Number Sense
Number Sense
Number Sense
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CAHSEE on Target<br />
UC Davis, School and University Partnerships<br />
CAHSEE on Target<br />
Mathematics Curriculum<br />
Published by<br />
The University of California, Davis,<br />
School/University Partnerships Program<br />
2006<br />
Director<br />
Sarah R. Martinez, School/University Partnerships, UC Davis<br />
Developed and Written by<br />
Syma Solovitch, School/University Partnerships, UC Davis<br />
Editor<br />
Nadia Samii, UC Davis Nutrition Graduate<br />
Reviewers<br />
Faith Paul, School/University Partnerships, UC Davis<br />
Linda Whent, School/University Partnerships, UC Davis<br />
The CAHSEE on Target curriculum was made possible by<br />
funding and support from the California Academic Partnership Program,<br />
GEAR UP, and the University of California Office of the President.<br />
We also gratefully acknowledge the contributions of teachers<br />
and administrators at Sacramento High School and Woodland High School<br />
who piloted the CAHSEE on Target curriculum.<br />
© Copyright The Regents of the University of California, Davis campus, 2005-06<br />
All Rights Reserved. Pages intended to be reproduced for students activities<br />
may be duplicated for classroom use. All other text may not be reproduced in any form<br />
without the express written permission of the copyright holder.<br />
For further information,<br />
please visit the School/University Partnerships Web site at:<br />
http://sup.ucdavis.edu
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Introduction to the CAHSEE<br />
The CAHSEE stands for the California High School Exit Exam. The<br />
mathematics section of the CAHSEE consists of 80 multiple-choice<br />
questions that cover 53 standards across 6 strands. These strands<br />
include the following:<br />
<strong>Number</strong> <strong>Sense</strong> (14 Questions)<br />
Statistics, Data Analysis & Probability (12 Questions)<br />
Algebra & Functions (17 Questions)<br />
Measurement & Geometry (17 Questions)<br />
Mathematical Reasoning (8 Questions)<br />
Algebra 1 (12 Questions)<br />
What is CAHSEE on Target?<br />
CAHSEE on Target is a tutoring course specifically designed for the<br />
California High School Exit Exam (CAHSEE). The goal of the program<br />
is to pinpoint each student’s areas of weakness and to then address<br />
those weaknesses through classroom and small group instruction,<br />
concentrated review, computer tutorials and challenging games.<br />
Each student will receive a separate workbook for each strand and will<br />
use these workbooks during their tutoring sessions. These workbooks<br />
will present and explain each concept covered on the CAHSEE, and<br />
introduce new or alternative approaches to solving math problems.<br />
What is <strong>Number</strong> <strong>Sense</strong>?<br />
<strong>Number</strong> <strong>Sense</strong> is the understanding of numbers and their<br />
relationships. The <strong>Number</strong> <strong>Sense</strong> Strand concepts that are tested on<br />
the CAHSEE can be divided into five major topics: Integers &<br />
Fractions; Exponents; Word Problems; Percents; and Interest. These<br />
topics are presented as separate units in this workbook.<br />
1
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Unit 1: Integers & Fractions<br />
On the CAHSEE, you will be given several problems involving rational<br />
numbers (integers, fractions and decimals).<br />
Integers are whole numbers; they include . . .<br />
• positive whole numbers {1, 2, 3, . . . }<br />
• negative whole numbers {−1, −2, −3, . . . } and<br />
• zero {0}.<br />
Positive and negative integers can be thought of as opposites of one<br />
another.<br />
A. Signs of Integers<br />
All numbers are signed (except zero). They are either positive or<br />
negative.<br />
When adding, subtracting, multiplying and dividing integers, we need<br />
to pay attention to the sign (+ or -) of each integer.<br />
Example: 5 ● -3 = ____<br />
Example: -5 + 4 = ___<br />
Example: -3 ● 12 = ___<br />
Whether it’s written or not, every number has a sign:<br />
Example: 5 means +5<br />
2
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Signed <strong>Number</strong>s in Everyday Life<br />
Signed numbers are used in everyday life to describe various<br />
situations. Often, they are used to indicate opposites:<br />
Altitude: The elevator went up 3 floors (+3) and then went down 5<br />
floors (-5).<br />
Weight: I lost 20 pounds (-20) but gained 10 back (+10).<br />
Money: I earned $60 (+60) and spent $25 (-25).<br />
Temperature: The temperature rose 5 degrees (+5) and then fell 2<br />
degrees (-2).<br />
Sea Level: Jericho, the oldest inhabited town in the world, lies 853<br />
feet below sea level (-853), making it the lowest town on earth.<br />
Mount Everest is the highest mountain in the world, standing at<br />
8850 meters (+8850), nearly 5.5 miles above sea level.<br />
Can you think of any other examples of how signed numbers are used<br />
in life?<br />
________________________________________________________<br />
________________________________________________________<br />
________________________________________________________<br />
________________________________________________________<br />
________________________________________________________<br />
________________________________________________________<br />
3
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
i. Adding Integers<br />
When adding two or more integers, it is very important to pay<br />
attention to the sign of each integer. Are we adding a positive or<br />
negative integer? We can demonstrate this concept with a number<br />
line.<br />
Look at the two examples below. In the first example, we add a<br />
positive 3 (+3) to 2.<br />
Example: 2 + 3 = __<br />
In this second example, we add a negative 3 (-3) to 2.<br />
Example: 2 + (–3) = __<br />
As you can see, we get a very different answer in this second problem<br />
To add integers using a number line, begin with the first number in<br />
the equation. Place your finger on that number on the number line.<br />
Look at the value and sign of the second number: if positive,<br />
move to the right; if negative, move to the left. (If a number<br />
does not have a sign, this means it is positive.) With your finger,<br />
move the number of spaces indicated by the second number.<br />
Example: 1 + (-2) = ___<br />
4
On Your Own<br />
-2 + (-3) = ___<br />
-6 + (3) = ___<br />
3 + (-6) = ___<br />
-3 + 6 = ___<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
5
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Rules for Adding Signed <strong>Number</strong>s (without a <strong>Number</strong> Line)<br />
A. Same Signs<br />
• Find the sum<br />
• Keep the sign<br />
B. Different Signs<br />
• Find the difference<br />
• Keep the sign of the larger number (# with larger absolute<br />
value)<br />
On Your Own<br />
-8 + (-7) = ___ -8 + 7 = ___<br />
(-13) + (-9) = ___ (+13) + (+9) = ___<br />
21 + (-21) = ___ (-21) + 21 = ___<br />
–13 +18 = ___ -18 + 13 = ___<br />
Add -10 and -5: ___ Add (-10), (+4), and (-16): ___<br />
6
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
ii. Subtracting Integers<br />
We can turn any subtraction problem into an addition problem. Just<br />
change the subtraction sign (-) to an addition sign (+) and<br />
change the sign of the second number. Then solve as you would<br />
an addition problem.<br />
Example: –2 - (+ 3) = ___<br />
Turn it from a subtraction problem to an addition problem; then<br />
change the sign of the second number:<br />
–2 - (+ 3) = -2 + (-3)<br />
Now solve as you would an addition problem.<br />
We can show this on a number line. Place your finger on that number<br />
on the number line. Look at the value and sign of the second number:<br />
if positive, move to the right; if negative, move to the left. With<br />
your finger, move the number of spaces indicated by the second<br />
number:<br />
Let's look at another problem:<br />
Example: -2 - (-3) = -2 + (___)<br />
Answer: ___<br />
Answer: ___<br />
7
On Your Own<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
6 – (+3) = 6 + (___) = _____<br />
3 – (-3) = 3 + (___) = ____<br />
-5 – (+1) = -5 + (___) = ____<br />
1 – (+1) = 1 + (___) = ___<br />
8
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Rules for Subtracting Signed <strong>Number</strong>s (without a <strong>Number</strong> Line)<br />
Add its opposite! Draw the line and change the sign (of the second<br />
number), and follow the rules for addition.<br />
Example: 6 – (-4)<br />
Steps:<br />
• Draw the line (to turn the minus sign into a plus sign): 6 + ____<br />
• Change the sign of the second number: 6 + (+ 4)<br />
• Now you have an addition problem. Follow the rules of adding<br />
numbers: 6 + 4 =10<br />
On Your Own: Draw the line and change the sign. Then solve the<br />
addition problem.<br />
19 – (- 13) = ___ -17 – (-15) = ___<br />
34 – (-9) = ___ -18 - 14 = ___<br />
-15 - (-35) = ___ 13 - (+15) = ___<br />
-13 – 15 = ___ -35 - (+35) = ___<br />
Subtract (-15) from (20): ___ Subtract 4 from (-14): ___<br />
9
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Signed <strong>Number</strong>s Continued<br />
Look at the following problem:<br />
Example: 1 - 3 + 5 = ___<br />
We can represent this problem on a number line:<br />
We begin at 1, move 3 spaces backwards (to the left) and then 5<br />
spaces forwards (to the right). We arrive at + 3.<br />
When we are given a problem with three or more signed integers, we<br />
must work out, separately, the addition and subtraction for each<br />
integer pair:<br />
1 - 3 + 5 = 1 - 3 + 5<br />
1 - 3 = -2 ← ⎯⎯ Work out the addition or subtraction for the 1st 2 integers<br />
-2 + 5 = ___ ← ⎯⎯ Take the answer from above & add it to the last integer.<br />
On Your Own<br />
1. 12 + 3 - 5 + 4 = _____<br />
2. -3 + 5 - 2 + 3 = _____<br />
3. 4 - 6 + 3 - 2 = _____<br />
10
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
iii. Multiplying and Dividing with Signed <strong>Number</strong>s<br />
Multiplying<br />
The product of two numbers with the same sign is positive.<br />
Example: -5 ● -3 = 15<br />
The product of two numbers with different signs is negative.<br />
Example: -5 ● 3 = -15<br />
Dividing<br />
The quotient of two numbers with the same sign is positive.<br />
Example: -15 ÷ -3 = 5<br />
The quotient of two numbers with different signs is negative.<br />
Example: -15 ÷ 3 = -5<br />
On Your Own<br />
(+8) (–4) = ___ (–7) (7) = ___<br />
(–8) (-8) = ___ (+7)(+8) = ___<br />
– 36 (-3) = ___ –36 3 = ___<br />
11
B. Absolute Value<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
The absolute value of a number is its distance from 0. This distance<br />
is always expressed as a positive number, regardless if the number<br />
is positive or negative.<br />
It is easier to understand this by examining a number line:<br />
The absolute value of 5, expressed as |5|, is 5 because it is 5 units<br />
from 0. We can see this on the number line above. The absolute value<br />
of -5, expressed as |-5|, is also 5 because it is 5 units from 0. Again,<br />
look at the number line and count the number of units from 0.<br />
On Your Own: Complete the chart. How far from zero is the number?<br />
<strong>Number</strong> Absolute Value<br />
|-16|<br />
|-115|<br />
|342|<br />
|x|<br />
|-x|<br />
|-100|<br />
12
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Finding the Absolute Value of an Expression<br />
