative 3 (-3) to 2.<br />

Example: 2 + (–3) = __<br />

As you can see, we get a very different answer in this second problem<br />

To add integers using a number line, begin with the first number in<br />

the equation. Place your finger on that number on the number line.<br />

Look at the value and sign of the second number: if positive,<br />

move to the right; if negative, move to the left. (If a number<br />

does not have a sign, this means it is positive.) With your finger,<br />

move the number of spaces indicated by the second number.<br />

Example: 1 + (-2) = ___<br />

4


On Your Own<br />

-2 + (-3) = ___<br />

-6 + (3) = ___<br />

3 + (-6) = ___<br />

-3 + 6 = ___<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

5


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Rules for Adding Signed <strong>Number</strong>s (without a <strong>Number</strong> Line)<br />

A. Same Signs<br />

• Find the sum<br />

• Keep the sign<br />

B. Different Signs<br />

• Find the difference<br />

• Keep the sign of the larger number (# with larger absolute<br />

value)<br />

On Your Own<br />

-8 + (-7) = ___ -8 + 7 = ___<br />

(-13) + (-9) = ___ (+13) + (+9) = ___<br />

21 + (-21) = ___ (-21) + 21 = ___<br />

–13 +18 = ___ -18 + 13 = ___<br />

Add -10 and -5: ___ Add (-10), (+4), and (-16): ___<br />

6


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

ii. Subtracting Integers<br />

We can turn any subtraction problem into an addition problem. Just<br />

change the subtraction sign (-) to an addition sign (+) and<br />

change the sign of the second number. Then solve as you would<br />

an addition problem.<br />

Example: –2 - (+ 3) = ___<br />

Turn it from a subtraction problem to an addition problem; then<br />

change the sign of the second number:<br />

–2 - (+ 3) = -2 + (-3)<br />

Now solve as you would an addition problem.<br />

We can show this on a number line. Place your finger on that number<br />

on the number line. Look at the value and sign of the second number:<br />

if positive, move to the right; if negative, move to the left. With<br />

your finger, move the number of spaces indicated by the second<br />

number:<br />

Let's look at another problem:<br />

Example: -2 - (-3) = -2 + (___)<br />

Answer: ___<br />

Answer: ___<br />

7


On Your Own<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

6 – (+3) = 6 + (___) = _____<br />

3 – (-3) = 3 + (___) = ____<br />

-5 – (+1) = -5 + (___) = ____<br />

1 – (+1) = 1 + (___) = ___<br />

8


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Rules for Subtracting Signed <strong>Number</strong>s (without a <strong>Number</strong> Line)<br />

Add its opposite! Draw the line and change the sign (of the second<br />

number), and follow the rules for addition.<br />

Example: 6 – (-4)<br />

Steps:<br />

• Draw the line (to turn the minus sign into a plus sign): 6 + ____<br />

• Change the sign of the second number: 6 + (+ 4)<br />

• Now you have an addition problem. Follow the rules of adding<br />

numbers: 6 + 4 =10<br />

On Your Own: Draw the line and change the sign. Then solve the<br />

addition problem.<br />

19 – (- 13) = ___ -17 – (-15) = ___<br />

34 – (-9) = ___ -18 - 14 = ___<br />

-15 - (-35) = ___ 13 - (+15) = ___<br />

-13 – 15 = ___ -35 - (+35) = ___<br />

Subtract (-15) from (20): ___ Subtract 4 from (-14): ___<br />

9


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Signed <strong>Number</strong>s Continued<br />

Look at the following problem:<br />

Example: 1 - 3 + 5 = ___<br />

We can represent this problem on a number line:<br />

We begin at 1, move 3 spaces backwards (to the left) and then 5<br />

spaces forwards (to the right). We arrive at + 3.<br />

When we are given a problem with three or more signed integers, we<br />

must work out, separately, the addition and subtraction for each<br />

integer pair:<br />

1 - 3 + 5 = 1 - 3 + 5<br />

1 - 3 = -2 ← ⎯⎯ Work out the addition or subtraction for the 1st 2 integers<br />

-2 + 5 = ___ ← ⎯⎯ Take the answer from above & add it to the last integer.<br />

On Your Own<br />

1. 12 + 3 - 5 + 4 = _____<br />

2. -3 + 5 - 2 + 3 = _____<br />

3. 4 - 6 + 3 - 2 = _____<br />

10


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

iii. Multiplying and Dividing with Signed <strong>Number</strong>s<br />

Multiplying<br />

The product of two numbers with the same sign is positive.<br />

Example: -5 ● -3 = 15<br />

The product of two numbers with different signs is negative.<br />

Example: -5 ● 3 = -15<br />

Dividing<br />

The quotient of two numbers with the same sign is positive.<br />

Example: -15 ÷ -3 = 5<br />

The quotient of two numbers with different signs is negative.<br />

Example: -15 ÷ 3 = -5<br />

On Your Own<br />

(+8) (–4) = ___ (–7) (7) = ___<br />

(–8) (-8) = ___ (+7)(+8) = ___<br />

– 36 (-3) = ___ –36 3 = ___<br />

11


B. Absolute Value<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

The absolute value of a number is its distance from 0. This distance<br />

is always expressed as a positive number, regardless if the number<br />

is positive or negative.<br />

It is easier to understand this by examining a number line:<br />

The absolute value of 5, expressed as |5|, is 5 because it is 5 units<br />

from 0. We can see this on the number line above. The absolute value<br />

of -5, expressed as |-5|, is also 5 because it is 5 units from 0. Again,<br />

look at the number line and count the number of units from 0.<br />

On Your Own: Complete the chart. How far from zero is the number?<br />

<strong>Number</strong> Absolute Value<br />

|-16|<br />

|-115|<br />

|342|<br />

|x|<br />

|-x|<br />

|-100|<br />

12


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Finding the Absolute Value of an Expression<br />

On the CAHSEE, you may need to find the absolute value of an<br />

expression. To do this, . . .<br />

• Evaluate the expression within the absolute value bars.<br />

• Take the absolute value of that result.<br />

• Perform any additional operations outside the absolute value<br />

bars.<br />

Example: 3 + |-4 - 3| = 3 + |-7| = 3 + 7 = 10<br />

On Your Own: Complete the chart.<br />

5 ●|3-8| = 5 ●|-5| = 5 ● 5 = 25<br />

|15 + 6| = =<br />

|-6 + 2| = =<br />

|1 - 3 + 2| = =<br />

4 + |-6| = =<br />

|-4| + |4| = =<br />

|16| - |-16| = =<br />

|-2| - |13| = =<br />

|-2| - |-13| = =<br />

13


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Absolute Value Continued 2.5<br />

While the absolute value of a number or expression will always be<br />

positive, the number between the absolute value bars can be<br />

positive or negative.<br />

Notice that in each case, the expression is equal to +8.<br />

You may be asked to identify these two possible values on the<br />

CAHSEE.<br />

Example: If |x| = 8, what is the value of x?<br />

For these types of problems, the answer consists of two values: the<br />

positive and negative value of the number.<br />

In the example above, the two values for x are 8 or -8.<br />

On Your Own<br />

1. If |y| = 225, what is the value of y? ____ or ____<br />

2. If |x| = 1,233, what is the value of x? ______ or ______<br />

3. If |m| = 18, what is the value of m? ____ or ____<br />

4. If |x| = 12, what is the value of x? ____ or ____<br />

5. If |y| = 17, what is the value of y? ____ or ____<br />

14


C. Fractions<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

A fraction means a part of a whole.<br />

Example: In the picture below, one of four equal parts is shaded:<br />

1<br />

We can represent this as a fraction:<br />

4<br />

1<br />

Fractions are expressed as one number over another number:<br />

4<br />

Every fraction consists of a numerator (the top number) and a<br />

denominator (the bottom number):<br />

A ← ⎯⎯ Numerator<br />

B ← ⎯⎯ Denominator<br />

A<br />

Fractions mean division: = A ÷ B<br />

B<br />

1<br />

= 1 ÷ 4 = 4 1 = .25<br />

4<br />

4<br />

= 4 ÷ 5 = 5 4 = .8<br />

5<br />

1<br />

= 1 ÷ 2 = 2 1 = .5<br />

2<br />

15


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

i. Adding & Subtracting Fractions<br />

Same Denominator: Keep the denominator; add the numerators:<br />

1 2<br />

Example: + = _____<br />

4 4<br />

We can represent this problem with a picture: Begin with the first<br />

1 2<br />

fraction, , and add two more fourths ( ):<br />

4<br />

4<br />

3<br />

We now have three-fourths of the whole shaded:<br />

4<br />

On Your Own: Add the following fractions.<br />

1 2<br />

+ = -------<br />

8 8<br />

1 1<br />

+ = -------<br />

3 3<br />

2 3<br />

+ = -------<br />

5 5<br />

2 1<br />

- = -------<br />

3 3<br />

Rule: When adding and subtracting fractions that have common<br />

denominators, we just add or subtract the numerators and keep the<br />

denominator. It gets trickier when the denominators are not the same.<br />

16


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Different Denominator<br />

1 3<br />

Example: +<br />

4 8<br />

Let's represent this with a picture:<br />

The first picture shows one whole divided into four parts. One<br />

1<br />

of these parts is shaded. We represent this as a fraction:<br />

4<br />

The second picture shows one whole divided into eight parts. Three<br />

3<br />

of these parts are shaded. We represent this as a fraction:<br />

8<br />

In order to add these two fractions, we need to first divide them up<br />

into equal parts. The first picture is divided into fourths but the<br />

second is divided into eighths. We can easily convert the first<br />

picture into eighths by drawing two more lines (i.e. divide each fourth<br />

by half):<br />

17


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Now let's see how the first fraction would appear once it is divided<br />

into eighths:<br />

1 2<br />

We can see, from the above picture, that is equal to .<br />

4<br />

8<br />

Now that we have a common denominator (8), we can add the<br />

2 3<br />

fractions: + . Just keep the denominator and add the<br />

8 8<br />

numerators:<br />

2 3<br />

+ =<br />

8 8 8<br />

2 4<br />

Let's look at another example: +<br />

3 5<br />

Can we add these two fractions in their current form? Explain.<br />

To add two fractions, we need a common denominator. We must<br />

therefore convert the fractions to ones whose denominator is the<br />

same. We can use any common denominator, but it is much easier to<br />

use the lowest common denominator, or LCD. One way to find the<br />

LCD is to make a table and list, in order, the multiples of each<br />

denominator. (Multiple means Multiply!)<br />

18


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Finding the Lowest Common Denominator (LCD)<br />

Look at the last problem again: 2 + 4<br />

3 5<br />

Now list the multiples of each denominator until you reach a<br />

common number.<br />

Multiples of 3 Multiples of 5<br />

3 5<br />

6 10<br />

9 15<br />

12<br />

15<br />

The lowest common denominator (LCD) is the first<br />

common number in both columns: 15. This will be the new<br />

denominator for both fractions.<br />

Since we changed the denominators, we must also change the<br />

numerators so that each new fraction is equivalent (or equal) to the<br />

original fraction.<br />

• Let’s start with the first original fraction: 2/3. Go back to the<br />

table. How many times did we multiply the denominator, 3,<br />

by itself? (Hint: How many rows did we go down in the first<br />

column?) ___<br />

• Since we multiplied the denominator (3) by __ to get 15,<br />

we must also multiply the numerator (2) by ___.<br />

Our new fraction is 15<br />

• Now let’s look at the second fraction: 4/*5. Since we<br />

multiplied the denominator (5) by ___, we do the same to the<br />

numerator: 4 ● ___ = ___.<br />

Our new fraction is 15<br />

• Now add the new fractions. 15 + 15 = 15<br />

We have an improper fraction because the numerator > the<br />

denominator. We must change it to a mixed number:<br />

22<br />

= ________<br />

15<br />

19


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Let's look at another example:<br />