On the CAHSEE, you may need to find the absolute value of an<br />
expression. To do this, . . .<br />
• Evaluate the expression within the absolute value bars.<br />
• Take the absolute value of that result.<br />
• Perform any additional operations outside the absolute value<br />
bars.<br />
Example: 3 + |-4 - 3| = 3 + |-7| = 3 + 7 = 10<br />
On Your Own: Complete the chart.<br />
5 ●|3-8| = 5 ●|-5| = 5 ● 5 = 25<br />
|15 + 6| = =<br />
|-6 + 2| = =<br />
|1 - 3 + 2| = =<br />
4 + |-6| = =<br />
|-4| + |4| = =<br />
|16| - |-16| = =<br />
|-2| - |13| = =<br />
|-2| - |-13| = =<br />
13
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Absolute Value Continued 2.5<br />
While the absolute value of a number or expression will always be<br />
positive, the number between the absolute value bars can be<br />
positive or negative.<br />
Notice that in each case, the expression is equal to +8.<br />
You may be asked to identify these two possible values on the<br />
CAHSEE.<br />
Example: If |x| = 8, what is the value of x?<br />
For these types of problems, the answer consists of two values: the<br />
positive and negative value of the number.<br />
In the example above, the two values for x are 8 or -8.<br />
On Your Own<br />
1. If |y| = 225, what is the value of y? ____ or ____<br />
2. If |x| = 1,233, what is the value of x? ______ or ______<br />
3. If |m| = 18, what is the value of m? ____ or ____<br />
4. If |x| = 12, what is the value of x? ____ or ____<br />
5. If |y| = 17, what is the value of y? ____ or ____<br />
14
C. Fractions<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
A fraction means a part of a whole.<br />
Example: In the picture below, one of four equal parts is shaded:<br />
1<br />
We can represent this as a fraction:<br />
4<br />
1<br />
Fractions are expressed as one number over another number:<br />
4<br />
Every fraction consists of a numerator (the top number) and a<br />
denominator (the bottom number):<br />
A ← ⎯⎯ Numerator<br />
B ← ⎯⎯ Denominator<br />
A<br />
Fractions mean division: = A ÷ B<br />
B<br />
1<br />
= 1 ÷ 4 = 4 1 = .25<br />
4<br />
4<br />
= 4 ÷ 5 = 5 4 = .8<br />
5<br />
1<br />
= 1 ÷ 2 = 2 1 = .5<br />
2<br />
15
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
i. Adding & Subtracting Fractions<br />
Same Denominator: Keep the denominator; add the numerators:<br />
1 2<br />
Example: + = _____<br />
4 4<br />
We can represent this problem with a picture: Begin with the first<br />
1 2<br />
fraction, , and add two more fourths ( ):<br />
4<br />
4<br />
3<br />
We now have three-fourths of the whole shaded:<br />
4<br />
On Your Own: Add the following fractions.<br />
1 2<br />
+ = -------<br />
8 8<br />
1 1<br />
+ = -------<br />
3 3<br />
2 3<br />
+ = -------<br />
5 5<br />
2 1<br />
- = -------<br />
3 3<br />
Rule: When adding and subtracting fractions that have common<br />
denominators, we just add or subtract the numerators and keep the<br />
denominator. It gets trickier when the denominators are not the same.<br />
16
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Different Denominator<br />
1 3<br />
Example: +<br />
4 8<br />
Let's represent this with a picture:<br />
The first picture shows one whole divided into four parts. One<br />
1<br />
of these parts is shaded. We represent this as a fraction:<br />
4<br />
The second picture shows one whole divided into eight parts. Three<br />
3<br />
of these parts are shaded. We represent this as a fraction:<br />
8<br />
In order to add these two fractions, we need to first divide them up<br />
into equal parts. The first picture is divided into fourths but the<br />
second is divided into eighths. We can easily convert the first<br />
picture into eighths by drawing two more lines (i.e. divide each fourth<br />
by half):<br />
17
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Now let's see how the first fraction would appear once it is divided<br />
into eighths:<br />
1 2<br />
We can see, from the above picture, that is equal to .<br />
4<br />
8<br />
Now that we have a common denominator (8), we can add the<br />
2 3<br />
fractions: + . Just keep the denominator and add the<br />
8 8<br />
numerators:<br />
2 3<br />
+ =<br />
8 8 8<br />
2 4<br />
Let's look at another example: +<br />
3 5<br />
Can we add these two fractions in their current form? Explain.<br />
To add two fractions, we need a common denominator. We must<br />
therefore convert the fractions to ones whose denominator is the<br />
same. We can use any common denominator, but it is much easier to<br />
use the lowest common denominator, or LCD. One way to find the<br />
LCD is to make a table and list, in order, the multiples of each<br />
denominator. (Multiple means Multiply!)<br />
18
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Finding the Lowest Common Denominator (LCD)<br />
Look at the last problem again: 2 + 4<br />
3 5<br />
Now list the multiples of each denominator until you reach a<br />
common number.<br />
Multiples of 3 Multiples of 5<br />
3 5<br />
6 10<br />
9 15<br />
12<br />
15<br />
The lowest common denominator (LCD) is the first<br />
common number in both columns: 15. This will be the new<br />
denominator for both fractions.<br />
Since we changed the denominators, we must also change the<br />
numerators so that each new fraction is equivalent (or equal) to the<br />
original fraction.<br />
• Let’s start with the first original fraction: 2/3. Go back to the<br />
table. How many times did we multiply the denominator, 3,<br />
by itself? (Hint: How many rows did we go down in the first<br />
column?) ___<br />
• Since we multiplied the denominator (3) by __ to get 15,<br />
we must also multiply the numerator (2) by ___.<br />
Our new fraction is 15<br />
• Now let’s look at the second fraction: 4/*5. Since we<br />
multiplied the denominator (5) by ___, we do the same to the<br />
numerator: 4 ● ___ = ___.<br />
Our new fraction is 15<br />
• Now add the new fractions. 15 + 15 = 15<br />
We have an improper fraction because the numerator > the<br />
denominator. We must change it to a mixed number:<br />
22<br />
= ________<br />
15<br />
19
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Let's look at another example:<br />
Example: Add the following fractions: 3 + 4<br />
4 5<br />
In order to add these fractions we must first find a common<br />
denominator. Make a table and list all of the multiples for each<br />
denominator until we reach a common multiple:<br />
Multiples of 4 Multiples of 5<br />
4 5<br />
8 10<br />
12 15<br />
16 20<br />
20<br />
We have a common denominator for both fractions: 20. Since we<br />
changed the denominators for both fractions, we must also change the<br />
numerators so that each new fraction is equivalent to the original<br />
fraction.<br />
3<br />
Let’s begin with the first fraction: =<br />
4 20<br />
4<br />
Now let’s proceed to the second fraction: =<br />
5 20<br />
Now both fractions have common denominators; add<br />
them:<br />
20 + 20 = 20<br />
If the sum is an improper fraction (i.e. numerator > denominator),<br />
we generally change it to a proper fraction: _______<br />
20
On Your Own<br />
Example: 3 + 5<br />
4 6<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Step 1: Make a table and list the multiples of each denominator<br />
until you reach a common denominator:<br />
Step 2: Convert each fraction to an equivalent fraction:<br />
Step 3: Add the fractions:<br />
Note: If you end up with an improper fraction, be sure to<br />
convert it to a mixed number.<br />
21
Practice<br />
4 2<br />
+ = -----------<br />
5 5<br />
7 3<br />
– = -----------<br />
9 9<br />
2 3<br />
+ = -----------<br />
5 4<br />
2 5<br />
+ = -----------<br />
3 8<br />
3 1<br />
- = -----------<br />
4 6<br />
5 1<br />
- = -----------<br />
8 2<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
'<br />
22
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Prime Factorization<br />
Another way to find the lowest common denominator of two fractions<br />
is through prime factorization. First, let’s learn more about prime<br />
numbers:<br />
Prime <strong>Number</strong>s: A prime number has two distinct whole number<br />
factors: 1 and itself.<br />
Note: 1 is not prime because it does not have two distinct<br />
factors.<br />
Example: 6 is not prime because it can be expressed as 2 ● 3.<br />
Example: 7 is prime because it can be expressed only as the<br />
product of two distinct factors: 1 ● 7.<br />
Write the first 10 prime numbers:<br />
2 3 5 ___ ___ ___ ___ ___ ___ ___<br />
Composite <strong>Number</strong>s<br />
A non-prime number is called a composite number. Composite<br />
numbers can be broken down into products of prime numbers:<br />
Example: 4 = 2 X 2<br />
Example: 12 = 2 X 6 = 2 X 2 X 3<br />
Example: 66 = 6 X 11 = 2 X 3 X 11<br />
Example: 24 = 2 X 12 = 2 X 2 X 2 X 3<br />
Example: 33 = 3 X 11<br />
Example: 125 = 5 X 5 X 5<br />
23
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Practice: Circle all of the prime numbers in the chart below:<br />
1<br />
6<br />
11<br />
16<br />
21<br />
26<br />
31<br />
36<br />
41<br />
46<br />
2<br />
7<br />
12<br />
17<br />
22<br />
27<br />
32<br />
37<br />
42<br />
47<br />
3<br />
8<br />
13<br />
18<br />
23<br />
28<br />
33<br />
38<br />
43<br />
48<br />
4<br />
9<br />
14<br />
19<br />
24<br />
29<br />
34<br />
39<br />
44<br />
49<br />
5<br />
10<br />
15<br />
20<br />
25<br />
30<br />
35<br />
40<br />
45<br />
50<br />
24
Prime Factor Trees<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
We can find the prime factors of a number by making a factor<br />
tree:<br />
Example: Find the prime factors of 18.<br />
• Write your number: 18<br />
• Begin with the smallest prime number factor of 18 (i.e. the<br />
smallest prime number that divides evenly 18.<br />
This number is 2.<br />
• Draw two branches: 2 and the second factor: 9.<br />
18<br />
⁄ \<br />
2 9<br />
• Continue this process for each branch until you have no remaining<br />
composite numbers. The prime factors of 18 are the prime<br />
numbers at the ends of all the branches:<br />
18<br />
⁄ \<br />
2 9<br />
⁄\<br />
3 3<br />
The prime factored form of 18 is ___ ● ___ ● ___.<br />
25
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Example: Find the prime factors of 60 using the factor tree:<br />
60<br />
⁄\<br />
2 30<br />
⁄\<br />
2 15<br />
⁄\<br />
3 5<br />
The prime factors of 60 are the factors at the end of each<br />
branch: ___, ___, ____ and ___.<br />
Helpful Guidelines:<br />
• Start with the smallest numbers: first 2’s, then 3’s, and so on.<br />
• If a number is even, it is divisible by 2.<br />
Note: An even number ends in 0, 2, 4, 6, and 8.<br />
Examples: 124 38 46 180 112<br />
• If the digits of a number add up to a number divisible by 3, the<br />
number is divisible by 3.<br />
Example: 123 can be divided evenly by 3 because if we add all of its<br />
digits, we get 6: 1 + 2 + 3 = 6<br />
Since the sum of the digits of 123 is divisible by 3, so too is 123.<br />
• If a number ends in 0 or 5, it is divisible by 5.<br />
Examples: 25 130 125 455<br />
26
On Your Own<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Find the prime factors of each number, using a factor tree:<br />
64 48<br />
72<br />
27
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Prime Factorization and the Lowest Common Denominator<br />
On the CAHSEE, you will be asked to find the prime factored form of<br />
the lowest common denominator (LCD) of two fractions:<br />
Example: Find the prime factored form for the lowest<br />
5 5<br />
common denominator + .<br />
6 9<br />
There are two methods we can use to solve this problem:<br />
Method I: Factor Tree and Pairing<br />
Steps:<br />
• Make a factor tree for both denominators:<br />
6 9<br />
⁄\ ⁄\<br />
2 3 3 3<br />
• Pair up common prime factors:<br />
• Multiply the common factor (counted once) by all leftover<br />
(unpaired) factors:<br />
LCD = 3 ● __ ● ___ = ____<br />
28
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Let's look at another example:<br />
Example: Find the least common multiple of 72 and 24. Write the<br />
LCM in prime-factored form.<br />
Steps:<br />
• Make a factor tree for each number:<br />
72 24<br />
⁄\ ⁄ \<br />
2 36 2 12<br />
⁄\ ⁄\<br />
2 18 2 6<br />
⁄ \ ⁄\<br />
2 9 2 3<br />
⁄ \<br />
3 3<br />
• Pair off common factors:<br />
72 = 2 ● 2 ● 2 ● 3 ● 3<br />
24 = 2 ● 2 ● 2 ● 3<br />
←⎯⎯ Count any common factor once!<br />
• Multiply all common factors by all leftover (unpaired) factors:<br />
LCM = __ ● __ ● __ ● __ ● ___ = ____<br />
29
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
On Your Own: Solve the following problems, using the factor<br />
tree/pairing method.<br />
1. What is the prime factored form of the lowest common<br />
5 5<br />
denominator of + ?<br />
9 12<br />
2. Find the least common multiple, in prime-factorization form,<br />
of 12 and 15.<br />
We will now look at the second method to find the prime factored<br />
from of the lowest common denominator (LCD) of two fractions.<br />
30
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Method II: Factor Tree and Venn Diagram<br />
To illustrate this second method, let's return to the original problem:<br />
Example: Find the prime factored form for the lowest<br />
5 5<br />
common denominator of + .<br />
6 9<br />
• Use the factor tree method to find the prime factored form of 6:<br />
6<br />
⁄ \<br />
2 3<br />
• Use the factor tree method to find the prime factored from of 9:<br />
9<br />
⁄ \<br />
3 3<br />
• Use a Venn diagram to find the prime-factored form of the lowest<br />
common denominator:<br />
On the next page, we will learn how to fill out this diagram.<br />
31
Venn Diagrams<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Venn diagrams are overlapping circles that help us compare and<br />
contrast the characteristics of different things. We can use them to<br />
find what is common to two items (where the circles overlap in the<br />
middle) and what is different between them (what is outside the<br />
overlap on either or both sides).<br />
Here, we want to find out which prime factors are the same for two<br />
numbers and which factors are distinct, or different.<br />
6 9<br />
⁄ \ ⁄ \<br />
2 3 3 3<br />
Steps:<br />
• Since only one 3 is common to both numbers, we need to put it in<br />
the middle, where the two circles overlap:<br />
6 Both 9<br />
↓<br />
Continued on next page ⎯<br />
⎯→<br />
32
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
• Now find the prime factors that are left for 6 and place them in the<br />
part of the circle for 6 that does not overlap with the circle for 9.<br />
6 Both 9<br />
↓<br />
• Next, find the prime factors that are left for 9 and place them in the<br />
part of the circle that does not overlap with the circle for 6.<br />
6 Both 9<br />
↓ ↓ ↓<br />
• The lowest common denominator for 6 and 9 is the product of all<br />
of the numbers in the circles:<br />
___ ● ___ ● ___, which is equal to ____<br />
Note: To write the LCD in prime-factored form, we do not carry out<br />
the multiplication; we just write the prime numbers:<br />
LDC of 6 and 9 = ___ ● ___ ● ___<br />
33
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
On Your Own<br />
1. What is the prime factored form of the lowest common denominator<br />
1 3<br />
of and ?<br />
6 10<br />
• Create separate prime factor trees for both denominators:<br />
6 10<br />
⁄ \ ⁄ \<br />
__ __ __ __<br />
• Organize the prime factors of both denominators, using a Venn<br />
diagram:<br />
6 Both 10<br />
What is the LCD? ________<br />
Write the LCD in prime factored form: _____________<br />
34
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
2. Find the prime factored form of the lowest common denominator for<br />
the following:<br />
5 11<br />
+<br />
8 12<br />
Factor Trees:<br />
LCD: ______<br />
8 Both 12<br />
LCD in prime factored form: _________________<br />
35
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
ii. Multiplying Fractions<br />
Whenever you are asked to find a fraction of a number, you need to<br />
multiply. In math, the word “of” means multiply.<br />
1 1<br />
Example: Find of .<br />
2 2<br />
1 1<br />
This is a multiplication problem. It means, “What is ● ?”<br />
2 2<br />
We can represent the problem visually. Here is the first part of the<br />
1<br />
problem: of the circle has been shaded.<br />
2<br />
1<br />
Taking of a number means dividing it by 2.<br />
2<br />
Now, if we take one-half of this again (divide it by 2 again), we get<br />
the following:<br />
1 1 1<br />
of is equal to .<br />
2 2<br />
4<br />
We end up with one-fourth of the circle.<br />
Note: We also could have solved the above problem by multiplying<br />
the numerator by the numerator and the denominator by the<br />
denominator:<br />
Numerator ● Numerator_ = 1 ● 1 = 1<br />
Denominator ● Denominator 2 ● 2 4<br />
36
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
When working these problems out during the CAHSEE, you will need to<br />
apply this rule:<br />
Numerator ● Numerator__<br />
Denominator ● Denominator<br />
Look at the next problem:<br />
1 1<br />
Find of 24. In math, we can write this as follows: ● 24<br />
2<br />
2<br />
The first factor is a fraction and the second factor is a whole number.<br />
We can easily change the second factor to a fraction because any<br />
whole number can be expressed as a fraction by placing it over a 1:<br />
24<br />
24 = because 24 means 24 ones.<br />
1<br />
1 24<br />
We can rewrite the problem as follows: ●<br />
2 1<br />
Now, just follow the rule for multiplying two fractions:<br />
Numerator ● Numerator__<br />
Denominator ● Denominator<br />
1 24 24<br />
● = = ___<br />
2 1 2<br />
1<br />
Note: Taking of 24 means dividing 24 by 2.<br />
2<br />
37
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Now look at the next example:<br />
24 5<br />
Example: ● = ____<br />
1 6<br />
There are two ways to solve this problem:<br />
1. The hard way: Perform all operations<br />
• Multiply numerators: 24 ● 5<br />
• Multiply denominators: 1 ● 6<br />
• Divide new numerator by denominator: 120 ÷6<br />
24 ● 5 = 120 = 120 ÷6 = ___<br />
1 ● 6 6<br />
2. The easy way: Simplify first, and then multiply:<br />
4<br />
24 ● 5_ = ____ Simplify by dividing out common factors!<br />
1 6 1<br />
Look at the following problems:<br />
533 9 3<br />
● 4 = ______ 3,435 ● = _____ 79 ● = _____<br />
4<br />
9<br />
3<br />
Do you need to work out these problems, or do you already know the<br />
answers? ________________________________________________<br />
________________________________________________________<br />
Remember: If you divide both a numerator and denominator by a<br />
common factor, you can make the problem much simpler to solve. So<br />
save yourself the time and work, and recognize these types of<br />
problems right away.<br />
38
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Look at the next set of problems:<br />
4 6<br />
●<br />
12 8<br />
8 5 14 3<br />
● ●<br />
15 12<br />
21 7<br />
What do you notice about the above problems? __________________<br />
________________________________________________________<br />
There is a lot of heavy multiplication involved in these problems. Is<br />
there a way to make your work easier? Explain:<br />
We can _________ fractions by ____________________<br />
before solving.<br />
We can simplify these problems quite a bit before solving. This makes<br />
our job easier. Let’s look at the first problem:<br />
4 6<br />
●<br />
12 8<br />
We can divide out common factors in each fraction. These<br />
common factors become clear if we write each fraction as a<br />
product of prime factors. Let's begin with the first fraction:<br />
4 = 1 2 ● 1 2____ = 1<br />
12 12 ● 12 ● 3 3<br />
Now do the second fraction on your own:<br />
6<br />
= ____________________<br />
8<br />
Now let's multiply the two reduced fractions; but first, can we simplify<br />
anymore? ______ If so, simplify first, and then multiply:<br />
39
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
On Your Own: Simplify and solve:<br />
8 5<br />
● = ______<br />
15 12<br />
3 10<br />
● = ______<br />
5 21<br />
14 3<br />
● = ______<br />
21 7<br />
12 5<br />
● = ______<br />
15 6<br />
2 2<br />
36 ● = _____ 27 ● = _____<br />
3<br />
9<br />
2 3<br />
● = _____<br />
3 2<br />
10 3<br />
● = _____<br />
15 2<br />
40
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
iii. Dividing Fractions<br />
When you divide something by a fraction, think, “How many<br />
times does the fraction go into the dividend?”<br />
1<br />
Example: 3 ÷<br />
2<br />
↑<br />
dividend<br />
This means, “How many times does ___ go into ____?”<br />
We can represent this visually:<br />
Answer: __________<br />
1<br />
Example: 2 ÷<br />
8<br />
We can represent this visually:<br />
Answer: __________<br />
41
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
On Your Own: Solve the next few problems, asking each time,<br />
“How many times does the fraction go into the whole number?”<br />
1<br />
3 ÷ = ___<br />
4<br />
1<br />
3 ÷ = ___<br />
8<br />
1<br />
4 ÷ = ___<br />
8<br />
Do you see a pattern? Explain.<br />
___________________________________________________<br />
___________________________________________________<br />
42
Reciprocals<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
As we saw in the previous exercise, each time we divide a whole<br />
number by a fraction, we get as our answer the product of the<br />
whole number and the reciprocal of the fraction.<br />
Reciprocal means the flip-side, or inverse.<br />
4 5<br />
Example: The reciprocal of is .<br />
5 4<br />
On Your Own: Find the reciprocal of each fraction:<br />
3 7 12<br />
⎯ ⎯→ _____ ⎯ ⎯→ _____ ⎯ ⎯→ _____<br />
4<br />
9<br />
5<br />
13 35 1<br />
⎯ ⎯→ ____ ⎯ ⎯→ ____ ⎯ ⎯→ _____<br />
1<br />
53<br />
12<br />
Now let's find the reciprocal of a whole number. We know that<br />
any whole number (or integer) can be expressed as a fraction by<br />
placing it over 1:<br />
35<br />
Example: 35 =<br />
1<br />
The reciprocal is the fraction turned upside down, or inverted:<br />
1<br />
Example: The reciprocal of 35 is<br />
35<br />
On Your Own: Find the reciprocal of each integer.<br />
1000 121 173 -18 -100<br />
_____ ____ ____ ____ ____<br />
43
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Now we are ready to divide a whole number by a fraction.<br />
1 2 10 20<br />
Example: 2 ÷ = ● = = 20<br />
10 1 1 1<br />
We can represent the above problem visually:<br />
1<br />
2 ÷ means . . .<br />
10<br />
If we count the number of little rectangles in the two big<br />
rectangles, we get _____.<br />
On Your Own<br />
1<br />
3 ÷ = ________________________<br />
5<br />
1<br />
6 ÷ ÷ = ________________________<br />
5<br />
1<br />
5 ÷ = _________________________<br />
3<br />
1<br />
2 ÷ = _________________________<br />
3<br />
1<br />
4 ÷ = _________________________<br />
2<br />
44
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Simplifying Division Problems<br />
3 9<br />
Example: ÷<br />
5 10<br />
Remember the rule for dividing fractions:<br />