Example: Add the following fractions: 3 + 4<br />

4 5<br />

In order to add these fractions we must first find a common<br />

denominator. Make a table and list all of the multiples for each<br />

denominator until we reach a common multiple:<br />

Multiples of 4 Multiples of 5<br />

4 5<br />

8 10<br />

12 15<br />

16 20<br />

20<br />

We have a common denominator for both fractions: 20. Since we<br />

changed the denominators for both fractions, we must also change the<br />

numerators so that each new fraction is equivalent to the original<br />

fraction.<br />

3<br />

Let’s begin with the first fraction: =<br />

4 20<br />

4<br />

Now let’s proceed to the second fraction: =<br />

5 20<br />

Now both fractions have common denominators; add<br />

them:<br />

20 + 20 = 20<br />

If the sum is an improper fraction (i.e. numerator > denominator),<br />

we generally change it to a proper fraction: _______<br />

20


On Your Own<br />

Example: 3 + 5<br />

4 6<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Step 1: Make a table and list the multiples of each denominator<br />

until you reach a common denominator:<br />

Step 2: Convert each fraction to an equivalent fraction:<br />

Step 3: Add the fractions:<br />

Note: If you end up with an improper fraction, be sure to<br />

convert it to a mixed number.<br />

21


Practice<br />

4 2<br />

+ = -----------<br />

5 5<br />

7 3<br />

– = -----------<br />

9 9<br />

2 3<br />

+ = -----------<br />

5 4<br />

2 5<br />

+ = -----------<br />

3 8<br />

3 1<br />

- = -----------<br />

4 6<br />

5 1<br />

- = -----------<br />

8 2<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

'<br />

22


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Prime Factorization<br />

Another way to find the lowest common denominator of two fractions<br />

is through prime factorization. First, let’s learn more about prime<br />

numbers:<br />

Prime <strong>Number</strong>s: A prime number has two distinct whole number<br />

factors: 1 and itself.<br />

Note: 1 is not prime because it does not have two distinct<br />

factors.<br />

Example: 6 is not prime because it can be expressed as 2 ● 3.<br />

Example: 7 is prime because it can be expressed only as the<br />

product of two distinct factors: 1 ● 7.<br />

Write the first 10 prime numbers:<br />

2 3 5 ___ ___ ___ ___ ___ ___ ___<br />

Composite <strong>Number</strong>s<br />

A non-prime number is called a composite number. Composite<br />

numbers can be broken down into products of prime numbers:<br />

Example: 4 = 2 X 2<br />

Example: 12 = 2 X 6 = 2 X 2 X 3<br />

Example: 66 = 6 X 11 = 2 X 3 X 11<br />

Example: 24 = 2 X 12 = 2 X 2 X 2 X 3<br />

Example: 33 = 3 X 11<br />

Example: 125 = 5 X 5 X 5<br />

23


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Practice: Circle all of the prime numbers in the chart below:<br />

1<br />

6<br />

11<br />

16<br />

21<br />

26<br />

31<br />

36<br />

41<br />

46<br />

2<br />

7<br />

12<br />

17<br />

22<br />

27<br />

32<br />

37<br />

42<br />

47<br />

3<br />

8<br />

13<br />

18<br />

23<br />

28<br />

33<br />

38<br />

43<br />

48<br />

4<br />

9<br />

14<br />

19<br />

24<br />

29<br />

34<br />

39<br />

44<br />

49<br />

5<br />

10<br />

15<br />

20<br />

25<br />

30<br />

35<br />

40<br />

45<br />

50<br />

24


Prime Factor Trees<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

We can find the prime factors of a number by making a factor<br />

tree:<br />

Example: Find the prime factors of 18.<br />

• Write your number: 18<br />

• Begin with the smallest prime number factor of 18 (i.e. the<br />

smallest prime number that divides evenly 18.<br />

This number is 2.<br />

• Draw two branches: 2 and the second factor: 9.<br />

18<br />

⁄ \<br />

2 9<br />

• Continue this process for each branch until you have no remaining<br />

composite numbers. The prime factors of 18 are the prime<br />

numbers at the ends of all the branches:<br />

18<br />

⁄ \<br />

2 9<br />

⁄\<br />

3 3<br />

The prime factored form of 18 is ___ ● ___ ● ___.<br />

25


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Example: Find the prime factors of 60 using the factor tree:<br />

60<br />

⁄\<br />

2 30<br />

⁄\<br />

2 15<br />

⁄\<br />

3 5<br />

The prime factors of 60 are the factors at the end of each<br />

branch: ___, ___, ____ and ___.<br />

Helpful Guidelines:<br />

• Start with the smallest numbers: first 2’s, then 3’s, and so on.<br />

• If a number is even, it is divisible by 2.<br />

Note: An even number ends in 0, 2, 4, 6, and 8.<br />

Examples: 124 38 46 180 112<br />

• If the digits of a number add up to a number divisible by 3, the<br />

number is divisible by 3.<br />

Example: 123 can be divided evenly by 3 because if we add all of its<br />

digits, we get 6: 1 + 2 + 3 = 6<br />

Since the sum of the digits of 123 is divisible by 3, so too is 123.<br />

• If a number ends in 0 or 5, it is divisible by 5.<br />

Examples: 25 130 125 455<br />

26


On Your Own<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Find the prime factors of each number, using a factor tree:<br />

64 48<br />

72<br />

27


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Prime Factorization and the Lowest Common Denominator<br />

On the CAHSEE, you will be asked to find the prime factored form of<br />

the lowest common denominator (LCD) of two fractions:<br />

Example: Find the prime factored form for the lowest<br />

5 5<br />

common denominator + .<br />

6 9<br />

There are two methods we can use to solve this problem:<br />

Method I: Factor Tree and Pairing<br />

Steps:<br />

• Make a factor tree for both denominators:<br />

6 9<br />

⁄\ ⁄\<br />

2 3 3 3<br />

• Pair up common prime factors:<br />

• Multiply the common factor (counted once) by all leftover<br />

(unpaired) factors:<br />

LCD = 3 ● __ ● ___ = ____<br />

28


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Let's look at another example:<br />

Example: Find the least common multiple of 72 and 24. Write the<br />

LCM in prime-factored form.<br />

Steps:<br />

• Make a factor tree for each number:<br />

72 24<br />

⁄\ ⁄ \<br />

2 36 2 12<br />

⁄\ ⁄\<br />

2 18 2 6<br />

⁄ \ ⁄\<br />

2 9 2 3<br />

⁄ \<br />

3 3<br />

• Pair off common factors:<br />

72 = 2 ● 2 ● 2 ● 3 ● 3<br />

24 = 2 ● 2 ● 2 ● 3<br />

←⎯⎯ Count any common factor once!<br />

• Multiply all common factors by all leftover (unpaired) factors:<br />

LCM = __ ● __ ● __ ● __ ● ___ = ____<br />

29


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

On Your Own: Solve the following problems, using the factor<br />

tree/pairing method.<br />

1. What is the prime factored form of the lowest common<br />

5 5<br />

denominator of + ?<br />

9 12<br />

2. Find the least common multiple, in prime-factorization form,<br />

of 12 and 15.<br />

We will now look at the second method to find the prime factored<br />

from of the lowest common denominator (LCD) of two fractions.<br />

30


CAHSEE on Target<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Method II: Factor Tree and Venn Diagram<br />

To illustrate this second method, let's return to the original problem:<br />

Example: Find the prime factored form for the lowest<br />

5 5<br />

common denominator of + .<br />

6 9<br />

• Use the factor tree method to find the prime factored form of 6:<br />

6<br />

⁄ \<br />

2 3<br />

• Use the factor tree method to find the prime factored from of 9:<br />

9<br />

⁄ \<br />

3 3<br />

• Use a Venn diagram to find the prime-factored form of the lowest<br />

common denominator:<br />

On the next page, we will learn how to fill out this diagram.<br />

31


Venn Diagrams<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Venn diagrams are overlapping circles that help us compare and<br />

contrast the characteristics of different things. We can use them to<br />

find what is common to two items (where the circles overlap in the<br />

middle) and what is different between them (what is outside the<br />

overlap on either or both sides).<br />

Here, we want to find out which prime factors are the same for two<br />

numbers and which factors are distinct, or different.<br />

6 9<br />

⁄ \ ⁄ \<br />

2 3 3 3<br />

Steps:<br />

• Since only one 3 is common to both numbers, we need to put it in<br />

the middle, where the two circles overlap:<br />

6 Both 9<br />

↓<br />

Continued on next page ⎯<br />

⎯→<br />

32


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

• Now find the prime factors that are left for 6 and place them in the<br />

part of the circle for 6 that does not overlap with the circle for 9.<br />

6 Both 9<br />

↓<br />

• Next, find the prime factors that are left for 9 and place them in the<br />

part of the circle that does not overlap with the circle for 6.<br />

6 Both 9<br />

↓ ↓ ↓<br />

• The lowest common denominator for 6 and 9 is the product of all<br />

of the numbers in the circles:<br />

___ ● ___ ● ___, which is equal to ____<br />

Note: To write the LCD in prime-factored form, we do not carry out<br />

the multiplication; we just write the prime numbers:<br />

LDC of 6 and 9 = ___ ● ___ ● ___<br />

33


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

On Your Own<br />

1. What is the prime factored form of the lowest common denominator<br />

1 3<br />

of and ?<br />

6 10<br />

• Create separate prime factor trees for both denominators:<br />

6 10<br />

⁄ \ ⁄ \<br />

__ __ __ __<br />

• Organize the prime factors of both denominators, using a Venn<br />

diagram:<br />

6 Both 10<br />

What is the LCD? ________<br />

Write the LCD in prime factored form: _____________<br />

34


CAHSEE on Target<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

2. Find the prime factored form of the lowest common denominator for<br />

the following:<br />

5 11<br />

+<br />

8 12<br />

Factor Trees:<br />

LCD: ______<br />

8 Both 12<br />

LCD in prime factored form: _________________<br />

35


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

ii. Multiplying Fractions<br />

Whenever you are asked to find a fraction of a number, you need to<br />

multiply. In math, the word “of” means multiply.<br />

1 1<br />

Example: Find of .<br />

2 2<br />

1 1<br />

This is a multiplication problem. It means, “What is ● ?”<br />

2 2<br />

We can represent the problem visually. Here is the first part of the<br />

1<br />

problem: of the circle has been shaded.<br />

2<br />

1<br />

Taking of a number means dividing it by 2.<br />

2<br />

Now, if we take one-half of this again (divide it by 2 again), we get<br />

the following:<br />

1 1 1<br />

of is equal to .<br />

2 2<br />

4<br />

We end up with one-fourth of the circle.<br />

Note: We also could have solved the above problem by multiplying<br />

the numerator by the numerator and the denominator by the<br />

denominator:<br />

Numerator ● Numerator_ = 1 ● 1 = 1<br />

Denominator ● Denominator 2 ● 2 4<br />

36


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

When working these problems out during the CAHSEE, you will need to<br />

apply this rule:<br />

Numerator ● Numerator__<br />

Denominator ● Denominator<br />

Look at the next problem:<br />

1 1<br />

Find of 24. In math, we can write this as follows: ● 24<br />

2<br />

2<br />

The first factor is a fraction and the second factor is a whole number.<br />

We can easily change the second factor to a fraction because any<br />

whole number can be expressed as a fraction by placing it over a 1:<br />

24<br />

24 = because 24 means 24 ones.<br />

1<br />

1 24<br />

We can rewrite the problem as follows: ●<br />

2 1<br />

Now, just follow the rule for multiplying two fractions:<br />

Numerator ● Numerator__<br />

Denominator ● Denominator<br />

1 24 24<br />

● = = ___<br />

2 1 2<br />

1<br />

Note: Taking of 24 means dividing 24 by 2.<br />

2<br />

37


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Now look at the next example:<br />

24 5<br />

Example: ● = ____<br />

1 6<br />

There are two ways to solve this problem:<br />

1. The hard way: Perform all operations<br />

• Multiply numerators: 24 ● 5<br />

• Multiply denominators: 1 ● 6<br />

• Divide new numerator by denominator: 120 ÷6<br />

24 ● 5 = 120 = 120 ÷6 = ___<br />

1 ● 6 6<br />

2. The easy way: Simplify first, and then multiply:<br />

4<br />

24 ● 5_ = ____ Simplify by dividing out common factors!<br />

1 6 1<br />

Look at the following problems:<br />

533 9 3<br />

● 4 = ______ 3,435 ● = _____ 79 ● = _____<br />

4<br />

9<br />

3<br />

Do you need to work out these problems, or do you already know the<br />

answers? ________________________________________________<br />

________________________________________________________<br />

Remember: If you divide both a numerator and denominator by a<br />

common factor, you can make the problem much simpler to solve. So<br />

save yourself the time and work, and recognize these types of<br />

problems right away.<br />

38


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Look at the next set of problems:<br />

4 6<br />

●<br />

12 8<br />

8 5 14 3<br />

● ●<br />

15 12<br />

21 7<br />

What do you notice about the above problems? __________________<br />

________________________________________________________<br />

There is a lot of heavy multiplication involved in these problems. Is<br />

there a way to make your work easier? Explain:<br />

We can _________ fractions by ____________________<br />

before solving.<br />

We can simplify these problems quite a bit before solving. This makes<br />

our job easier. Let’s look at the first problem:<br />

4 6<br />

●<br />

12 8<br />

We can divide out common factors in each fraction. These<br />

common factors become clear if we write each fraction as a<br />

product of prime factors. Let's begin with the first fraction:<br />

4 = 1 2 ● 1 2____ = 1<br />

12 12 ● 12 ● 3 3<br />

Now do the second fraction on your own:<br />

6<br />

= ____________________<br />

8<br />

Now let's multiply the two reduced fractions; but first, can we simplify<br />

anymore? ______ If so, simplify first, and then multiply:<br />

39


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

On Your Own: Simplify and solve:<br />

8 5<br />

● = ______<br />

15 12<br />

3 10<br />

● = ______<br />

5 21<br />

14 3<br />

● = ______<br />

21 7<br />

12 5<br />

● = ______<br />

15 6<br />

2 2<br />

36 ● = _____ 27 ● = _____<br />

3<br />

9<br />

2 3<br />

● = _____<br />

3 2<br />

10 3<br />

● = _____<br />

15 2<br />

40


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

iii. Dividing Fractions<br />

When you divide something by a fraction, think, “How many<br />

times does the fraction go into the dividend?”<br />

1<br />

Example: 3 ÷<br />

2<br />

↑<br />

dividend<br />

This means, “How many times does ___ go into ____?”<br />

We can represent this visually:<br />

Answer: __________<br />

1<br />

Example: 2 ÷<br />

8<br />

We can represent this visually:<br />

Answer: __________<br />

41


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

On Your Own: Solve the next few problems, asking each time,<br />

“How many times does the fraction go into the whole number?”<br />

1<br />

3 ÷ = ___<br />

4<br />

1<br />

3 ÷ = ___<br />

8<br />

1<br />

4 ÷ = ___<br />

8<br />

Do you see a pattern? Explain.<br />

___________________________________________________<br />

___________________________________________________<br />

42


Reciprocals<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

As we saw in the previous exercise, each time we divide a whole<br />

number by a fraction, we get as our answer the product of the<br />

whole number and the reciprocal of the fraction.<br />

Reciprocal means the flip-side, or inverse.<br />

4 5<br />

Example: The reciprocal of is .<br />

5 4<br />

On Your Own: Find the reciprocal of each fraction:<br />

3 7 12<br />

⎯ ⎯→ _____ ⎯ ⎯→ _____ ⎯ ⎯→ _____<br />

4<br />

9<br />

5<br />

13 35 1<br />

⎯ ⎯→ ____ ⎯ ⎯→ ____ ⎯ ⎯→ _____<br />

1<br />

53<br />

12<br />

Now let's find the reciprocal of a whole number. We know that<br />

any whole number (or integer) can be expressed as a fraction by<br />

placing it over 1:<br />

35<br />

Example: 35 =<br />

1<br />

The reciprocal is the fraction turned upside down, or inverted:<br />

1<br />

Example: The reciprocal of 35 is<br />

35<br />

On Your Own: Find the reciprocal of each integer.<br />

1000 121 173 -18 -100<br />

_____ ____ ____ ____ ____<br />

43


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Now we are ready to divide a whole number by a fraction.<br />

1 2 10 20<br />

Example: 2 ÷ = ● = = 20<br />

10 1 1 1<br />

We can represent the above problem visually:<br />

1<br />

2 ÷ means . . .<br />

10<br />

If we count the number of little rectangles in the two big<br />

rectangles, we get _____.<br />

On Your Own<br />

1<br />

3 ÷ = ________________________<br />

5<br />

1<br />

6 ÷ ÷ = ________________________<br />

5<br />

1<br />

5 ÷ = _________________________<br />

3<br />

1<br />

2 ÷ = _________________________<br />

3<br />

1<br />

4 ÷ = _________________________<br />

2<br />

44


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Simplifying Division Problems<br />

3 9<br />

Example: ÷<br />

5 10<br />

Remember the rule for dividing fractions:<br />

Rule: When dividing fractions, multiply the first fraction<br />

by the reciprocal of the second fraction!<br />

Steps:<br />

• Multiplying the first fraction by the reciprocal of the second<br />

fraction, we get . . .<br />

3 10<br />

●<br />

5 9<br />

• We can simplify this problem by dividing out common factors:<br />

1 3 ● 10 2<br />

1 5 9 3<br />

• Now, apply the rule for multiplication:<br />

Numerator ● Numerator____ = 1 ● 2 = ____<br />

Denominator ● Denominator 1 ● 3<br />

45


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

On Your Own: Simplify and solve.<br />

1 3 ÷ = _________________<br />

4 8<br />

2 3 ÷ = _________________<br />

5 10<br />

3 9 ÷ = _________________________<br />

7 14<br />

5 15 ÷ = __________________<br />

8 24<br />

1 13 ÷ = __________________<br />

10 10<br />

46


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Unit Quiz: The following problems appeared on the CAHSEE.<br />