Rule: When dividing fractions, multiply the first fraction<br />
by the reciprocal of the second fraction!<br />
Steps:<br />
• Multiplying the first fraction by the reciprocal of the second<br />
fraction, we get . . .<br />
3 10<br />
●<br />
5 9<br />
• We can simplify this problem by dividing out common factors:<br />
1 3 ● 10 2<br />
1 5 9 3<br />
• Now, apply the rule for multiplication:<br />
Numerator ● Numerator____ = 1 ● 2 = ____<br />
Denominator ● Denominator 1 ● 3<br />
45
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
On Your Own: Simplify and solve.<br />
1 3 ÷ = _________________<br />
4 8<br />
2 3 ÷ = _________________<br />
5 10<br />
3 9 ÷ = _________________________<br />
7 14<br />
5 15 ÷ = __________________<br />
8 24<br />
1 13 ÷ = __________________<br />
10 10<br />
46
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Unit Quiz: The following problems appeared on the CAHSEE.<br />
11 1 1<br />
1. – ( + ) =<br />
12 3 4<br />
1<br />
A.<br />
3<br />
3<br />
B.<br />
4<br />
5<br />
C.<br />
6<br />
9<br />
D.<br />
5<br />
5 7<br />
2. Which fraction is equivalent to + ?<br />
6 8<br />
35<br />
A.<br />
48<br />
6<br />
B.<br />
7<br />
20<br />
C.<br />
21<br />
41<br />
D.<br />
24<br />
3. What is the prime factored form for the lowest common<br />
2 7<br />
denominator of the following: + ?<br />
9 12<br />
A. 3 X 2 X 2<br />
B. 3 X 3 X 2 X 2<br />
C. 3 X 3 X 3 X 2 X 2<br />
D. 9 X 12<br />
47
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
4. Which of the following is the prime factored form of the lowest<br />
7 8<br />
common denominator of +15 ?<br />
10<br />
A. 5 X 1<br />
B. 2 X 3 X 5<br />
C. 2 X 5 X 3 X 5<br />
D. 10 X 15<br />
5. Which of the following numerical expressions results in a negative<br />
number?<br />
A. (-7) + (-3)<br />
B. (-3) + (7)<br />
C. (3) + (7)<br />
D. (3) + (-7) + (11)<br />
6. One hundred is multiplied by a number between 0 and 1. The<br />
answer has to be ____.<br />
A. less than 0.<br />
B. between 0 and 50 but not 25.<br />
C. between 0 and 100 but not 50.<br />
D. between 0 and 100.<br />
7. If |x| = 3, what is the value of x?<br />
A. -3 or 0<br />
B. -3 or 3<br />
C. 0 or 3<br />
D. -9 or 9<br />
48
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
8. What is the absolute value of -4?<br />
A. -4<br />
1<br />
B. −<br />
4<br />
1<br />
C.<br />
4<br />
D. 4<br />
9. The winning number in a contest was less than 50. It was a<br />
multiple of 3, 5, and 6. What was the number?<br />
A. 14<br />
B. 15<br />
C. 30<br />
D. It cannot be determined<br />
10. If n is any odd number, which of the following is true about n + 1?<br />
A. It is an odd number.<br />
B. It is an even number<br />
C. It is a prime number<br />
D. It is the same as n −1.<br />
11. Which is the best estimate of 326 X 279?<br />
A. 900<br />
B. 9,000<br />
C. 90,000<br />
D. 900,000<br />
49
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
12. The table below shows the number of visitors to a natural history<br />
museum during a 4-day period.<br />
Day <strong>Number</strong> of Visitors<br />
Friday 597<br />
Saturday 1115<br />
Sunday 1346<br />
Monday 365<br />
Which expression would give the BEST estimate of the total number<br />
of visitors during this period?<br />
A. 500 + 1100 + 1300 + 300<br />
B. 600 + 1100 + 1300 + 300<br />
C. 600 + 1100 + 1300 + 400<br />
D. 600 + 1100 + 1400 + 400<br />
2<br />
13. John uses of a cup of oats per serving to make oatmeal. How<br />
3<br />
many cups of oats does he need to make 6 servings?<br />
2<br />
A 2<br />
3<br />
B 4<br />
1<br />
C 5<br />
3<br />
D 9<br />
14. If a is a positive number and b is a negative number, which<br />
expression is always positive?<br />
A. a - b<br />
B. a + b<br />
C. a X b<br />
D. a ÷ b<br />
50
Unit 2: Exponents<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
On the CAHSEE, you will be given several problems on exponents.<br />
Exponents are a shorthand way of representing how many times a<br />
number is multiplied by itself.<br />
Example: 9 9 9 9 can be expressed as 9 4 since four 9's are<br />
multiplied together.<br />
Base ←⎯⎯ 9 4 exponent<br />
The number being multiplied is called the base.<br />
The exponent tells how many times the base is multiplied by itself.<br />
9 4 is read as “9 to the 4 th power,” or “9 to the power of 4.”<br />
Let's look at another example: 2 = 2 ● 2 ● 2 ● 2 ● 2 = 32<br />
On Your Own<br />
2³ = ___ 2 = ___<br />
3² = ___ 3³ = ___<br />
Power of 0<br />
Any number raised to the 0 power (except 0) is always equal to 1.<br />
Example: 100 0 = 1<br />
On Your Own<br />
7 0 = ___ 293 0 = ___ (-131) 0 = ___ 47 0 = ___<br />
51
Power of 1<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
A number raised to the 1 st power (i.e., an exponent of 1) is always<br />
equal to that number.<br />
Example: 100 1 = 100<br />
On Your Own<br />
7 1 = ____ 293 1 = ____ (-131) 1 = ____ 47 1 = ____<br />
Power of 2 (Squares)<br />
A number raised to the 2 nd power is referred to as the square of a<br />
number. When we square a whole number, we multiply it by itself.<br />
Example: 12² = 12 ● 12 = 144<br />
The square of any whole number is called a perfect square.<br />
Here are the first 3 perfect squares:<br />
1² = 1 ● 1 = 1 2² = 2 ● 2 = 4 3² = 3 ● 3 = 9<br />
On Your Own: Write the perfect squares for the following numbers:<br />
4² = ____ 5² = ____ 6² = ____ 7² = ____<br />
8² = ____ 9² = ____ 10² = ____ 11² = ____<br />
20² = ____ (2 - 8)² – (3 - 7)² =_______ 3² + 5² = _____<br />
52
Square Roots<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
The square root ( ) of a number is one of its two equal factors.<br />
Example: 8² = 64<br />
1 2 3 4 5 6 7 8<br />
2<br />
3<br />
4<br />
5<br />
6<br />
7<br />
8<br />
Any number raised to the second power (the power of 2) can be<br />
represented as a square. That’s why it’s called “squaring the<br />
number.”<br />
The square above has 64 units. Each side (the length and width) is 8<br />
units. The area of the square is determined by multiplying the length<br />
(8 units) by the width (8 units). The square root is the number of<br />
units in each of the two equal sides: 8<br />
Note: 64 has a second square root: -8 (-8 ● -8 = +64). However,<br />
when we are asked to evaluate an expression, we always take the<br />
positive root.<br />
Example: Find the square root of 36.<br />
Answer: 36 = ___<br />
53
On Your Own<br />
1. 25 = ___<br />
2. 16 = ___<br />
3. 100 = ___<br />
4. 81 = ___<br />
5. 49 = ___<br />
6. 121 = ___<br />
7. 400 = ___<br />
8. 4 + 9 = ___<br />
9.<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
2 2<br />
3 + 4 = ___<br />
10. Which is not a perfect square?<br />
A. 144<br />
B. 100<br />
C. 48<br />
D. 169<br />
54
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Power of 3 (Cubes)<br />
A number with an exponent of 3 (or a number raised to the 3 rd power)<br />
is the cube of a number.<br />
Example: 5³ = 5 ● 5 ● 5 = 125<br />
The cube of a whole number is called a perfect cube.<br />
Cubes of Positive <strong>Number</strong>s<br />
The cube of a positive number will always be a positive number.<br />
1³ = 1 ● 1 ● 1 = 1 2³ = 2 ● 2 ● 2 = 8<br />
Cubes and Negative <strong>Number</strong>s<br />
The cube of a negative number will always be a negative number.<br />
(-1)³ = (-1)(-1)(-1) = -1 (-2) 3 = (-2)(-2)(-2) = -8<br />
On Your Own: Write the perfect cubes for the following numbers:<br />
3³ = _____ 4³ = ______ 5³ = _____<br />
-3³ = _____ -4³ = ______ -5³ = _____<br />
55
Cube Roots<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
The cube root of a number is one of its three equal factors. The cube<br />
root of a positive number will always be a positive number.<br />
Example: What is the cube root of 27?<br />
The cube root of 27 is written as 3 27<br />
To find the cube root of 27, ask, “What number multiplied by itself 3<br />
times is equal to 27?”<br />
__ ● __ ● __ = 27<br />
3 ● 3 ● 3 = 27, or 3³ = 27.<br />
On Your Own<br />
3 3 3 3<br />
8 = ___ 64 = ____ 1 , 000 = ____ 125 = ____<br />
Cube Roots of Negative <strong>Number</strong>s<br />
The cube root of a negative number will always be a negative number.<br />
Example: 3 − 64<br />
Ask, “What number multiplied by itself 3 times is equal to -64?<br />
__ ● __ ● __ = -64<br />
-4 ● -4 ● -4 = -64, or (-4)³ = -64<br />
On Your Own: 3 − 1,<br />
000 = ____ 3 − 125 = ____ 3 − 8 = ____<br />
56
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Raising Fractions to a Power<br />
When raising a fraction to an exponent, both the numerator (top<br />
number) and the denominator (bottom number) are raised to the<br />
exponent:<br />
2<br />
5<br />
numerator<br />
denominator<br />
Example: (2/5)³ = 2 ● 2 ● 2 = 8_<br />
5 ● 5 ● 5 125<br />
On Your Own<br />
(1/4)²= ____ (1/2) = _____ (2/3)³ = ____<br />
(2/5)³ = _____ (4/7)² = ____ (6/11)² = _____<br />
(3/4)³ = ____ (5/12)= ____ (2/5)² = ____<br />
Taking the Root of a Fraction<br />
When taking the root of a fraction, we must take the root of both the<br />
numerator and denominator.<br />
Example:<br />
On Your Own<br />
3<br />
9 25 36<br />
= _____ = _____ = _____<br />
16<br />
100<br />
81<br />
1 81 1<br />
= ____ = _____ = _____<br />
125<br />
121<br />
9<br />
3<br />
3<br />
27<br />
= _____<br />
64<br />
8<br />
= _____<br />
27<br />
57
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Raising Negative <strong>Number</strong>s to a Power<br />
When raising a negative number to a power, we are raising both the<br />
number and the negative sign. The answer may be positive or<br />
negative:<br />
A. If the exponent is an even number, the answer will be a positive<br />
number (as in the example below) since a negative multiplied by a<br />
negative equals a positive.<br />
Example: (-2) 6 = (-2)(-2)(-2)(-2)(-2)(-2) = 64<br />
Note: (-2) 6 and -2 6 are two different problems:<br />
• -2 6 tells us to multiply positive 2 by itself 6 times<br />
(2)(2)(2)(2)(2)(2) = 64<br />
and then take the negative of that answer: -64<br />
• (-2) 6 tells us to multiply -2 by itself 6 times:<br />
(-2)(-2)(-2)(-2)(-2)(-2) = +64<br />
B. If the exponent is an odd number, the answer will be a negative<br />
number (a positive multiplied by a negative equals a negative).<br />
Example: (-2) 5 = (-2)(-2)(-2)(-2)(-2) = -32<br />
On Your Own<br />
(-3)² = _____ -3³ = _____ (-2)² = _____ (-2) = _____<br />
-4² = _____ -4 = _____ (-5)² = _____ -5² = _____<br />
58
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Negative Exponents<br />
On the CAHSEE, you may be given an expression with a negative<br />
exponent. When an exponent is negative, the expression represents<br />
a fraction:<br />
1<br />
Example: 3¯³ means 3<br />
3<br />
Notice that the exponent is now positive.<br />
Remember: Any whole number can be written as a fraction by placing<br />
it over 1:<br />
3<br />
3¯³ can also be written as<br />
1<br />
3 −<br />
We now flip the fraction and make the exponent positive.<br />
3 3 −<br />
1<br />
1<br />
⎯ ⎯→ 3<br />
3<br />
In the above example, the numerator is equal to 1, and the<br />
denominator consists of the base and the (positive) exponent.<br />
On Your Own: Flip the fraction and make the exponent positive.<br />
3¯² = ____ 5¯³= ____ 2¯³ = ____ 4¯² = ____<br />
1<br />
59
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Negative Exponents and Fractions<br />
When raising a fraction to a negative exponent, just invert the entire<br />
fraction and make the exponents positive:<br />
Example: − 3<br />
3<br />
1<br />
Here we have a fraction whose denominator consists of the base and a<br />
negative exponent. If we invert the fraction, the exponent<br />