11 1 1<br />

1. – ( + ) =<br />

12 3 4<br />

1<br />

A.<br />

3<br />

3<br />

B.<br />

4<br />

5<br />

C.<br />

6<br />

9<br />

D.<br />

5<br />

5 7<br />

2. Which fraction is equivalent to + ?<br />

6 8<br />

35<br />

A.<br />

48<br />

6<br />

B.<br />

7<br />

20<br />

C.<br />

21<br />

41<br />

D.<br />

24<br />

3. What is the prime factored form for the lowest common<br />

2 7<br />

denominator of the following: + ?<br />

9 12<br />

A. 3 X 2 X 2<br />

B. 3 X 3 X 2 X 2<br />

C. 3 X 3 X 3 X 2 X 2<br />

D. 9 X 12<br />

47


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

4. Which of the following is the prime factored form of the lowest<br />

7 8<br />

common denominator of +15 ?<br />

10<br />

A. 5 X 1<br />

B. 2 X 3 X 5<br />

C. 2 X 5 X 3 X 5<br />

D. 10 X 15<br />

5. Which of the following numerical expressions results in a negative<br />

number?<br />

A. (-7) + (-3)<br />

B. (-3) + (7)<br />

C. (3) + (7)<br />

D. (3) + (-7) + (11)<br />

6. One hundred is multiplied by a number between 0 and 1. The<br />

answer has to be ____.<br />

A. less than 0.<br />

B. between 0 and 50 but not 25.<br />

C. between 0 and 100 but not 50.<br />

D. between 0 and 100.<br />

7. If |x| = 3, what is the value of x?<br />

A. -3 or 0<br />

B. -3 or 3<br />

C. 0 or 3<br />

D. -9 or 9<br />

48


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

8. What is the absolute value of -4?<br />

A. -4<br />

1<br />

B. −<br />

4<br />

1<br />

C.<br />

4<br />

D. 4<br />

9. The winning number in a contest was less than 50. It was a<br />

multiple of 3, 5, and 6. What was the number?<br />

A. 14<br />

B. 15<br />

C. 30<br />

D. It cannot be determined<br />

10. If n is any odd number, which of the following is true about n + 1?<br />

A. It is an odd number.<br />

B. It is an even number<br />

C. It is a prime number<br />

D. It is the same as n −1.<br />

11. Which is the best estimate of 326 X 279?<br />

A. 900<br />

B. 9,000<br />

C. 90,000<br />

D. 900,000<br />

49


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

12. The table below shows the number of visitors to a natural history<br />

museum during a 4-day period.<br />

Day <strong>Number</strong> of Visitors<br />

Friday 597<br />

Saturday 1115<br />

Sunday 1346<br />

Monday 365<br />

Which expression would give the BEST estimate of the total number<br />

of visitors during this period?<br />

A. 500 + 1100 + 1300 + 300<br />

B. 600 + 1100 + 1300 + 300<br />

C. 600 + 1100 + 1300 + 400<br />

D. 600 + 1100 + 1400 + 400<br />

2<br />

13. John uses of a cup of oats per serving to make oatmeal. How<br />

3<br />

many cups of oats does he need to make 6 servings?<br />

2<br />

A 2<br />

3<br />

B 4<br />

1<br />

C 5<br />

3<br />

D 9<br />

14. If a is a positive number and b is a negative number, which<br />

expression is always positive?<br />

A. a - b<br />

B. a + b<br />

C. a X b<br />

D. a ÷ b<br />

50


Unit 2: Exponents<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

On the CAHSEE, you will be given several problems on exponents.<br />

Exponents are a shorthand way of representing how many times a<br />

number is multiplied by itself.<br />

Example: 9 9 9 9 can be expressed as 9 4 since four 9's are<br />

multiplied together.<br />

Base ←⎯⎯ 9 4 exponent<br />

The number being multiplied is called the base.<br />

The exponent tells how many times the base is multiplied by itself.<br />

9 4 is read as “9 to the 4 th power,” or “9 to the power of 4.”<br />

Let's look at another example: 2 = 2 ● 2 ● 2 ● 2 ● 2 = 32<br />

On Your Own<br />

2³ = ___ 2 = ___<br />

3² = ___ 3³ = ___<br />

Power of 0<br />

Any number raised to the 0 power (except 0) is always equal to 1.<br />

Example: 100 0 = 1<br />

On Your Own<br />

7 0 = ___ 293 0 = ___ (-131) 0 = ___ 47 0 = ___<br />

51


Power of 1<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

A number raised to the 1 st power (i.e., an exponent of 1) is always<br />

equal to that number.<br />

Example: 100 1 = 100<br />

On Your Own<br />

7 1 = ____ 293 1 = ____ (-131) 1 = ____ 47 1 = ____<br />

Power of 2 (Squares)<br />

A number raised to the 2 nd power is referred to as the square of a<br />

number. When we square a whole number, we multiply it by itself.<br />

Example: 12² = 12 ● 12 = 144<br />

The square of any whole number is called a perfect square.<br />

Here are the first 3 perfect squares:<br />

1² = 1 ● 1 = 1 2² = 2 ● 2 = 4 3² = 3 ● 3 = 9<br />

On Your Own: Write the perfect squares for the following numbers:<br />

4² = ____ 5² = ____ 6² = ____ 7² = ____<br />

8² = ____ 9² = ____ 10² = ____ 11² = ____<br />

20² = ____ (2 - 8)² – (3 - 7)² =_______ 3² + 5² = _____<br />

52


Square Roots<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

The square root ( ) of a number is one of its two equal factors.<br />

Example: 8² = 64<br />

1 2 3 4 5 6 7 8<br />

2<br />

3<br />

4<br />

5<br />

6<br />

7<br />

8<br />

Any number raised to the second power (the power of 2) can be<br />

represented as a square. That’s why it’s called “squaring the<br />

number.”<br />

The square above has 64 units. Each side (the length and width) is 8<br />

units. The area of the square is determined by multiplying the length<br />

(8 units) by the width (8 units). The square root is the number of<br />

units in each of the two equal sides: 8<br />

Note: 64 has a second square root: -8 (-8 ● -8 = +64). However,<br />

when we are asked to evaluate an expression, we always take the<br />

positive root.<br />

Example: Find the square root of 36.<br />

Answer: 36 = ___<br />

53


On Your Own<br />

1. 25 = ___<br />

2. 16 = ___<br />

3. 100 = ___<br />

4. 81 = ___<br />

5. 49 = ___<br />

6. 121 = ___<br />

7. 400 = ___<br />

8. 4 + 9 = ___<br />

9.<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

2 2<br />

3 + 4 = ___<br />

10. Which is not a perfect square?<br />

A. 144<br />

B. 100<br />

C. 48<br />

D. 169<br />

54


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Power of 3 (Cubes)<br />

A number with an exponent of 3 (or a number raised to the 3 rd power)<br />

is the cube of a number.<br />

Example: 5³ = 5 ● 5 ● 5 = 125<br />

The cube of a whole number is called a perfect cube.<br />

Cubes of Positive <strong>Number</strong>s<br />

The cube of a positive number will always be a positive number.<br />

1³ = 1 ● 1 ● 1 = 1 2³ = 2 ● 2 ● 2 = 8<br />

Cubes and Negative <strong>Number</strong>s<br />

The cube of a negative number will always be a negative number.<br />

(-1)³ = (-1)(-1)(-1) = -1 (-2) 3 = (-2)(-2)(-2) = -8<br />

On Your Own: Write the perfect cubes for the following numbers:<br />

3³ = _____ 4³ = ______ 5³ = _____<br />

-3³ = _____ -4³ = ______ -5³ = _____<br />

55


Cube Roots<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

The cube root of a number is one of its three equal factors. The cube<br />

root of a positive number will always be a positive number.<br />

Example: What is the cube root of 27?<br />

The cube root of 27 is written as 3 27<br />

To find the cube root of 27, ask, “What number multiplied by itself 3<br />

times is equal to 27?”<br />

__ ● __ ● __ = 27<br />

3 ● 3 ● 3 = 27, or 3³ = 27.<br />

On Your Own<br />

3 3 3 3<br />

8 = ___ 64 = ____ 1 , 000 = ____ 125 = ____<br />

Cube Roots of Negative <strong>Number</strong>s<br />

The cube root of a negative number will always be a negative number.<br />

Example: 3 − 64<br />

Ask, “What number multiplied by itself 3 times is equal to -64?<br />

__ ● __ ● __ = -64<br />

-4 ● -4 ● -4 = -64, or (-4)³ = -64<br />

On Your Own: 3 − 1,<br />

000 = ____ 3 − 125 = ____ 3 − 8 = ____<br />

56


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Raising Fractions to a Power<br />

When raising a fraction to an exponent, both the numerator (top<br />

number) and the denominator (bottom number) are raised to the<br />

exponent:<br />

2<br />

5<br />

numerator<br />

denominator<br />

Example: (2/5)³ = 2 ● 2 ● 2 = 8_<br />

5 ● 5 ● 5 125<br />

On Your Own<br />

(1/4)²= ____ (1/2) = _____ (2/3)³ = ____<br />

(2/5)³ = _____ (4/7)² = ____ (6/11)² = _____<br />

(3/4)³ = ____ (5/12)= ____ (2/5)² = ____<br />

Taking the Root of a Fraction<br />

When taking the root of a fraction, we must take the root of both the<br />

numerator and denominator.<br />

Example:<br />

On Your Own<br />

3<br />

9 25 36<br />

= _____ = _____ = _____<br />

16<br />

100<br />

81<br />

1 81 1<br />

= ____ = _____ = _____<br />

125<br />

121<br />

9<br />

3<br />

3<br />

27<br />

= _____<br />

64<br />

8<br />

= _____<br />

27<br />

57


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Raising Negative <strong>Number</strong>s to a Power<br />

When raising a negative number to a power, we are raising both the<br />

number and the negative sign. The answer may be positive or<br />

negative:<br />

A. If the exponent is an even number, the answer will be a positive<br />

number (as in the example below) since a negative multiplied by a<br />

negative equals a positive.<br />

Example: (-2) 6 = (-2)(-2)(-2)(-2)(-2)(-2) = 64<br />

Note: (-2) 6 and -2 6 are two different problems:<br />

• -2 6 tells us to multiply positive 2 by itself 6 times<br />

(2)(2)(2)(2)(2)(2) = 64<br />

and then take the negative of that answer: -64<br />

• (-2) 6 tells us to multiply -2 by itself 6 times:<br />

(-2)(-2)(-2)(-2)(-2)(-2) = +64<br />

B. If the exponent is an odd number, the answer will be a negative<br />

number (a positive multiplied by a negative equals a negative).<br />

Example: (-2) 5 = (-2)(-2)(-2)(-2)(-2) = -32<br />

On Your Own<br />

(-3)² = _____ -3³ = _____ (-2)² = _____ (-2) = _____<br />

-4² = _____ -4 = _____ (-5)² = _____ -5² = _____<br />

58


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Negative Exponents<br />

On the CAHSEE, you may be given an expression with a negative<br />

exponent. When an exponent is negative, the expression represents<br />

a fraction:<br />

1<br />

Example: 3¯³ means 3<br />

3<br />

Notice that the exponent is now positive.<br />

Remember: Any whole number can be written as a fraction by placing<br />

it over 1:<br />

3<br />

3¯³ can also be written as<br />

1<br />

3 −<br />

We now flip the fraction and make the exponent positive.<br />

3 3 −<br />

1<br />

1<br />

⎯ ⎯→ 3<br />

3<br />

In the above example, the numerator is equal to 1, and the<br />

denominator consists of the base and the (positive) exponent.<br />

On Your Own: Flip the fraction and make the exponent positive.<br />

3¯² = ____ 5¯³= ____ 2¯³ = ____ 4¯² = ____<br />

1<br />

59


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Negative Exponents and Fractions<br />

When raising a fraction to a negative exponent, just invert the entire<br />

fraction and make the exponents positive:<br />

Example: − 3<br />

3<br />

1<br />

Here we have a fraction whose denominator consists of the base and a<br />

negative exponent. If we invert the fraction, the exponent<br />

becomes positive:<br />

3<br />

1<br />

−3<br />

3<br />

⎯ ⎯→<br />

1<br />

3<br />

On Your Own<br />

1<br />

1. ( ) 3<br />

2<br />

2. ( ) 3<br />

1<br />

3. ( ) 8<br />

3<br />

4. ( ) 5<br />

1<br />

5. ( ) 3<br />

−2<br />

−1<br />

−2<br />

−2<br />

−3<br />

⎯ ⎯→ 3 3<br />

2<br />

= ( )<br />

= ___<br />

1<br />

= ( ) = ___<br />

= _____<br />

= _____<br />

= _____<br />

60


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Multiplying Expressions Involving Exponents with a Common<br />

Base<br />

On the CAHSEE, you may be asked to multiply expressions involving<br />

exponents.<br />

Example: 3 5 ● 3 4<br />

In order to multiply expressions involving exponents, there must be a<br />

common base. In the above example, the base (3) is common to both<br />

terms.<br />

When we have a common base, the rule for multiplying the<br />

expressions is simple: keep the base and add the exponents:<br />

Base ● Base = Base 5+4 ⎯ ⎯→ 3 5 ● 3 4 =3 5+4 =3 9<br />

On Your Own<br />

2² ● 2⁸ = ____ 3¹ ● 3⁷ = ____<br />

4 3 ● 4 2 = ____ 4 ● 4¯ = ____<br />

3¯³ ● 3³ = ____ 6 ● 6 = ____<br />

61


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Note: In some cases, we may end up with a negative exponent.<br />

Remember to apply the rules for negative exponents: invert the<br />

fraction and make the exponent positive.<br />

Example: 3 2 ● 3 -3 = 3 2+(-3) 3<br />

= 3¯ =<br />

1<br />

1 −<br />

On Your Own<br />

1 1<br />

= = 1<br />

3 3<br />

4 1 ● 4¯ 3 = _______ 5¯ 1 ● 5¯ 1 = __________<br />

3 5 ● 3¯ 8 = _______ 4 ● 4¯ 7 = __________<br />

Dividing Expressions Involving Exponents with a Common Base<br />

On the CAHSEE, you may be asked to divide expressions involving<br />

exponents.<br />

For these types of problems, there must be a common base:<br />

3<br />

5<br />

Example: 3<br />

3<br />

To divide exponents with a common base, keep the base and<br />

subtract the exponent in the denominator from the exponent in the<br />

numerator:<br />

5<br />

5<br />

Base -<br />

= Base = Base² ⎯ ⎯→<br />

3<br />

3<br />

Base<br />

3 5-3 2<br />

= 3 = 3<br />

3<br />

62


On Your Own<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

3<br />

5<br />

3<br />

= _______ 2<br />

3<br />

3<br />

4<br />

8<br />

5<br />

= _________ 2<br />

3<br />

5<br />

4<br />

= ________<br />

4<br />

2<br />

= ________<br />

2<br />

−2<br />

3<br />

The next problem is a bit more complicated: −3<br />

3<br />

Remember, when an exponent is negative, the expression is a<br />

fraction and the numerator (top number) is always equal to 1,<br />

while the denominator (bottom number) is the base. But, here, the<br />

problem is already a fraction, so we really have one fraction over<br />

another fraction. We will get back to the above problem in a moment,<br />

but first, let’s do a quick review of the rules for dividing fractions:<br />

Dividing Fractions<br />

To divide two fractions, we multiply the 1st fraction by the<br />

reciprocal of the 2 nd fraction. This means that we invert the second<br />

fraction over, or invert it.<br />

2 5<br />

For example, the reciprocal of is .<br />

5 2<br />

Let’s solve the following problem:<br />

3 1 3 3 9<br />

÷ = ● =<br />

4 3 4 1 4<br />

9<br />

is an improper fraction (numerator > denominator). We must<br />

4<br />

1<br />

change this to a mixed fraction (whole number and fraction): 2<br />

4<br />

63


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

−2<br />

3<br />

Now we are ready to tackle the earlier: problem: −3<br />

3<br />

We have negative exponents in both the numerator and the<br />

denominator. We can therefore rewrite each as fractions with<br />

positive exponents:<br />

1 1<br />

3¯² = and 3¯³ = 2<br />

3<br />

3<br />

3<br />

We can now rewrite the original problem as follows: 2<br />

3<br />

1 1<br />

÷ 3<br />

Applying the rule for dividing two fractions, we invert the second<br />

fraction and multiply:<br />

1 3<br />

● 2<br />

3 1<br />

3<br />

Multiplying the numerator by the numerator, and the denominator by<br />

3<br />

3<br />

the denominator, we get . . . 2<br />

3<br />

Now we apply the rules for dividing exponents: the base remains the<br />

same and we subtract the exponent in the denominator from the<br />

exponent in the numerator:<br />

3<br />

3<br />

= 3³¯² = ________<br />

2<br />

3<br />

Shortcut!<br />

Since both exponents in the above example are negative, a quicker<br />

way to solve the problem is to just flip the fractions and reverse the<br />

sign of each exponent; then simplify:<br />

3<br />

−<br />

3<br />

−2<br />

3<br />

3<br />

3<br />

= = _________<br />

2<br />

3<br />

3<br />

64


Another Shortcut!<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

A third way to solve the problem is to apply the rule for dividing<br />

expressions with exponents: keep the base and subtract the<br />

exponent in the denominator from the exponent in the numerator:<br />

−2<br />

Base -2 -(-3) - + 3<br />

= Base = Base ² ⎯→<br />

−3<br />

Base<br />

3<br />

−<br />

3<br />

−2<br />

3<br />

On Your Own<br />

2<br />

−<br />

2<br />

−8<br />

8<br />

−<br />

8<br />

3<br />

−4<br />

2<br />

−<br />

2<br />

2<br />

−7<br />

2<br />

−<br />

2<br />

2 −<br />

2<br />

1<br />

2<br />

3<br />

2<br />

3<br />

⎯ Base 1<br />

= 3 -2 -(-3) = 3 - ² + 3 ⎯ ⎯→ 3 1 = 3<br />

= ___________<br />

= ___________<br />

= ___________<br />

= ________<br />

= ___________<br />

65


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Power Raised to a Power<br />

When raising a power to a power, multiply the powers together:<br />

Example: (2 3 ) 2 = 2 (3) ● (2) = 2 6<br />

This is easy to see if you expand the exponents:<br />

(2 3 ) 2 =<br />

(2³)(2³) =<br />

(2 ● 2 ● 2) (2 ● 2 ● 2) =<br />

2 ● 2 ● 2 ● 2 ● 2 ● 2 =<br />

2 6<br />

On Your Own<br />

(y³)² = ______ (2)² = ______<br />

(n 3 ) 3 = _____ (5)³ = _____<br />

(2²) = _____ (x²y)² = _____<br />

66


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Square Roots of Non-Perfect Squares<br />

Remember that when we multiply a whole number by itself, we get a<br />

perfect square. And the square root of a perfect square is the factor<br />

that, when multiplied by itself, gave us the perfect square.<br />

For example, the square root of 64 is 8 because 8 ● 8 = 64.<br />

But whole numbers that are not perfect squares still have square<br />

roots. However, their square roots are not whole numbers; rather<br />

they are decimals or fractions of whole numbers.<br />

On the CAHSEE, you may be given a non-perfect square and asked to<br />

place its root between two consecutive whole numbers.<br />

Example: Between what two consecutive whole numbers is 153 ?<br />

Solution:<br />

Think about our list of perfect squares. Refer to the chart on the next<br />

page.<br />

Since 153 falls between 144 and 169 in our perfect squares list, the<br />

square root of 153 is between 12 and 13. (Note: 12 and 13 are the<br />

square roots of 144 and 169 respectively).<br />

67


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Memorize these for the CAHSEE!<br />

<strong>Number</strong> Square<br />

1 1<br />

2 4<br />

3 9<br />

4 16<br />

5 25<br />

6 36<br />

7 49<br />

8 64<br />

9 81<br />

10 100<br />

11 121<br />

12 144<br />

13 169<br />

14 196<br />

15 225<br />

16 256<br />

17 289<br />

18 324<br />

19 361<br />

20 400<br />

68


On Your Own<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

1. Between what two consecutive whole numbers is the square root of<br />

17?<br />

2. Between which two consecutive whole numbers is 200 ?<br />

3. Between which two consecutive whole numbers is 130 ?<br />

4. The square root of 140 is between which two numbers?<br />

5. Between which two integers does 53 lie?<br />

69


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Roots and Exponents<br />

On the CAHSEE, you may be given a variable that has been raised to a<br />

power and asked to find the base (the original number before it was<br />

raised).<br />

Example: If x² = 25, find the value for x.<br />

Since the base (x) is raised to the second power, we can find the value<br />

for x by taking the square root of x² . Since we have an equation, we<br />

must also find the square root of 25 so that the two sides of the<br />

equation remain in balance.<br />

x² = 25 ⎯ ⎯→ x = 5<br />

You may also be given the root of a variable and asked to find the<br />

variable.<br />

Example: x = 5<br />

To solve this, we need to square both sides of the equation:<br />

( x )² = (5)² ⎯ ⎯→ x = 25<br />

On Your Own: Find x:<br />

x² = 64 ______ x³ = 8 ______<br />

x = 1/27 ______ x² = 9/16 ______<br />

x = 8/27 ______ x² = 4/25 ______<br />

x = 11 ______<br />

3 x = 10 ______<br />

x = 20 ______ x = 9 ______<br />

70


Scientific Notation<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Scientific Notation is a way to express very small or very large<br />

numbers, using exponents.<br />

Example of a Very Big <strong>Number</strong>: The distance of the earth from the<br />

sun is approximately 144,000,000,000 meters.<br />

You can see that it can be tedious to write so many zeroes. This<br />

number can be expressed much more simply in scientific notation:<br />

1.44 X 10<br />

Example of a Very Small <strong>Number</strong>: An example using a very small<br />

number is the mass of a dust particle: 0.000000000 753 kg.<br />

We can write this number in scientific notation as 7.53 X 10 - º.<br />

On the CAHSEE, you will need to . . .<br />

• Read numbers in scientific notation<br />

• Compare numbers in scientific notation<br />

• Convert from standard notation (15,340) to scientific notation<br />

(1.534 X 10 4 )<br />

• Convert from scientific notation (2.36 X 10¯ 3 ) to standard<br />

notation (.00236)<br />

71


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Scientific Notation is a special type of exponent expression: the base<br />

is always 10 and it is raised to a positive or negative power.<br />

A number written in scientific notation consists of four parts:<br />

i. 4.95 X 10¯²<br />

a number (n) greater than or equal to 1 and less than 10<br />

ii. 4.95 X 10¯²<br />

iii. 4.95 X 10¯²<br />

iv. 4.95 X 10¯²<br />

a multiplication sign<br />

the base, which is always 10<br />

a positive or negative exponent<br />

72


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Examples Correct Scientific Notation? Why?<br />

4.5 x 10 13<br />

45.6 x 10 -8<br />

Yes<br />

No<br />

1 ≤ n < 10<br />

n > 10<br />

Remember: For an expression to be written in correct scientific<br />

notation, the number (n) that appears before the base must be greater<br />

or equal to 1 and less than 10.<br />

On Your Own: Check all expressions in correct scientific notation:<br />

3.2 X 10 13<br />

23.6 X 10 12<br />

5.788 X 10³<br />

5.788 X 10¯³ 57.88 X 10² 2.36 X 10³<br />

2.36 X 10² 0. 0236 X 10 8 0. 236 X 10 7<br />

2.3 X 10 7 2. 3 X 10¯³ ` 0.23 X 10¯²<br />

73


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Converting to Scientific Notation:<br />

Example: Write in scientific notation: 3,860,000<br />

(1) Convert to a number between 1 and 10.<br />

How: Place decimal point such that there is one non-zero digit to the<br />

left of the decimal point: 3.86<br />

(2) Multiply by a power of 10:<br />

How: Count number of decimal places that the decimal has "moved"<br />

from the original number. This will be the exponent of the 10.<br />

3 8 6 0 0 0 0<br />

6 5 4 3 2 1<br />

We have moved 6 places so the number (3.86) is multiplied by 10 6<br />

(3) If the original number was less than 1, the exponent is negative; if<br />

the original number was greater than 1, the exponent is positive.<br />

3,860,000 > 1, so the exponent is positive.<br />

Answer: 3.86 X 10 6<br />

74


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

On Your Own: Express in correct scientific notation:<br />

Standard Form Scientific Notation<br />

39,400<br />

0.0000394<br />

394<br />

39,400,000<br />

39.4<br />

0.394<br />

3,940<br />

0.00394<br />

3.94<br />

0.000394<br />

Place the following numbers in order, from smallest to largest:<br />

3.35 X 10 0 , 7.4 X 10 -2 , 1.6 X 10 -1 , 4.33 X 10 3 , 7.45 X 10 -3<br />

________ ________ ________ ________ _________<br />

75


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Converting from Scientific Notation to Standard Form:<br />

A. Positive Exponents<br />

• If exponent is positive, move decimal point to the right.<br />

• The exponent will determine how many decimals to move.<br />

Example: 3.45 X 10² = 345 (Move to the right 2 places)<br />

B. Negative Exponents<br />

• If exponent is negative, move decimal point to the left.<br />

• The exponent will determine how many decimals to move.<br />

Example: 3.45 X 10¯² = .0345 (Move to the left 2 places)<br />

On Your Own: Express in standard form:<br />

a. 3.45 x 10 -8<br />

• Since the exponent is negative, we move to the left.<br />

• Since the exponent is 8, we move to the left 8 places.<br />

Answer: ________________________________<br />

b. 5.3 X 10³ ______________<br />

c. 3. 5.3 X 10¯³ ______________<br />

d. 7.98 X 10¯ 4 ________________<br />

e. 7.98 X 10 5 ___________________<br />

76


Unit Review<br />

1. (3)¯² = _____<br />

2. (-3)² = _____<br />

3. -(3)² = _____<br />

3. (-3) 1 = _____<br />

4. (3) 1 = _____<br />

5. (3)¯ 1 = _____<br />

6. (3) 0 = _____<br />

7. (-3) 0 = _____<br />

8. -(3) 0 = _____<br />

9. 3 X 3 = _____<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

77


10. (3 1 )² = _____<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

11. 3 ● 10¯= _____<br />

12. 3¯ ● 3= _____<br />

13. 3 3 ● 3 -6 = _____<br />

14.<br />

15.<br />

16.<br />

3 64 = _____<br />

4 16 = _____<br />

25<br />

= _____<br />

100<br />

17. 4 4 X 4 0 = _____<br />

−6<br />

3<br />

18. = _____<br />

−8<br />

3<br />

19. 4 -4 X 4 4 = _____<br />

78


CAHSEE on Target<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

20. Which shows the number 34,600,000 written in scientific<br />

notation?<br />

A. 346 X 10 5<br />

B. 34.6 X 10 6<br />

C. 3.46 X 10 7<br />

D. 3.46 X 10 -7<br />

E. 0.346 X 10 -8<br />

5<br />

3<br />

21. = _____<br />

− 1<br />

3<br />

3<br />

22. 1<br />

3<br />

−<br />

5<br />

= _____<br />

4<br />

4<br />

23. = _____<br />

− 1<br />

4<br />

−5<br />

4<br />

25. = _____<br />

−3<br />

4<br />

26. 5 3 ● 5 -2 = _____<br />

79


CAHSEE on Target<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Unit Quiz: The following problems appeared on the CAHSEE.<br />

3 ³<br />

1. { } = _______<br />

4<br />

9<br />

A.<br />

12<br />

9<br />

B.<br />

16<br />

27<br />

C.<br />

32<br />

27<br />

D.<br />

64<br />

1<br />

2. Solve for x: x³ =<br />

8<br />

A. x = 2<br />

B. x = 3<br />

1<br />

C. x =<br />

2<br />

1<br />

D. x =<br />

3<br />

3. Which number equals (2)¯ 4<br />

A. -8<br />

1<br />

B. −<br />

16<br />

1<br />

C.<br />

16<br />

1<br />

D.<br />

8<br />

80


4. 10 -2 = _____<br />

10 -4<br />

A. 10¯ 6<br />

B. 10¯²<br />

C. 10²<br />

D. 10<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

5. Between which two integers does 76 lie?<br />

A. 7 and 8<br />

B. 8 and 9<br />

C. 9 and 10<br />

D. 10 and 11<br />

6. The square of a whole number is between 1500 and 1600. The<br />

number must be between:<br />

A. 30 and 35<br />

B. 35 and 40<br />

C. 40 and 45<br />

D. 45 and 50<br />

7. The square root of 150 is between which two numbers?<br />

A. 10 and 11<br />

B. 11 and 12<br />

C. 12 and 13<br />

D. 13 and 14<br />

81


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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

8. The radius of the earth’s orbit is 150,000,000,000 meters. What is<br />

this number in scientific notation?<br />

A. 1.5 X 10¯¹¹<br />

B. 1.5 X 10¹¹<br />

C. 15 X 10¹º<br />

D. 150 X 10 9<br />

9. 3.6 X 10² = ____<br />

A. 3.600<br />

B. 36<br />

C. 360<br />

D. 3,600<br />

10. (3 8 ) 2 = _____<br />

A. 3<br />

B. 3 6<br />

C. 3º<br />

D. 3 6<br />

11. 4³ X 4² = _____<br />

A. 4<br />

B. 4 6<br />

C. 16<br />

D. 16 6<br />

12. (x 2 ) 4 = _____<br />

A. x 6<br />

B. x<br />

C. x 6<br />

D. x²<br />

82


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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Unit 3: Multi-Step Word Problems<br />