becomes positive:<br />
3<br />
1<br />
−3<br />
3<br />
⎯ ⎯→<br />
1<br />
3<br />
On Your Own<br />
1<br />
1. ( ) 3<br />
2<br />
2. ( ) 3<br />
1<br />
3. ( ) 8<br />
3<br />
4. ( ) 5<br />
1<br />
5. ( ) 3<br />
−2<br />
−1<br />
−2<br />
−2<br />
−3<br />
⎯ ⎯→ 3 3<br />
2<br />
= ( )<br />
= ___<br />
1<br />
= ( ) = ___<br />
= _____<br />
= _____<br />
= _____<br />
60
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Multiplying Expressions Involving Exponents with a Common<br />
Base<br />
On the CAHSEE, you may be asked to multiply expressions involving<br />
exponents.<br />
Example: 3 5 ● 3 4<br />
In order to multiply expressions involving exponents, there must be a<br />
common base. In the above example, the base (3) is common to both<br />
terms.<br />
When we have a common base, the rule for multiplying the<br />
expressions is simple: keep the base and add the exponents:<br />
Base ● Base = Base 5+4 ⎯ ⎯→ 3 5 ● 3 4 =3 5+4 =3 9<br />
On Your Own<br />
2² ● 2⁸ = ____ 3¹ ● 3⁷ = ____<br />
4 3 ● 4 2 = ____ 4 ● 4¯ = ____<br />
3¯³ ● 3³ = ____ 6 ● 6 = ____<br />
61
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Note: In some cases, we may end up with a negative exponent.<br />
Remember to apply the rules for negative exponents: invert the<br />
fraction and make the exponent positive.<br />
Example: 3 2 ● 3 -3 = 3 2+(-3) 3<br />
= 3¯ =<br />
1<br />
1 −<br />
On Your Own<br />
1 1<br />
= = 1<br />
3 3<br />
4 1 ● 4¯ 3 = _______ 5¯ 1 ● 5¯ 1 = __________<br />
3 5 ● 3¯ 8 = _______ 4 ● 4¯ 7 = __________<br />
Dividing Expressions Involving Exponents with a Common Base<br />
On the CAHSEE, you may be asked to divide expressions involving<br />
exponents.<br />
For these types of problems, there must be a common base:<br />
3<br />
5<br />
Example: 3<br />
3<br />
To divide exponents with a common base, keep the base and<br />
subtract the exponent in the denominator from the exponent in the<br />
numerator:<br />
5<br />
5<br />
Base -<br />
= Base = Base² ⎯ ⎯→<br />
3<br />
3<br />
Base<br />
3 5-3 2<br />
= 3 = 3<br />
3<br />
62
On Your Own<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
3<br />
5<br />
3<br />
= _______ 2<br />
3<br />
3<br />
4<br />
8<br />
5<br />
= _________ 2<br />
3<br />
5<br />
4<br />
= ________<br />
4<br />
2<br />
= ________<br />
2<br />
−2<br />
3<br />
The next problem is a bit more complicated: −3<br />
3<br />
Remember, when an exponent is negative, the expression is a<br />
fraction and the numerator (top number) is always equal to 1,<br />
while the denominator (bottom number) is the base. But, here, the<br />
problem is already a fraction, so we really have one fraction over<br />
another fraction. We will get back to the above problem in a moment,<br />
but first, let’s do a quick review of the rules for dividing fractions:<br />
Dividing Fractions<br />
To divide two fractions, we multiply the 1st fraction by the<br />
reciprocal of the 2 nd fraction. This means that we invert the second<br />
fraction over, or invert it.<br />
2 5<br />
For example, the reciprocal of is .<br />
5 2<br />
Let’s solve the following problem:<br />
3 1 3 3 9<br />
÷ = ● =<br />
4 3 4 1 4<br />
9<br />
is an improper fraction (numerator > denominator). We must<br />
4<br />
1<br />
change this to a mixed fraction (whole number and fraction): 2<br />
4<br />
63
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
−2<br />
3<br />
Now we are ready to tackle the earlier: problem: −3<br />
3<br />
We have negative exponents in both the numerator and the<br />
denominator. We can therefore rewrite each as fractions with<br />
positive exponents:<br />
1 1<br />
3¯² = and 3¯³ = 2<br />
3<br />
3<br />
3<br />
We can now rewrite the original problem as follows: 2<br />
3<br />
1 1<br />
÷ 3<br />
Applying the rule for dividing two fractions, we invert the second<br />
fraction and multiply:<br />
1 3<br />
● 2<br />
3 1<br />
3<br />
Multiplying the numerator by the numerator, and the denominator by<br />
3<br />
3<br />
the denominator, we get . . . 2<br />
3<br />
Now we apply the rules for dividing exponents: the base remains the<br />
same and we subtract the exponent in the denominator from the<br />
exponent in the numerator:<br />
3<br />
3<br />
= 3³¯² = ________<br />
2<br />
3<br />
Shortcut!<br />
Since both exponents in the above example are negative, a quicker<br />
way to solve the problem is to just flip the fractions and reverse the<br />
sign of each exponent; then simplify:<br />
3<br />
−<br />
3<br />
−2<br />
3<br />
3<br />
3<br />
= = _________<br />
2<br />
3<br />
3<br />
64
Another Shortcut!<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
A third way to solve the problem is to apply the rule for dividing<br />
expressions with exponents: keep the base and subtract the<br />
exponent in the denominator from the exponent in the numerator:<br />
−2<br />
Base -2 -(-3) - + 3<br />
= Base = Base ² ⎯→<br />
−3<br />
Base<br />
3<br />
−<br />
3<br />
−2<br />
3<br />
On Your Own<br />
2<br />
−<br />
2<br />
−8<br />
8<br />
−<br />
8<br />
3<br />
−4<br />
2<br />
−<br />
2<br />
2<br />
−7<br />
2<br />
−<br />
2<br />
2 −<br />
2<br />
1<br />
2<br />
3<br />
2<br />
3<br />
⎯ Base 1<br />
= 3 -2 -(-3) = 3 - ² + 3 ⎯ ⎯→ 3 1 = 3<br />
= ___________<br />
= ___________<br />
= ___________<br />
= ________<br />
= ___________<br />
65
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Power Raised to a Power<br />
When raising a power to a power, multiply the powers together:<br />
Example: (2 3 ) 2 = 2 (3) ● (2) = 2 6<br />
This is easy to see if you expand the exponents:<br />
(2 3 ) 2 =<br />
(2³)(2³) =<br />
(2 ● 2 ● 2) (2 ● 2 ● 2) =<br />
2 ● 2 ● 2 ● 2 ● 2 ● 2 =<br />
2 6<br />
On Your Own<br />
(y³)² = ______ (2)² = ______<br />
(n 3 ) 3 = _____ (5)³ = _____<br />
(2²) = _____ (x²y)² = _____<br />
66
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Square Roots of Non-Perfect Squares<br />
Remember that when we multiply a whole number by itself, we get a<br />
perfect square. And the square root of a perfect square is the factor<br />
that, when multiplied by itself, gave us the perfect square.<br />
For example, the square root of 64 is 8 because 8 ● 8 = 64.<br />
But whole numbers that are not perfect squares still have square<br />
roots. However, their square roots are not whole numbers; rather<br />
they are decimals or fractions of whole numbers.<br />
On the CAHSEE, you may be given a non-perfect square and asked to<br />
place its root between two consecutive whole numbers.<br />
Example: Between what two consecutive whole numbers is 153 ?<br />
Solution:<br />
Think about our list of perfect squares. Refer to the chart on the next<br />
page.<br />
Since 153 falls between 144 and 169 in our perfect squares list, the<br />
square root of 153 is between 12 and 13. (Note: 12 and 13 are the<br />
square roots of 144 and 169 respectively).<br />
67
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Memorize these for the CAHSEE!<br />
<strong>Number</strong> Square<br />
1 1<br />
2 4<br />
3 9<br />
4 16<br />
5 25<br />
6 36<br />
7 49<br />
8 64<br />
9 81<br />
10 100<br />
11 121<br />
12 144<br />
13 169<br />
14 196<br />
15 225<br />
16 256<br />
17 289<br />
18 324<br />
19 361<br />
20 400<br />
68
On Your Own<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
1. Between what two consecutive whole numbers is the square root of<br />
17?<br />
2. Between which two consecutive whole numbers is 200 ?<br />
3. Between which two consecutive whole numbers is 130 ?<br />
4. The square root of 140 is between which two numbers?<br />
5. Between which two integers does 53 lie?<br />
69
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Roots and Exponents<br />
On the CAHSEE, you may be given a variable that has been raised to a<br />
power and asked to find the base (the original number before it was<br />
raised).<br />
Example: If x² = 25, find the value for x.<br />
Since the base (x) is raised to the second power, we can find the value<br />
for x by taking the square root of x² . Since we have an equation, we<br />
must also find the square root of 25 so that the two sides of the<br />
equation remain in balance.<br />
x² = 25 ⎯ ⎯→ x = 5<br />
You may also be given the root of a variable and asked to find the<br />
variable.<br />
Example: x = 5<br />
To solve this, we need to square both sides of the equation:<br />
( x )² = (5)² ⎯ ⎯→ x = 25<br />
On Your Own: Find x:<br />
x² = 64 ______ x³ = 8 ______<br />
x = 1/27 ______ x² = 9/16 ______<br />
x = 8/27 ______ x² = 4/25 ______<br />
x = 11 ______<br />
3 x = 10 ______<br />
x = 20 ______ x = 9 ______<br />
70
Scientific Notation<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Scientific Notation is a way to express very small or very large<br />
numbers, using exponents.<br />
Example of a Very Big <strong>Number</strong>: The distance of the earth from the<br />
sun is approximately 144,000,000,000 meters.<br />
You can see that it can be tedious to write so many zeroes. This<br />
number can be expressed much more simply in scientific notation:<br />
1.44 X 10<br />
Example of a Very Small <strong>Number</strong>: An example using a very small<br />
number is the mass of a dust particle: 0.000000000 753 kg.<br />
We can write this number in scientific notation as 7.53 X 10 - º.<br />
On the CAHSEE, you will need to . . .<br />
• Read numbers in scientific notation<br />
• Compare numbers in scientific notation<br />
• Convert from standard notation (15,340) to scientific notation<br />
(1.534 X 10 4 )<br />
• Convert from scientific notation (2.36 X 10¯ 3 ) to standard<br />
notation (.00236)<br />
71
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Scientific Notation is a special type of exponent expression: the base<br />
is always 10 and it is raised to a positive or negative power.<br />
A number written in scientific notation consists of four parts:<br />
i. 4.95 X 10¯²<br />
a number (n) greater than or equal to 1 and less than 10<br />
ii. 4.95 X 10¯²<br />
iii. 4.95 X 10¯²<br />
iv. 4.95 X 10¯²<br />
a multiplication sign<br />
the base, which is always 10<br />
a positive or negative exponent<br />
72
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Examples Correct Scientific Notation? Why?<br />
4.5 x 10 13<br />
45.6 x 10 -8<br />
Yes<br />
No<br />
1 ≤ n < 10<br />
n > 10<br />
Remember: For an expression to be written in correct scientific<br />
notation, the number (n) that appears before the base must be greater<br />
or equal to 1 and less than 10.<br />
On Your Own: Check all expressions in correct scientific notation:<br />
3.2 X 10 13<br />
23.6 X 10 12<br />
5.788 X 10³<br />
5.788 X 10¯³ 57.88 X 10² 2.36 X 10³<br />
2.36 X 10² 0. 0236 X 10 8 0. 236 X 10 7<br />
2.3 X 10 7 2. 3 X 10¯³ ` 0.23 X 10¯²<br />
73
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Converting to Scientific Notation:<br />
Example: Write in scientific notation: 3,860,000<br />
(1) Convert to a number between 1 and 10.<br />
How: Place decimal point such that there is one non-zero digit to the<br />
left of the decimal point: 3.86<br />
(2) Multiply by a power of 10:<br />
How: Count number of decimal places that the decimal has "moved"<br />
from the original number. This will be the exponent of the 10.<br />
3 8 6 0 0 0 0<br />
6 5 4 3 2 1<br />
We have moved 6 places so the number (3.86) is multiplied by 10 6<br />
(3) If the original number was less than 1, the exponent is negative; if<br />
the original number was greater than 1, the exponent is positive.<br />
3,860,000 > 1, so the exponent is positive.<br />
Answer: 3.86 X 10 6<br />