Some problems involve more than one step. These are called multistep<br />

problems. On the CAHSEE you can expect to get at least a few<br />

multi-step problems.<br />

Example: The following problem appeared on the CAHSEE.<br />

The five members of a band are getting new outfits. Shirts cost $12<br />

each, pants cost $29 each, and boots cost $49 a pair. What is the<br />

total cost of the new outfits for all the band members?<br />

To solve this kind of problem, we must follow some basic steps:<br />

A. First, determine what the question asks: Total cost for all band<br />

members<br />

B. Write down all of the numerical information given in the problem:<br />

• 5 members in band<br />

• Shirts @ $12 each<br />

• Pants @ $29 each<br />

• Boots @ $49 each<br />

C. Determine the operations required to solve the problem. In other<br />

words, what do we do with all of the numbers listed in step 2?<br />

• Multiply each item bought by 5 since there are 5 members and<br />

each item is required for each member:<br />

Shirts: 12 X 5 = ________<br />

Pants: 29 X 5 = ________<br />

Boots: 49 X 5 = ________<br />

• Add it all up (listing biggest numbers first):<br />

Answer: The total cost of the band’s outfits is _______.<br />

83


On Your Own<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

1. Derrick wants to buy a sweater that costs $46. If he has $22 saved<br />

up and earns $12 a week in allowance, how long will it take before<br />

he has enough money to buy the sweater?<br />

Steps:<br />

A. What does the question ask: _______________________________<br />

______________________________________________________<br />

B. Write down all of the information that is important:<br />

• _______________________<br />

• _______________________<br />

• _______________________<br />

C. Determine the operations required to solve the problem and then<br />

apply these operations to solve the problem.<br />

• The sweater costs $46, but he already has $22. How much more<br />

money does he need? Which operation is required to answer<br />

this question? _________________<br />

Solve:<br />

• Now that we know how much more money Derrick needs, all we<br />

have to do is to figure out how many weeks it will take to earn<br />

this amount. Which operation is required to answer this<br />

question? _____________<br />

Solve:<br />

Answer: Derrick can buy the sweater in ___ weeks.<br />

84


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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

2. Uncle Bernie took his three nieces to the movies. Each niece<br />

ordered a small popcorn, a large soda, and a chocolate bar. If a<br />

small order of popcorn costs $4, a large soda costs $3, and a<br />

chocolate bar costs $1.50, how much did Uncle Bernie spend on<br />

snacks?<br />

3. Cynthia wants to buy a pair of jeans that cost $56, including tax.<br />

If she earns $10.50 each week for allowance and spends $3.50<br />

per week on bus fare to and from her dance lessons, what is the<br />

fewest number of weeks that it will take Cynthia to save enough<br />

money to buy the jeans?<br />

85


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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Extraneous Information<br />

Sometimes there may be information in the problem that you don’t<br />

need. It may be there to confuse you. Whenever you come to<br />

information that is extraneous (i.e., don’t need it, don’t want it),<br />

cross it out:<br />

Example: Daphne, Cynthia, and Rachel went to the movies on<br />

October 21. October 21 fell on a Friday. The movie began at 8:00<br />

p.m. They each bought a bucket of popcorn and a snickers bar. If<br />

each movie ticket costs $8.00, a bucket of popcorn costs $4.00, and a<br />

snickers bar costs $2.50, how much money did they spend altogether?<br />

Steps:<br />

• Cross out any information that you don’t need. Don’t just ignore it<br />

- - cross it out.<br />

Daphne, Cynthia, and Rachel went to the movies on October 21.<br />

October 21 fell on a Friday. The movie began at 8:00 p.m. They each<br />

bought a bucket of popcorn and a snickers bar. If each movie ticket<br />

costs $8.00, a bucket of popcorn costs $4.00, and a snickers bar costs<br />

$2.50, how much money did they spend altogether?<br />

• Write down all of the information that is important:<br />

3 people<br />

Tickets $8.00 each<br />

Popcorn $4.00 each<br />

Snickers $2.50 each<br />

• Figure out how much one person spent:<br />

8 + 4 + 2.50 = ______<br />

• Figure out how much all three people spent:<br />

_____ ● 3 = _____<br />

86


On Your Own<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

1. Matthew bought a used car for $800. The car was 15 years old. He<br />

wrote a check for $520 and gave the salesman $125 in cash. The<br />

rest he promised to pay at the end of the week, when he would be<br />

receiving a paycheck for $385. How much does he owe on the car?<br />

• Cross out any information that you don’t need. Don’t just<br />

ignore it - - cross it out. That way you will be sure that you<br />

don’t accidentally slip it in later.<br />

• Now write down all of the information that is important:<br />

_____________________________________________<br />

_____________________________________________<br />

_____________________________________________<br />

• How much did Matthew already pay? ____________<br />

• How much more does he owe? _________<br />

2. Mrs. Brown took her four children out to the pizza party. She and<br />

her children each ordered a small pepperoni pizza and a large soda.<br />

A small vegetarian pizza costs $4.50, while a small pepperoni pizza<br />

costs $5.25. Small sodas cost $2.00, medium sodas cost $2.50,<br />

and large sodas cost $3.25. How much did Mrs. Brown spend at<br />

the pizza party?<br />

87


Unit Quiz<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

1. Martine bought 3 cans of soda for 65¢ each, 2 pretzels for $1.25<br />

each and a slice of pizza for $1.75. She paid with a $20 bill. How<br />

much change should she get back from the cashier?<br />

2. Joy spent 25% of her weekly paycheck to help her sister buy a new<br />

dress. If the dress costs $235 and her paycheck is $450, how<br />

much does she have left for the week?<br />

3. If it costs $150 to feed a family of four for the week, how much will<br />

it cost to feed a family of six?<br />

4. Adrienne has $166 left in her checking account and $1300 in her<br />

savings account. Each week she earns $175 as a cashier at the<br />

Five and Dime Store. She is planning on buying a set of dishes for<br />

her best friend’s wedding shower. The set costs $500. If she does<br />

not take any money out of her savings account, what is the fewest<br />

number of weeks that she must work in order to buy the dishes?<br />

88


Unit 4: Percent<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

On the CAHSEE, you will have many problems that involve percent.<br />

(Note: Some of these will be word problems.)<br />

Percent of a <strong>Number</strong><br />

Percent, written as %, literally means "out of 100." Any number<br />

expressed as a percent stands for a fraction.<br />

Example: Five percent (or 5%) means 5 out of 100. As a fraction,<br />

this is written as 5/100, which can be reduced to 1/20. This can<br />

also be expressed as a decimal: .05 (read as five hundredths).<br />

Example: Seventy-five percent (75%) means 75 out of 100, or<br />

75/100. This fraction can be reduced to 3/4. As a decimal, 75%<br />

would be written as 0.75, which means 75 hundredths.<br />

Converting from Percent to Decimal<br />

To change a percent to a decimal, divide the percent value by 100:<br />

move the decimal point two places to the left.<br />

Examples:<br />

17% = .17<br />

3% = .03<br />

80% = .80 (or .8)<br />

125% = 1.25<br />

.8% = .008<br />

3.4% = .034<br />

46% = 0.46<br />

89


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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Converting from Decimal to Percent<br />

To change a decimal to a percent, move the decimal point two places<br />

to the right. (Multiply by 100!)<br />

Examples:<br />

.34 = 34% .09 = 9% 2.3 = 230% .6 = 60% 0.125 = 12.5%<br />

Practice: Fill in the following chart. Reduce fractions to lowest terms.<br />

Fraction Decimal Percent<br />

9<br />

100<br />

9<br />

10<br />

1<br />

4<br />

0.08<br />

0.8<br />

0.84<br />

35%<br />

95%<br />

60%<br />

90


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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Solving Percent Problems<br />

There are two methods for solving percent problems. The first is<br />

setting up a proportion.<br />

Method 1: Proportion<br />

A proportion is two equivalent ratios, written as fractions. In<br />

any proportion, the product of the means is equal to the product<br />

of the extremes:<br />

We see that this is true: 3 ● 10 = 30 and 5 ● 6 = 30<br />

The product of the means is equal to the product of the extreme.<br />

We can solve a percent problem by setting up a proportion. Here is<br />

the proportion used to solve percent problems:<br />

Part x<br />

=<br />

Whole 100<br />

This proportion may be translated as follows: The part is to the whole<br />

as what number is to 100?"<br />

And, since in a proportion, the product of the means is equal to the<br />

product of the extremes, the following is also true:<br />

Whole ● x = Part ● 100<br />

This relationship will always be true for a proportion. Since we<br />

multiply diagonally across the proportion, people often use the term<br />

"cross multiplying" for short (since it can be encumbering to keep<br />

saying, "The product of the means is equal to the product of the<br />

extremes." You can use the term "cross-multiplication" if you like;<br />

just remember the concept that is behind it.<br />

91


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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Let's solve a percent problem together, using the proportion method:<br />

Example: 23 is what percent of 50?<br />

23 x<br />

=<br />

50 100<br />

50x = 2300 ← ⎯⎯ Now divide to solve for x.<br />

x = ___<br />

23<br />

Answer: is equal to ___%<br />

50<br />

On Your Own: Use the method of cross multiplication to solve for x.<br />

x 5<br />

1. =<br />

20 100<br />

92


4 x<br />

2. =<br />

25 100<br />

18 x<br />

3. =<br />

20 100<br />

7 x<br />

4. =<br />

10 100<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

93


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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Let's look at more examples of percent problems solved with the<br />

proportion method:<br />

Example: 18 is what percent of 50?<br />

• Set up a proportion:<br />

Part x<br />

=<br />

Whole 100<br />

Note: The term 50 is the "whole" and 18 is the "part":<br />

18 x<br />

Proportion: =<br />

50 100<br />

• Cross multiply: 50x = 1800<br />

1800<br />

• Isolate x by dividing by 50: x = = ____<br />

50<br />

Example: What is 25% of $60?<br />

x 25<br />

• Set up a proportion: =<br />

60 100<br />

Note: The term 60 is the "whole" and the problem asks for 25%<br />

of this whole:<br />

• Cross multiply: 100x = 1500<br />

1500<br />

• Find x: x = = -----<br />

100<br />

94


On Your Own<br />

CAHSEE on Target<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

1. 25% of what number is 15?<br />

15 25<br />

• Set up a proportion: =<br />

x 100<br />

Note: The term 15 is the "part" and the problem asks for 25% of<br />

the whole:<br />

• Cross multiply: __________________<br />

• Find x: _______________________<br />

2. 30 is what percent of 50?<br />

3. What is 45% of 90?<br />

4. 30% of what number is 60?<br />

95


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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Method 2: Translate & Compute<br />

In this method, we translate the problem into an algebraic equation<br />

and then solve. Let's look at the previous problems again, this time<br />

using this second method:<br />

Example: 18 is what percent of 50?<br />

• Translate:<br />

18 is what percent of 50?<br />

x<br />

18 = ● 50<br />

100<br />

50x<br />

• Compute: 18 =<br />

100<br />

18 = 1 50x ← ⎯⎯ Simplify all fractions<br />

2100<br />

x<br />

18 =<br />

2<br />

18 ● 2 = x ● 2 1 ← ⎯⎯ Multiply both sides by 2.<br />

12<br />

x = ___ Answer: 18 is __% of 50.<br />

Note: This method can also be used as a complement to Method 1<br />

and as way to verify the answers you arrived at using Method 1.<br />

96


On Your Own<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

1. What is 25% of $60?<br />

• Translate:<br />

What is 25 percent of 60?<br />

___ ___ ____ ___ ___<br />

• Compute:<br />

2. 25% of what number is 15?<br />

• Translate:<br />

25 percent of what number is 15?<br />

____ ___ ___ ___ ___<br />

• Compute:<br />

97


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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

3. 15% of what number is 30?<br />

4. 35 is what percent of 80?<br />

5. What is 15% of 90?<br />

6. 15 is what percent of 80?<br />

98


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Practice: Use either method to solve the percent problems below.<br />

1. On average, every 16 out of 200 students study Calculus. What<br />

percent study Calculus?<br />

2. If 150 people were surveyed in the 2004 presidential elections and<br />

90 of those people said that they were going to vote for John Kerry,<br />

find the percent of Kerry supporters in the sample population?<br />

3. The Brighton Movie Theater sells the following candies at their<br />

snack bar: Snickers Candy Bars, Peanut Clusters, O’Henry Bars,<br />

M & M’s, and Milky Way Bars. Currently, there are 10,000 candies<br />

in stock. The following chart below shows a percentage breakdown<br />

of each type of candy in stock. Find the actual number of each type<br />

of candy:<br />

Candy <strong>Number</strong><br />

Snickers: 5%<br />

Peanut Clusters: 15%<br />

O’Henry: 20%<br />

M & M’s: 25%<br />

Milky Way Bars: 35%<br />

4. What is the fractional equivalent of 95% (reduced to lowest terms)?<br />

99


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UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

5. Four months of the year have 30 days. Which percentage most<br />

closely represents the months that do not have 30 days?<br />

A. 33%<br />

B. 44%<br />

C. 66%<br />

D. 75%<br />

12<br />

6. What is the percentage equivalent of ?<br />

15<br />

7. In Mr. Martin’s class, 9 of the 27 students in Mr. Martin’s class<br />

received a B+ or higher on the Algebra quiz. What percent of the<br />

students received a grade of B or lower?<br />

4<br />

8. What is expressed as a percent?<br />

5<br />

9. What is 0.80 expressed as a fraction (in simplest terms)?<br />

100


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Percent Increases & Decrease<br />

Often, when we compare one entity across time (such as changes<br />

in population or the price of a particular item), we express these<br />

changes in terms of percent. The percent of change is the ratio of<br />

the amount of change to the original amount.<br />

Ratio: How much it went up or down<br />

The original amount<br />

An easy way to solve percent increase & percent decrease problems is<br />

to set up a proportion that consists of two ratios, the one above and<br />

a second one for the percent. Remember that “percent” is always a<br />

ratio and the denominator of that ratio is always 100.<br />

What<br />

So the second ratio looks like this:<br />

Percent<br />

x<br />

or<br />

100<br />

If you set up a proportion using these two ratios, you get the<br />

following:<br />

How much it went up or down = x_<br />

The original amount 100<br />

All you need to do after that is cross multiply and isolate the x value.<br />

Let's look at an example on the next page.<br />

101


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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Example: Jimmy got a raise from $6.00 to $8.00 per hour. This<br />

represents a raise of what percent?<br />

Steps:<br />

• Find out how much it went up or down and place this number<br />

over the original amount:<br />

2 ← ⎯⎯ It went up $2<br />

6 ← ⎯⎯ Original amount is $6.00<br />

• Set up proportion:<br />

2 x<br />

=<br />

6 100<br />

• Cross multiply:<br />

• Solve for x:<br />

• Express answer as a percent: _________<br />

Make sure you use the original amount as the denominator!<br />

102


Alternative Method<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

You can also solve the previous problem by setting up an equation:<br />

Change = What Percent of Original Amount<br />

Let's look at the problem again:<br />

Example: Jimmy got a raise from $6.00 to $8.00 per hour. This<br />

represents a raise of what percent?<br />

Now plug the values in the equation:<br />

Change = What Percent of Original Amount<br />

x<br />

2 = ● 6<br />

100<br />

Now solve:<br />

x<br />

2 = (6)<br />

100<br />

103


On Your Own<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

1. Tasty Delight raised their prices on ice cream sundaes from $5.00<br />

to $7.00. This represents an increase of what percent?<br />

x<br />

• Set up proportion: ____=<br />

100<br />

• Cross multiply: _________________<br />

• Solve for x: _____________________<br />

• Express answer as a percent: ________<br />

Note: Be sure to use the original amount as the denominator!<br />

Now solve the above problem using the alternative method:<br />

Plug in values:<br />

Change = What Percent of Original Amount<br />

____ ____ ___ ______<br />

Solve:<br />

104


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

2. A shirt that costs $40 in 1999 costs $60 in 2005. What is the<br />

percent increase? (Use either method to solve.)<br />

Solve:<br />

Percent Increase: _______________<br />

What would be a trick answer on the CAHSEE? _____________<br />

3. Elizabeth’s basketball card collection increased in value from $500<br />

to $1,000. What is the percent increase? (Use either method to<br />

solve.)<br />

Solve:<br />

Percent Increase: _______________<br />

What would be a trick answer on the CAHSEE? ____________<br />

105


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

4. Jordy’s basketball card collection decreased in value from $1,000 to<br />

$500. What is the percent decrease?<br />

Solve:<br />

Percent Decrease: ____________________<br />

What would be a trick answer on the CAHSEE? _______________<br />

5. Last year Andrea had 36 students in her class. This year she only<br />

has 27. What is the percent decrease?<br />

Solve:<br />

Percent Decrease: ______________________<br />

What would be a trick answer on the CAHSEE? _______________<br />

6. If a shirt that costs $80 last year is worth only 75% as much this<br />

year, what is the current value of the shirt?<br />

Solve:<br />

Answer: _________<br />

106


Price Discounts<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Stores will often sell items for a discounted sales price. The store will<br />

discount an item by a percent of the original price. To find the amount<br />

of a discount (in dollars), simply multiply the original price by the<br />

percent discount.<br />

Example: An item, which originally cost $20, was discounted by 25%.<br />

Find the discount in dollars?<br />

Steps:<br />

• Translate the problem into math:<br />

25<br />

25% of $20 = ● 20<br />

100<br />

• Calculate:<br />

25<br />

● 20 = $5.00 (or ¼ ● 20 = 5)<br />

100<br />

The item was sold for $5.00 less than its original price.<br />

Terms you may see for discounted items:<br />

• 50% Off<br />

• Save 50%<br />

• Discounted by 50%<br />

107


On Your Own<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

1. A transistor radio is normally sold for $80 at Karter Electric Goods.<br />

This week, it is being offered at a 20% discount. How much<br />

cheaper is the radio this week?<br />

2. A dress, which sold for $80 last week, is on sale for 20% off. This<br />

represents a discount of how much (in dollars)?<br />

3. At Peppy’s Pizza, a small pepperoni pizza normally sells for $6.00.<br />

This week, the store is offering a 25% discount on all small pizzas.<br />

How much cheaper is the pizza this week?<br />

108


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Note: Many price discount questions on the CAHSEE ask you to find<br />

the new price, not the amount of discount. This involves one<br />

more important step.<br />

Example: An item originally cost $20 and was discounted by 25%.<br />

What was the new sales price?<br />

Steps:<br />

25<br />

• Translate the problem into math: 25% of $20 = ● 20<br />

100<br />

• Calculate the discount in dollars:<br />

25<br />

● 20 = $5.00 (or ¼ ● 20 = 5)<br />

100<br />

The item was sold for $5.00 less than its original price.<br />

• Finally, to find the new sales price, subtract the amount of discount<br />

from the original price:<br />

$20.00-$5.00=$15.00<br />

CAHSEE Alert! Don’t forget this last step. If this were an actual item<br />

on the exam, $5.00 (the amount of discount) would probably be one of<br />

the answer choices. If you are working out a problem that has multiple<br />

steps, remember to do all of the steps to get the right answer.<br />

109


On Your Own<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

1. A dress, which sold for $80 last week, is on sale for 20% off. What<br />

is the new price of the dress?<br />

Solve:<br />

New Price: ________<br />

What would be a trick answer on the CAHSEE? ____________<br />

2. At Peppy’s Pizza, a small pepperoni pizza normally sells for $6.00.<br />

This week, the store is offering a 25% discount on all small pizzas.<br />

How much does a small pepperoni pizza cost this week?<br />

Solve:<br />

New Price: ________<br />

What would be a trick answer on the CAHSEE? ___________<br />

3. Rain boots regularly sell for $70 a pair. They are currently on sale<br />

for 40% off. What is the sale price of the boots?<br />

Solve:<br />

New Price: ________<br />

What would be a trick answer on the CAHSEE? ___________<br />

110


Markups<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Stores buy items from a wholesaler or a distributor and increase the<br />

price when they sell them to consumers. The increase in price provides<br />

money for the operation of the store and the salaries of people who<br />

work in the store. A store may have a rule that the price of a certain<br />

type of item needs to be increased by a certain percentage. This<br />

percentage is called the markup.<br />

A. Two-Step Method<br />

1. Find the markup in dollar amount:<br />

Original Cost ● Percent of Markup<br />

2. Add this dollar amount to the original price.<br />

Markup in $ + Original Price<br />

Example: A merchant buys an item for $4.00 and marks it up by<br />

25%. How much does he charge for the item?<br />

1. Find the markup in dollars:<br />

$4.00 ● .25 = $1.00 Or . . .<br />

1<br />

4 ● = 1<br />

4<br />

2. Add this dollar amount to the original price:<br />

$4.00 + 1.00 = $5.00<br />

CAHSEE Alert! Like the discount problems, be careful not to forget<br />

the last step. In the above problem, a probable answer choice would<br />

be $1.00. Don’t be fooled! Read the question carefully.<br />

111


CAHSEE on Target<br />

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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

B. One-Step Method<br />

A faster way to calculate the sales price is to make the original cost<br />

equal to 100%.<br />

Example: A merchant buys an item for $4.00 and marks it up by<br />

25%. How much does he charge for the item?<br />

Since the markup is 25%, the customer pays 125% of the original<br />

cost. Multiply the original cost by 125% (or 1.25):<br />

$4.00 ● 1.25 =<br />

(4 ● 1) + (4 ● .25) =<br />

4 + 1 = $5.00 The merchant charges $5.00 for the item.<br />

CAHSEE Alert! Some questions on the CAHSEE may ask for the<br />

dollar amount of the markup, not the final sales price.<br />

Example: Harry’s Bargain Basement has a 20% markup on all its<br />

goods. If the manufacturer price of irons is $16, how much extra<br />

does the customer pay for each iron?<br />

Solve: _____________________________________________<br />

Compare with this problem:<br />

Harry’s Bargain Basement has a 20% markup on all its goods. If the<br />

manufacturer price of irons is $16, how much does the customer pay<br />

for an iron?<br />

Solve: _____________________________________________<br />

Note: On the CAHSEE, be sure to read the question carefully to<br />

determine whether it is asking for the markup or final sales price.<br />

112


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

On Your Own: Read each problem carefully and determine what the<br />

question is asking. Then solve the problem.<br />

1. The original cost of a dress is $12.00. (This is the amount that the<br />

store paid the manufacturer.) The store marks up all their items by<br />

20%. How much does the store charge for the dress?<br />

2. Bill’s Auto Supplies buys tires for $80. If the store sells its tires for<br />

$100, what is its percent markup?<br />

3. All items at Bargain Slim’s have been marked up by 40%. If the<br />

store paid $12 for each CD, how much does the customer pay?<br />

4. A stainless steel refrigerator is bought for $500 and then marked up<br />

by 100%. What is the new price of the refrigerator?<br />

113


Commissions<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Sales commissions are often paid to employees who sell merchandise<br />

or products. Commissions serve to motivate salespersons to sell a lot.<br />

A commission is generally a percentage of the total sales made by<br />

a salesperson. To find the commission, just multiply the value of<br />

the total sales by the commission rate. It is that simple!<br />

Example: A salesman receives a 10% commission on all sales. If he<br />

sells $1500 worth of merchandise, how much does he earn in<br />

commission?<br />

$1,500 X 0.10 = $150<br />

or<br />

$1500 X 10_ = 15 X 10 = $150<br />

100<br />

On Your Own<br />

1. Sarah is a real estate agent. She earns 12% commission on every<br />

house she sells. Sarah recently sold a house for $400,000. What<br />

was her commission?<br />

2. Ronald is a salesman in the men’s department at Bloomingdale’s<br />

Department Store. He earns 15% on all sales. His total sales for<br />

the month of August came to $80,000. How much did he earn in<br />

commission?<br />

7. Alvin Ray sells used cars at Kaplan’s Auto Dealer. His commission<br />

rate is 30%. What was his commission on the used Audi he sold for<br />

$36,000?<br />

114


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Unit Quiz: The following questions appeared on the CAHSEE.<br />