74
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
On Your Own: Express in correct scientific notation:<br />
Standard Form Scientific Notation<br />
39,400<br />
0.0000394<br />
394<br />
39,400,000<br />
39.4<br />
0.394<br />
3,940<br />
0.00394<br />
3.94<br />
0.000394<br />
Place the following numbers in order, from smallest to largest:<br />
3.35 X 10 0 , 7.4 X 10 -2 , 1.6 X 10 -1 , 4.33 X 10 3 , 7.45 X 10 -3<br />
________ ________ ________ ________ _________<br />
75
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Converting from Scientific Notation to Standard Form:<br />
A. Positive Exponents<br />
• If exponent is positive, move decimal point to the right.<br />
• The exponent will determine how many decimals to move.<br />
Example: 3.45 X 10² = 345 (Move to the right 2 places)<br />
B. Negative Exponents<br />
• If exponent is negative, move decimal point to the left.<br />
• The exponent will determine how many decimals to move.<br />
Example: 3.45 X 10¯² = .0345 (Move to the left 2 places)<br />
On Your Own: Express in standard form:<br />
a. 3.45 x 10 -8<br />
• Since the exponent is negative, we move to the left.<br />
• Since the exponent is 8, we move to the left 8 places.<br />
Answer: ________________________________<br />
b. 5.3 X 10³ ______________<br />
c. 3. 5.3 X 10¯³ ______________<br />
d. 7.98 X 10¯ 4 ________________<br />
e. 7.98 X 10 5 ___________________<br />
76
Unit Review<br />
1. (3)¯² = _____<br />
2. (-3)² = _____<br />
3. -(3)² = _____<br />
3. (-3) 1 = _____<br />
4. (3) 1 = _____<br />
5. (3)¯ 1 = _____<br />
6. (3) 0 = _____<br />
7. (-3) 0 = _____<br />
8. -(3) 0 = _____<br />
9. 3 X 3 = _____<br />
CAHSEE on Target<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
77
10. (3 1 )² = _____<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
11. 3 ● 10¯= _____<br />
12. 3¯ ● 3= _____<br />
13. 3 3 ● 3 -6 = _____<br />
14.<br />
15.<br />
16.<br />
3 64 = _____<br />
4 16 = _____<br />
25<br />
= _____<br />
100<br />
17. 4 4 X 4 0 = _____<br />
−6<br />
3<br />
18. = _____<br />
−8<br />
3<br />
19. 4 -4 X 4 4 = _____<br />
78
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
20. Which shows the number 34,600,000 written in scientific<br />
notation?<br />
A. 346 X 10 5<br />
B. 34.6 X 10 6<br />
C. 3.46 X 10 7<br />
D. 3.46 X 10 -7<br />
E. 0.346 X 10 -8<br />
5<br />
3<br />
21. = _____<br />
− 1<br />
3<br />
3<br />
22. 1<br />
3<br />
−<br />
5<br />
= _____<br />
4<br />
4<br />
23. = _____<br />
− 1<br />
4<br />
−5<br />
4<br />
25. = _____<br />
−3<br />
4<br />
26. 5 3 ● 5 -2 = _____<br />
79
CAHSEE on Target<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Unit Quiz: The following problems appeared on the CAHSEE.<br />
3 ³<br />
1. { } = _______<br />
4<br />
9<br />
A.<br />
12<br />
9<br />
B.<br />
16<br />
27<br />
C.<br />
32<br />
27<br />
D.<br />
64<br />
1<br />
2. Solve for x: x³ =<br />
8<br />
A. x = 2<br />
B. x = 3<br />
1<br />
C. x =<br />
2<br />
1<br />
D. x =<br />
3<br />
3. Which number equals (2)¯ 4<br />
A. -8<br />
1<br />
B. −<br />
16<br />
1<br />
C.<br />
16<br />
1<br />
D.<br />
8<br />
80
4. 10 -2 = _____<br />
10 -4<br />
A. 10¯ 6<br />
B. 10¯²<br />
C. 10²<br />
D. 10<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
5. Between which two integers does 76 lie?<br />
A. 7 and 8<br />
B. 8 and 9<br />
C. 9 and 10<br />
D. 10 and 11<br />
6. The square of a whole number is between 1500 and 1600. The<br />
number must be between:<br />
A. 30 and 35<br />
B. 35 and 40<br />
C. 40 and 45<br />
D. 45 and 50<br />
7. The square root of 150 is between which two numbers?<br />
A. 10 and 11<br />
B. 11 and 12<br />
C. 12 and 13<br />
D. 13 and 14<br />
81
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
8. The radius of the earth’s orbit is 150,000,000,000 meters. What is<br />
this number in scientific notation?<br />
A. 1.5 X 10¯¹¹<br />
B. 1.5 X 10¹¹<br />
C. 15 X 10¹º<br />
D. 150 X 10 9<br />
9. 3.6 X 10² = ____<br />
A. 3.600<br />
B. 36<br />
C. 360<br />
D. 3,600<br />
10. (3 8 ) 2 = _____<br />
A. 3<br />
B. 3 6<br />
C. 3º<br />
D. 3 6<br />
11. 4³ X 4² = _____<br />
A. 4<br />
B. 4 6<br />
C. 16<br />
D. 16 6<br />
12. (x 2 ) 4 = _____<br />
A. x 6<br />
B. x<br />
C. x 6<br />
D. x²<br />
82
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Unit 3: Multi-Step Word Problems<br />
Some problems involve more than one step. These are called multistep<br />
problems. On the CAHSEE you can expect to get at least a few<br />
multi-step problems.<br />
Example: The following problem appeared on the CAHSEE.<br />
The five members of a band are getting new outfits. Shirts cost $12<br />
each, pants cost $29 each, and boots cost $49 a pair. What is the<br />
total cost of the new outfits for all the band members?<br />
To solve this kind of problem, we must follow some basic steps:<br />
A. First, determine what the question asks: Total cost for all band<br />
members<br />
B. Write down all of the numerical information given in the problem:<br />
• 5 members in band<br />
• Shirts @ $12 each<br />
• Pants @ $29 each<br />
• Boots @ $49 each<br />
C. Determine the operations required to solve the problem. In other<br />
words, what do we do with all of the numbers listed in step 2?<br />
• Multiply each item bought by 5 since there are 5 members and<br />
each item is required for each member:<br />
Shirts: 12 X 5 = ________<br />
Pants: 29 X 5 = ________<br />
Boots: 49 X 5 = ________<br />
• Add it all up (listing biggest numbers first):<br />
Answer: The total cost of the band’s outfits is _______.<br />
83
On Your Own<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
1. Derrick wants to buy a sweater that costs $46. If he has $22 saved<br />
up and earns $12 a week in allowance, how long will it take before<br />
he has enough money to buy the sweater?<br />
Steps:<br />
A. What does the question ask: _______________________________<br />
______________________________________________________<br />
B. Write down all of the information that is important:<br />
• _______________________<br />
• _______________________<br />
• _______________________<br />
C. Determine the operations required to solve the problem and then<br />
apply these operations to solve the problem.<br />
• The sweater costs $46, but he already has $22. How much more<br />
money does he need? Which operation is required to answer<br />
this question? _________________<br />
Solve:<br />
• Now that we know how much more money Derrick needs, all we<br />
have to do is to figure out how many weeks it will take to earn<br />
this amount. Which operation is required to answer this<br />
question? _____________<br />
Solve:<br />
Answer: Derrick can buy the sweater in ___ weeks.<br />
84
CAHSEE on Target<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
2. Uncle Bernie took his three nieces to the movies. Each niece<br />
ordered a small popcorn, a large soda, and a chocolate bar. If a<br />
small order of popcorn costs $4, a large soda costs $3, and a<br />
chocolate bar costs $1.50, how much did Uncle Bernie spend on<br />
snacks?<br />
3. Cynthia wants to buy a pair of jeans that cost $56, including tax.<br />
If she earns $10.50 each week for allowance and spends $3.50<br />
per week on bus fare to and from her dance lessons, what is the<br />
fewest number of weeks that it will take Cynthia to save enough<br />
money to buy the jeans?<br />
85
CAHSEE on Target<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Extraneous Information<br />
Sometimes there may be information in the problem that you don’t<br />
need. It may be there to confuse you. Whenever you come to<br />
information that is extraneous (i.e., don’t need it, don’t want it),<br />
cross it out:<br />
Example: Daphne, Cynthia, and Rachel went to the movies on<br />
October 21. October 21 fell on a Friday. The movie began at 8:00<br />
p.m. They each bought a bucket of popcorn and a snickers bar. If<br />
each movie ticket costs $8.00, a bucket of popcorn costs $4.00, and a<br />
snickers bar costs $2.50, how much money did they spend altogether?<br />
Steps:<br />
• Cross out any information that you don’t need. Don’t just ignore it<br />
- - cross it out.<br />
Daphne, Cynthia, and Rachel went to the movies on October 21.<br />
October 21 fell on a Friday. The movie began at 8:00 p.m. They each<br />
bought a bucket of popcorn and a snickers bar. If each movie ticket<br />
costs $8.00, a bucket of popcorn costs $4.00, and a snickers bar costs<br />
$2.50, how much money did they spend altogether?<br />
• Write down all of the information that is important:<br />
3 people<br />
Tickets $8.00 each<br />
Popcorn $4.00 each<br />
Snickers $2.50 each<br />
• Figure out how much one person spent:<br />
8 + 4 + 2.50 = ______<br />
• Figure out how much all three people spent:<br />
_____ ● 3 = _____<br />
86
On Your Own<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
1. Matthew bought a used car for $800. The car was 15 years old. He<br />
wrote a check for $520 and gave the salesman $125 in cash. The<br />
rest he promised to pay at the end of the week, when he would be<br />
receiving a paycheck for $385. How much does he owe on the car?<br />
• Cross out any information that you don’t need. Don’t just<br />
ignore it - - cross it out. That way you will be sure that you<br />
don’t accidentally slip it in later.<br />
• Now write down all of the information that is important:<br />
_____________________________________________<br />
_____________________________________________<br />
_____________________________________________<br />
• How much did Matthew already pay? ____________<br />
• How much more does he owe? _________<br />
2. Mrs. Brown took her four children out to the pizza party. She and<br />
her children each ordered a small pepperoni pizza and a large soda.<br />
A small vegetarian pizza costs $4.50, while a small pepperoni pizza<br />
costs $5.25. Small sodas cost $2.00, medium sodas cost $2.50,<br />
and large sodas cost $3.25. How much did Mrs. Brown spend at<br />
the pizza party?<br />
87
Unit Quiz<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
1. Martine bought 3 cans of soda for 65¢ each, 2 pretzels for $1.25<br />
each and a slice of pizza for $1.75. She paid with a $20 bill. How<br />
much change should she get back from the cashier?<br />
2. Joy spent 25% of her weekly paycheck to help her sister buy a new<br />
dress. If the dress costs $235 and her paycheck is $450, how<br />
much does she have left for the week?<br />
3. If it costs $150 to feed a family of four for the week, how much will<br />
it cost to feed a family of six?<br />
4. Adrienne has $166 left in her checking account and $1300 in her<br />
savings account. Each week she earns $175 as a cashier at the<br />
Five and Dime Store. She is planning on buying a set of dishes for<br />
her best friend’s wedding shower. The set costs $500. If she does<br />
not take any money out of her savings account, what is the fewest<br />
number of weeks that she must work in order to buy the dishes?<br />
88
Unit 4: Percent<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
On the CAHSEE, you will have many problems that involve percent.<br />
(Note: Some of these will be word problems.)<br />
Percent of a <strong>Number</strong><br />
Percent, written as %, literally means "out of 100." Any number<br />
expressed as a percent stands for a fraction.<br />
Example: Five percent (or 5%) means 5 out of 100. As a fraction,<br />
this is written as 5/100, which can be reduced to 1/20. This can<br />
also be expressed as a decimal: .05 (read as five hundredths).<br />