1. At a recent school play, 504 of the 840 seats were filled. What<br />

percent of the seats were empty?<br />

A. 33.6%<br />

B. 40%<br />

C. 50.4%<br />

D. 60%<br />

2. Some of the students attend school 180 of the 365 days in a year.<br />

About what part of the year do they attend school?<br />

A. 18%<br />

B. 50%<br />

C. 75%<br />

D. 180%<br />

3. What is the fractional equivalent of 60%?<br />

1<br />

A.<br />

6<br />

3<br />

B.<br />

6<br />

3<br />

C.<br />

5<br />

2<br />

D.<br />

3<br />

115


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

4. If Freya makes 4 of her 5 free throws in a basketball game, what is<br />

her free throw shooting percentage?<br />

A. 20%<br />

B. 40%<br />

C. 80%<br />

D. 90%<br />

5. Between 6:00 AM and noon, the temperature went from 45° to 90°.<br />

By what percentage did the temperature increase between 6:00 AM<br />

to noon?<br />

A. 45%<br />

B. 50%<br />

C. 55%<br />

D. 100%<br />

6. The price of a calculator has decreased from $12.00 to $9.00.<br />

What is the percent of decrease?<br />

A. 3%<br />

B. 25%<br />

C. 33%<br />

D. 75%<br />

7. The cost of an afternoon movie ticket last year was $4.00. This<br />

year an afternoon movie ticket costs $5.00. What is the percent<br />

increase of the ticket from last year to this year?<br />

A. 10%<br />

B. 20%<br />

C. 25%<br />

D. 40%<br />

116


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

8. A pair of jeans regularly sells for $24.00. They are on sale for 25%<br />

off. What is the sales price of the jeans?<br />

A. $6.00<br />

B. $18.00<br />

C. $20.00<br />

D. $30.00<br />

9. A CD player regularly sells for $80. It is on sale for 20% off. What<br />

is the sales price of the CD player?<br />

A. $16<br />

B. $60<br />

C. $64<br />

D. $96<br />

10. Mr. Norris is paid a 5% commission on each house that he sells.<br />

What is his commission on a house that he sells for $125,000?<br />

A. $625<br />

B. $6,250<br />

C. $62,500<br />

D. $625,000<br />

117


Unit 5: Interest<br />

CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

On the CAHSEE, you may be asked several questions on interest.<br />

These questions will cover both simple interest and compound interest.<br />

Introduction to Interest<br />

Did you know that money can make more money? Whenever money is<br />

invested or borrowed, additional funds, called interest, are<br />

charged for the use of that money for a certain period of time. When<br />

the money is paid back, both the principal (amount of money that<br />

was borrowed) and the interest are due.<br />

If you invest money in the bank, the bank is borrowing the money and<br />

the interest is paid to you. On the other hand, when you take out a<br />

loan, you are borrowing the money and you must pay the interest.<br />

Interest can be simple or compound:<br />

Simple interest is generally used when borrowing or investing money<br />

for short periods of time.<br />

Compound interest is generally used when borrowing or investing<br />

money for longer periods of time. We will learn about compound<br />

interest later.<br />

Interest depends on three things:<br />

1. Principle (P): The amount you invest or borrow; principle is<br />

expressed in dollars.<br />

2. Interest Rate (R): How much it costs you to borrow the money or<br />

how much you gain by investing your money; this rate is always<br />

expressed as a percent in the problem, although you may convert<br />

the rate to a decimal during computation.<br />

3. Time (T): How long you borrow the money or how long you invest<br />

your money; this time is always expressed in number of years<br />

118


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Converting to Years<br />

When calculating interest, time is expressed in years. If the period<br />

of time is given in months, you must first convert it to the number of<br />

years.<br />

Examples:<br />

1<br />

6 months is year, or .5 year.<br />

2<br />

3<br />

18 months is years, or 1.5 years.<br />

2<br />

Working with Improper Fractions<br />

We will see that, when calculating interest, it is easiest to work with<br />

improper fractions than with mixed numbers.<br />

Mixed <strong>Number</strong>s: A mixed number consists of both a whole integer<br />

and a fraction.<br />

1<br />

1 is a mixed number because it consists of a whole number (1) and<br />

4<br />

1<br />

a fraction .<br />

4<br />

Improper Fractions: An improper fraction is one in which the<br />

numerator is greater than the denominator.<br />

4<br />

5 is an improper fraction because the numerator (5) is greater than<br />

the denominator (4).<br />

119


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Converting Mixed <strong>Number</strong>s to Improper Fractions<br />

To convert a mixed number to an improper fraction, follow these<br />

steps:<br />

• Multiply the whole number by the denominator of the fraction.<br />

• Add the numerator of the fraction to the product found above.<br />

• Place the result over the fraction's denominator.<br />

1<br />

Example: Convert 1 to an improper fraction.<br />

4<br />

• Multiply the whole number by the denominator of the fraction:<br />

1 ● 4 = 4<br />

• Add the numerator of the fraction to the product found in Step 1:<br />

4 + 1 = 5<br />

• Place the result over the fraction's denominator:<br />

5<br />

4<br />

3<br />

On Your Own: Convert 1 to a mixed fraction.<br />

5<br />

120


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Practice: Express each time interval below in years. Express as both<br />

a fraction (reduced to lowest terms) and a decimal.<br />

Note: Be sure to covert any mixed number to an improper fraction.<br />

Months Years: Fraction Years: Decimal<br />

3 months<br />

4 months<br />

8 months<br />

27 months<br />

15 months<br />

9 months<br />

21 months<br />

1 year and 8<br />

months<br />

121


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Converting to Percents & Decimals<br />

The interest rate is expressed as a percent or as a decimal.<br />

Examples:<br />

5<br />

5% = = 0.05<br />

100<br />

8.<br />

5<br />

8½% =<br />

100<br />

= 0.085<br />

x<br />

On Your Own: Express as both a percent ( ) and a decimal.<br />

100<br />

Rate Percent Decimal<br />

12%<br />

20%<br />

3%<br />

18%<br />

9½%<br />

12½%<br />

122


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Solving Simple Interest Problems<br />

To solve simple interest problems, just apply the formula:<br />

Principle ● Rate ● Time<br />

We can abbreviate this as follows: P ● R ● T<br />

Note: Be sure to learn this formula for the CAHSEE!<br />

One Step-Problems<br />

One-step problems ask you to find the interest (in dollars and cents)<br />

earned (from an investment) or owed (on a loan). Just apply the<br />

formula for interest:<br />

One-step problems ask you to find the interest (in dollars and cents)<br />

earned (from an investment) or owed (on a loan). Just apply the<br />

formula for interest:<br />

Principle ● Rate ● Time<br />

Note: Be sure to convert all terms to their correct units:<br />

• Rate in % or decimal<br />

• Time in years<br />

Example: $500 invested for 6 months in an account paying 7%<br />

interest. How much is earned in interest?<br />

To solve, simply plug the correct values into the equation and do the<br />

computation:<br />

Principle ● Rate ● Time<br />

$500 ● 0.07 ● 0.5 = _______ OR<br />

500 ● 7_ ● 1 = ______<br />

100 2<br />

123


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Fractions and Interest Problems<br />

As we mentioned earlier, when solving interest problems, it is easier to<br />

work with improper fractions than with mixed numbers.<br />

Example: Shawn invests $4,000 at 16%. How much does he earn in<br />

15 months?<br />

Let's solve this problem by expressing 15 months as an improper<br />

fraction. (Note: It is much easier to multiply with improper fractions<br />

than with mixed numbers.)<br />

There are 12 months in 1 year; we have 15 months:<br />

15<br />

← ⎯⎯ Improper fraction: Denominator > numerator<br />

12<br />

15 5<br />

We can reduce this fraction: =<br />

12 4<br />

Now let's solve the problem:<br />

P ● R ● T<br />

4000 ● 16 ● 5 =<br />

100 4<br />

4,000 ● 4 16 ● 5 =<br />

100 41<br />

40 ● 20 = ____<br />

124


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

On Your Own: Plug the correct values and solve:<br />

1. $1,500 is borrowed at an interest rate of 3 percent for 20 years.<br />

How much is earned in interest?<br />

P = __________<br />

R = __________<br />

T = __________<br />

P ● R ●T = _______________________________<br />

2. $5,000 is invested for 24 months in an account paying 6% interest.<br />

How much is earned in interest.<br />

P = __________<br />

R = __________<br />

T = __________<br />

P ● R ●T = _______________________________<br />

3. Drew earns 6% in simple interest. If he invests $8,000 in a bank<br />

account, how much interest will he have earned after 18 months?<br />

Note: In each of the above questions, we are asked to find the<br />

interest earned, rather than the value of the entire investment. We will<br />

now learn to add the interest to the principle.<br />

125


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Two-Step Problems<br />

On the CAHSEE, you may be asked to find the value of the entire<br />

investment. For these problems, there is one additional step.<br />

Example: Marianne invested $5,000 in the bank at an annual interest<br />

rate of 8 ½ percent. How much will her investment be worth in two<br />

years?<br />

• Find the amount of interest earned:<br />

P ● R ● T<br />

8.<br />

5<br />

5,000 ● ● 2 = _______________________<br />

100<br />

• Add the interest to the principle to get the value of the investment:<br />

5,000 + _______ = $ ________<br />

On Your Own:<br />

1. Rachel invests $3,000 at 12%. How much will her investment be<br />

worth in 15 months?<br />

• Plug the values into the formula and compute interest earned:<br />

• Add interest to principal:<br />

3000 + ___ = ____<br />

126


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

2. Amy has a bank account that pays an annual interest rate of 7%<br />

(simple interest). If she has $7,000 in principal, how much interest<br />

will she earn this year?<br />

3. Denise earns 8% in simple interest each year. If she now has $900<br />

in her savings account, what will be the value of her savings<br />

account in six months?<br />

4. Emily has invested $15,000 at Chase Manhattan Bank. If her<br />

current rate of interest is 8%, how much interest will she have<br />

earned in nine months?<br />

5. Refer back to the previous problem. What will be the total value of<br />

Emily’s investment after nine months?<br />

127


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Compound Interest<br />

While simple interest is paid once per year, compound interest can be<br />

paid twice a year (semi-annually), four times a year (quarterly) or<br />

even monthly!<br />

Example: Peter invests $500 in a savings account. The bank pays<br />

10% annual interest, compounded twice a year. What is the value of<br />

Peter’s investment after one year?<br />

Steps:<br />

• How much does Peter earn after 6 months? Not 10% because that<br />

is what he earns annually. 10% annual interest compounded twice<br />

a year means that half of the interest is paid after 6 months (half of<br />

the year) and the other half is paid at the end of the year. Since six<br />

months is one-half of a year, Peter only earns half of 10%, or 5%,<br />

after six months.<br />

Calculate 5% of $500: _5 ● 500 = $25.<br />

100<br />

• Add this to the principle to find the total value of his investment<br />

after six months:<br />

$500 + $25 = $525<br />

• For the next six months, Peter will earn 5% on $525. Calculate the<br />

interest:<br />

5% ● ____ = ______<br />

• Add this amount to the value of his investment after one year:<br />

______ + _____ = ________<br />

128


CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

CAHSEE Tip: Since the math section of the CAHSEE uses a multiple-<br />

choice format, you can automatically rule out certain choices on<br />

compound interest problems:<br />

• We know that compound interest is always greater than simple<br />

interest; therefore, you can cross out any answers that are less<br />

than or equal to the amount calculated for simple interest.<br />

• At the same time, the answer will be only slightly greater than<br />

the amount obtained under simple interest since CAHSEE compound<br />

interest problems will generally be limited to one year (the<br />

difference between the interest earned under simple and compound<br />

interest gets bigger with each year); therefore, you can cross out<br />

answers that are significantly greater than that obtained under<br />

simple interest.<br />

See if you can apply this strategy for the following two problems.<br />

1. Ellie invested $3,000 in a savings account that pays an annual<br />

interest rate of 6% compounded twice a year. How much will she<br />

have in the bank after one year?<br />

A. $3,000.00<br />

B. $3,180.00<br />

C. $3,182.70<br />

D. $3,600<br />

2. Drew has invested $10,000 at Bank of America. His current rate of<br />

interest is 5%, compounded twice a year. How much interest will he<br />

have earned in one year?<br />

A. $10, 756.25<br />

B. $10,506.25<br />

C. $10,256.25<br />

D. $10,500<br />

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CAHSEE on Target<br />

UC Davis, School/University Partnerships<br />

Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />

Unit Quiz: The following questions appeared on the CAHSEE.<br />

1. Sally puts $200 in a bank account. Each year the account earns<br />

8% simple interest. How much interest will she earn in three<br />

years?<br />

A. $16.00<br />

B. $24.00<br />

C. $48.00<br />

D. $160.00<br />

2. Mr. Yee invested $2000 in a savings account that pays an annual<br />

interest rate of 4% compounded twice a year. If Mr. Yee does not<br />

deposit or withdraw any money, how much will he have in the bank<br />

after one year?<br />

A. $2,080.00<br />

B. $2,080.80<br />

C. $2,160.00<br />

D. $2,163.20<br />

Note: See if you can solve this problem by applying the multiplechoice<br />

strategy for compound interest problems.<br />

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