Example: Seventy-five percent (75%) means 75 out of 100, or<br />
75/100. This fraction can be reduced to 3/4. As a decimal, 75%<br />
would be written as 0.75, which means 75 hundredths.<br />
Converting from Percent to Decimal<br />
To change a percent to a decimal, divide the percent value by 100:<br />
move the decimal point two places to the left.<br />
Examples:<br />
17% = .17<br />
3% = .03<br />
80% = .80 (or .8)<br />
125% = 1.25<br />
.8% = .008<br />
3.4% = .034<br />
46% = 0.46<br />
89
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Converting from Decimal to Percent<br />
To change a decimal to a percent, move the decimal point two places<br />
to the right. (Multiply by 100!)<br />
Examples:<br />
.34 = 34% .09 = 9% 2.3 = 230% .6 = 60% 0.125 = 12.5%<br />
Practice: Fill in the following chart. Reduce fractions to lowest terms.<br />
Fraction Decimal Percent<br />
9<br />
100<br />
9<br />
10<br />
1<br />
4<br />
0.08<br />
0.8<br />
0.84<br />
35%<br />
95%<br />
60%<br />
90
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Solving Percent Problems<br />
There are two methods for solving percent problems. The first is<br />
setting up a proportion.<br />
Method 1: Proportion<br />
A proportion is two equivalent ratios, written as fractions. In<br />
any proportion, the product of the means is equal to the product<br />
of the extremes:<br />
We see that this is true: 3 ● 10 = 30 and 5 ● 6 = 30<br />
The product of the means is equal to the product of the extreme.<br />
We can solve a percent problem by setting up a proportion. Here is<br />
the proportion used to solve percent problems:<br />
Part x<br />
=<br />
Whole 100<br />
This proportion may be translated as follows: The part is to the whole<br />
as what number is to 100?"<br />
And, since in a proportion, the product of the means is equal to the<br />
product of the extremes, the following is also true:<br />
Whole ● x = Part ● 100<br />
This relationship will always be true for a proportion. Since we<br />
multiply diagonally across the proportion, people often use the term<br />
"cross multiplying" for short (since it can be encumbering to keep<br />
saying, "The product of the means is equal to the product of the<br />
extremes." You can use the term "cross-multiplication" if you like;<br />
just remember the concept that is behind it.<br />
91
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Let's solve a percent problem together, using the proportion method:<br />
Example: 23 is what percent of 50?<br />
23 x<br />
=<br />
50 100<br />
50x = 2300 ← ⎯⎯ Now divide to solve for x.<br />
x = ___<br />
23<br />
Answer: is equal to ___%<br />
50<br />
On Your Own: Use the method of cross multiplication to solve for x.<br />
x 5<br />
1. =<br />
20 100<br />
92
4 x<br />
2. =<br />
25 100<br />
18 x<br />
3. =<br />
20 100<br />
7 x<br />
4. =<br />
10 100<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
93
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Let's look at more examples of percent problems solved with the<br />
proportion method:<br />
Example: 18 is what percent of 50?<br />
• Set up a proportion:<br />
Part x<br />
=<br />
Whole 100<br />
Note: The term 50 is the "whole" and 18 is the "part":<br />
18 x<br />
Proportion: =<br />
50 100<br />
• Cross multiply: 50x = 1800<br />
1800<br />
• Isolate x by dividing by 50: x = = ____<br />
50<br />
Example: What is 25% of $60?<br />
x 25<br />
• Set up a proportion: =<br />
60 100<br />
Note: The term 60 is the "whole" and the problem asks for 25%<br />
of this whole:<br />
• Cross multiply: 100x = 1500<br />
1500<br />
• Find x: x = = -----<br />
100<br />
94
On Your Own<br />
CAHSEE on Target<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
1. 25% of what number is 15?<br />
15 25<br />
• Set up a proportion: =<br />
x 100<br />
Note: The term 15 is the "part" and the problem asks for 25% of<br />
the whole:<br />
• Cross multiply: __________________<br />
• Find x: _______________________<br />
2. 30 is what percent of 50?<br />
3. What is 45% of 90?<br />
4. 30% of what number is 60?<br />
95
CAHSEE on Target<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Method 2: Translate & Compute<br />
In this method, we translate the problem into an algebraic equation<br />
and then solve. Let's look at the previous problems again, this time<br />
using this second method:<br />
Example: 18 is what percent of 50?<br />
• Translate:<br />
18 is what percent of 50?<br />
x<br />
18 = ● 50<br />
100<br />
50x<br />
• Compute: 18 =<br />
100<br />
18 = 1 50x ← ⎯⎯ Simplify all fractions<br />
2100<br />
x<br />
18 =<br />
2<br />
18 ● 2 = x ● 2 1 ← ⎯⎯ Multiply both sides by 2.<br />
12<br />
x = ___ Answer: 18 is __% of 50.<br />
Note: This method can also be used as a complement to Method 1<br />
and as way to verify the answers you arrived at using Method 1.<br />
96
On Your Own<br />
CAHSEE on Target<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
1. What is 25% of $60?<br />
• Translate:<br />
What is 25 percent of 60?<br />
___ ___ ____ ___ ___<br />
• Compute:<br />
2. 25% of what number is 15?<br />
• Translate:<br />
25 percent of what number is 15?<br />
____ ___ ___ ___ ___<br />
• Compute:<br />
97
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
3. 15% of what number is 30?<br />
4. 35 is what percent of 80?<br />
5. What is 15% of 90?<br />
6. 15 is what percent of 80?<br />
98
CAHSEE on Target<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Practice: Use either method to solve the percent problems below.<br />
1. On average, every 16 out of 200 students study Calculus. What<br />
percent study Calculus?<br />
2. If 150 people were surveyed in the 2004 presidential elections and<br />
90 of those people said that they were going to vote for John Kerry,<br />
find the percent of Kerry supporters in the sample population?<br />
3. The Brighton Movie Theater sells the following candies at their<br />
snack bar: Snickers Candy Bars, Peanut Clusters, O’Henry Bars,<br />
M & M’s, and Milky Way Bars. Currently, there are 10,000 candies<br />
in stock. The following chart below shows a percentage breakdown<br />
of each type of candy in stock. Find the actual number of each type<br />
of candy:<br />
Candy <strong>Number</strong><br />
Snickers: 5%<br />
Peanut Clusters: 15%<br />
O’Henry: 20%<br />
M & M’s: 25%<br />
Milky Way Bars: 35%<br />
4. What is the fractional equivalent of 95% (reduced to lowest terms)?<br />
99
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
5. Four months of the year have 30 days. Which percentage most<br />
closely represents the months that do not have 30 days?<br />
A. 33%<br />
B. 44%<br />
C. 66%<br />
D. 75%<br />
12<br />
6. What is the percentage equivalent of ?<br />
15<br />
7. In Mr. Martin’s class, 9 of the 27 students in Mr. Martin’s class<br />
received a B+ or higher on the Algebra quiz. What percent of the<br />
students received a grade of B or lower?<br />
4<br />
8. What is expressed as a percent?<br />
5<br />
9. What is 0.80 expressed as a fraction (in simplest terms)?<br />
100
CAHSEE on Target<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Percent Increases & Decrease<br />
Often, when we compare one entity across time (such as changes<br />
in population or the price of a particular item), we express these<br />
changes in terms of percent. The percent of change is the ratio of<br />
the amount of change to the original amount.<br />
Ratio: How much it went up or down<br />
The original amount<br />
An easy way to solve percent increase & percent decrease problems is<br />
to set up a proportion that consists of two ratios, the one above and<br />
a second one for the percent. Remember that “percent” is always a<br />
ratio and the denominator of that ratio is always 100.<br />
What<br />
So the second ratio looks like this:<br />
Percent<br />
x<br />
or<br />
100<br />
If you set up a proportion using these two ratios, you get the<br />
following:<br />
How much it went up or down = x_<br />
The original amount 100<br />
All you need to do after that is cross multiply and isolate the x value.<br />
Let's look at an example on the next page.<br />
101
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Example: Jimmy got a raise from $6.00 to $8.00 per hour. This<br />
represents a raise of what percent?<br />
Steps:<br />
• Find out how much it went up or down and place this number<br />
over the original amount:<br />
2 ← ⎯⎯ It went up $2<br />
6 ← ⎯⎯ Original amount is $6.00<br />
• Set up proportion:<br />
2 x<br />
=<br />
6 100<br />
• Cross multiply:<br />
• Solve for x:<br />
• Express answer as a percent: _________<br />
Make sure you use the original amount as the denominator!<br />
102
Alternative Method<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
You can also solve the previous problem by setting up an equation:<br />
Change = What Percent of Original Amount<br />
Let's look at the problem again:<br />
Example: Jimmy got a raise from $6.00 to $8.00 per hour. This<br />
represents a raise of what percent?<br />
Now plug the values in the equation:<br />
Change = What Percent of Original Amount<br />
x<br />
2 = ● 6<br />
100<br />
Now solve:<br />
x<br />
2 = (6)<br />
100<br />
103
On Your Own<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
1. Tasty Delight raised their prices on ice cream sundaes from $5.00<br />
to $7.00. This represents an increase of what percent?<br />
x<br />
• Set up proportion: ____=<br />
100<br />
• Cross multiply: _________________<br />
• Solve for x: _____________________<br />
• Express answer as a percent: ________<br />
Note: Be sure to use the original amount as the denominator!<br />
Now solve the above problem using the alternative method:<br />
Plug in values:<br />
Change = What Percent of Original Amount<br />
____ ____ ___ ______<br />
Solve:<br />
104
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
2. A shirt that costs $40 in 1999 costs $60 in 2005. What is the<br />
percent increase? (Use either method to solve.)<br />
Solve:<br />
Percent Increase: _______________<br />
What would be a trick answer on the CAHSEE? _____________<br />
3. Elizabeth’s basketball card collection increased in value from $500<br />
to $1,000. What is the percent increase? (Use either method to<br />
solve.)<br />
Solve:<br />
Percent Increase: _______________<br />
What would be a trick answer on the CAHSEE? ____________<br />
105
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
4. Jordy’s basketball card collection decreased in value from $1,000 to<br />
$500. What is the percent decrease?<br />
Solve:<br />
Percent Decrease: ____________________<br />
What would be a trick answer on the CAHSEE? _______________<br />
5. Last year Andrea had 36 students in her class. This year she only<br />
has 27. What is the percent decrease?<br />
Solve:<br />
Percent Decrease: ______________________<br />
What would be a trick answer on the CAHSEE? _______________<br />
6. If a shirt that costs $80 last year is worth only 75% as much this<br />
year, what is the current value of the shirt?<br />
Solve:<br />
Answer: _________<br />
106
Price Discounts<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Stores will often sell items for a discounted sales price. The store will<br />
discount an item by a percent of the original price. To find the amount<br />
of a discount (in dollars), simply multiply the original price by the<br />
percent discount.<br />
Example: An item, which originally cost $20, was discounted by 25%.<br />
Find the discount in dollars?<br />
Steps:<br />
• Translate the problem into math:<br />
25<br />
25% of $20 = ● 20<br />
100<br />
• Calculate:<br />
25<br />
● 20 = $5.00 (or ¼ ● 20 = 5)<br />
100<br />
The item was sold for $5.00 less than its original price.<br />
Terms you may see for discounted items:<br />
• 50% Off<br />
• Save 50%<br />
• Discounted by 50%<br />
107
On Your Own<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
1. A transistor radio is normally sold for $80 at Karter Electric Goods.<br />
This week, it is being offered at a 20% discount. How much<br />
cheaper is the radio this week?<br />
2. A dress, which sold for $80 last week, is on sale for 20% off. This<br />
represents a discount of how much (in dollars)?<br />
3. At Peppy’s Pizza, a small pepperoni pizza normally sells for $6.00.<br />
This week, the store is offering a 25% discount on all small pizzas.<br />
How much cheaper is the pizza this week?<br />
108
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Note: Many price discount questions on the CAHSEE ask you to find<br />
the new price, not the amount of discount. This involves one<br />
more important step.<br />
Example: An item originally cost $20 and was discounted by 25%.<br />
What was the new sales price?<br />
Steps:<br />
25<br />
• Translate the problem into math: 25% of $20 = ● 20<br />
100<br />
• Calculate the discount in dollars:<br />
25<br />
● 20 = $5.00 (or ¼ ● 20 = 5)<br />
100<br />
The item was sold for $5.00 less than its original price.<br />
• Finally, to find the new sales price, subtract the amount of discount<br />
from the original price:<br />
$20.00-$5.00=$15.00<br />
CAHSEE Alert! Don’t forget this last step. If this were an actual item<br />
on the exam, $5.00 (the amount of discount) would probably be one of<br />
the answer choices. If you are working out a problem that has multiple<br />
steps, remember to do all of the steps to get the right answer.<br />
109
On Your Own<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
1. A dress, which sold for $80 last week, is on sale for 20% off. What<br />
is the new price of the dress?<br />
Solve:<br />
New Price: ________<br />
What would be a trick answer on the CAHSEE? ____________<br />
2. At Peppy’s Pizza, a small pepperoni pizza normally sells for $6.00.<br />
This week, the store is offering a 25% discount on all small pizzas.<br />
How much does a small pepperoni pizza cost this week?<br />
Solve:<br />
New Price: ________<br />
What would be a trick answer on the CAHSEE? ___________<br />
3. Rain boots regularly sell for $70 a pair. They are currently on sale<br />
for 40% off. What is the sale price of the boots?<br />
Solve:<br />
New Price: ________<br />
What would be a trick answer on the CAHSEE? ___________<br />
110
Markups<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Stores buy items from a wholesaler or a distributor and increase the<br />
price when they sell them to consumers. The increase in price provides<br />
money for the operation of the store and the salaries of people who<br />
work in the store. A store may have a rule that the price of a certain<br />
type of item needs to be increased by a certain percentage. This<br />
percentage is called the markup.<br />
A. Two-Step Method<br />
1. Find the markup in dollar amount:<br />
Original Cost ● Percent of Markup<br />
2. Add this dollar amount to the original price.<br />
Markup in $ + Original Price<br />
Example: A merchant buys an item for $4.00 and marks it up by<br />
25%. How much does he charge for the item?<br />
1. Find the markup in dollars:<br />
$4.00 ● .25 = $1.00 Or . . .<br />
1<br />
4 ● = 1<br />
4<br />
2. Add this dollar amount to the original price:<br />
$4.00 + 1.00 = $5.00<br />
CAHSEE Alert! Like the discount problems, be careful not to forget<br />
the last step. In the above problem, a probable answer choice would<br />
be $1.00. Don’t be fooled! Read the question carefully.<br />
111
CAHSEE on Target<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
B. One-Step Method<br />
A faster way to calculate the sales price is to make the original cost<br />
equal to 100%.<br />
Example: A merchant buys an item for $4.00 and marks it up by<br />
25%. How much does he charge for the item?<br />
Since the markup is 25%, the customer pays 125% of the original<br />
cost. Multiply the original cost by 125% (or 1.25):<br />
$4.00 ● 1.25 =<br />
(4 ● 1) + (4 ● .25) =<br />
4 + 1 = $5.00 The merchant charges $5.00 for the item.<br />
CAHSEE Alert! Some questions on the CAHSEE may ask for the<br />
dollar amount of the markup, not the final sales price.<br />
Example: Harry’s Bargain Basement has a 20% markup on all its<br />
goods. If the manufacturer price of irons is $16, how much extra<br />
does the customer pay for each iron?<br />
Solve: _____________________________________________<br />
Compare with this problem:<br />
Harry’s Bargain Basement has a 20% markup on all its goods. If the<br />
manufacturer price of irons is $16, how much does the customer pay<br />
for an iron?<br />
Solve: _____________________________________________<br />
Note: On the CAHSEE, be sure to read the question carefully to<br />
determine whether it is asking for the markup or final sales price.<br />
112
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
On Your Own: Read each problem carefully and determine what the<br />
question is asking. Then solve the problem.<br />
1. The original cost of a dress is $12.00. (This is the amount that the<br />
store paid the manufacturer.) The store marks up all their items by<br />
20%. How much does the store charge for the dress?<br />
2. Bill’s Auto Supplies buys tires for $80. If the store sells its tires for<br />
$100, what is its percent markup?<br />
3. All items at Bargain Slim’s have been marked up by 40%. If the<br />
store paid $12 for each CD, how much does the customer pay?<br />
4. A stainless steel refrigerator is bought for $500 and then marked up<br />
by 100%. What is the new price of the refrigerator?<br />
113
Commissions<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Sales commissions are often paid to employees who sell merchandise<br />
or products. Commissions serve to motivate salespersons to sell a lot.<br />
A commission is generally a percentage of the total sales made by<br />
a salesperson. To find the commission, just multiply the value of<br />
the total sales by the commission rate. It is that simple!<br />
Example: A salesman receives a 10% commission on all sales. If he<br />
sells $1500 worth of merchandise, how much does he earn in<br />
commission?<br />
$1,500 X 0.10 = $150<br />
or<br />
$1500 X 10_ = 15 X 10 = $150<br />
100<br />
On Your Own<br />
1. Sarah is a real estate agent. She earns 12% commission on every<br />
house she sells. Sarah recently sold a house for $400,000. What<br />
was her commission?<br />
2. Ronald is a salesman in the men’s department at Bloomingdale’s<br />
Department Store. He earns 15% on all sales. His total sales for<br />
the month of August came to $80,000. How much did he earn in<br />
commission?<br />
7. Alvin Ray sells used cars at Kaplan’s Auto Dealer. His commission<br />
rate is 30%. What was his commission on the used Audi he sold for<br />
$36,000?<br />
114
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Unit Quiz: The following questions appeared on the CAHSEE.<br />
1. At a recent school play, 504 of the 840 seats were filled. What<br />
percent of the seats were empty?<br />
A. 33.6%<br />
B. 40%<br />
C. 50.4%<br />
D. 60%<br />
2. Some of the students attend school 180 of the 365 days in a year.<br />
About what part of the year do they attend school?<br />
A. 18%<br />
B. 50%<br />
C. 75%<br />
D. 180%<br />
3. What is the fractional equivalent of 60%?<br />
1<br />
A.<br />
6<br />
3<br />
B.<br />
6<br />
3<br />
C.<br />
5<br />
2<br />
D.<br />
3<br />
115
CAHSEE on Target<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
4. If Freya makes 4 of her 5 free throws in a basketball game, what is<br />
her free throw shooting percentage?<br />
A. 20%<br />
B. 40%<br />
C. 80%<br />
D. 90%<br />
5. Between 6:00 AM and noon, the temperature went from 45° to 90°.<br />
By what percentage did the temperature increase between 6:00 AM<br />
to noon?<br />
A. 45%<br />
B. 50%<br />
C. 55%<br />
D. 100%<br />
6. The price of a calculator has decreased from $12.00 to $9.00.<br />
What is the percent of decrease?<br />
A. 3%<br />
B. 25%<br />
C. 33%<br />
D. 75%<br />
7. The cost of an afternoon movie ticket last year was $4.00. This<br />
year an afternoon movie ticket costs $5.00. What is the percent<br />
increase of the ticket from last year to this year?<br />
A. 10%<br />
B. 20%<br />
C. 25%<br />
D. 40%<br />
116
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
8. A pair of jeans regularly sells for $24.00. They are on sale for 25%<br />
off. What is the sales price of the jeans?<br />
A. $6.00<br />
B. $18.00<br />
C. $20.00<br />
D. $30.00<br />
9. A CD player regularly sells for $80. It is on sale for 20% off. What<br />
is the sales price of the CD player?<br />
A. $16<br />
B. $60<br />
C. $64<br />
D. $96<br />
10. Mr. Norris is paid a 5% commission on each house that he sells.<br />
What is his commission on a house that he sells for $125,000?<br />
A. $625<br />
B. $6,250<br />
C. $62,500<br />
D. $625,000<br />
117
Unit 5: Interest<br />
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
On the CAHSEE, you may be asked several questions on interest.<br />
These questions will cover both simple interest and compound interest.<br />
Introduction to Interest<br />
Did you know that money can make more money? Whenever money is<br />
invested or borrowed, additional funds, called interest, are<br />
charged for the use of that money for a certain period of time. When<br />
the money is paid back, both the principal (amount of money that<br />
was borrowed) and the interest are due.<br />
If you invest money in the bank, the bank is borrowing the money and<br />
the interest is paid to you. On the other hand, when you take out a<br />
loan, you are borrowing the money and you must pay the interest.<br />
Interest can be simple or compound:<br />
Simple interest is generally used when borrowing or investing money<br />
for short periods of time.<br />
Compound interest is generally used when borrowing or investing<br />
money for longer periods of time. We will learn about compound<br />
interest later.<br />
Interest depends on three things:<br />
1. Principle (P): The amount you invest or borrow; principle is<br />
expressed in dollars.<br />
2. Interest Rate (R): How much it costs you to borrow the money or<br />
how much you gain by investing your money; this rate is always<br />
expressed as a percent in the problem, although you may convert<br />
the rate to a decimal during computation.<br />
3. Time (T): How long you borrow the money or how long you invest<br />
your money; this time is always expressed in number of years<br />
118
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Converting to Years<br />
When calculating interest, time is expressed in years. If the period<br />
of time is given in months, you must first convert it to the number of<br />
years.<br />
Examples:<br />
1<br />
6 months is year, or .5 year.<br />
2<br />
3<br />
18 months is years, or 1.5 years.<br />
2<br />
Working with Improper Fractions<br />
We will see that, when calculating interest, it is easiest to work with<br />
improper fractions than with mixed numbers.<br />
Mixed <strong>Number</strong>s: A mixed number consists of both a whole integer<br />
and a fraction.<br />
1<br />
1 is a mixed number because it consists of a whole number (1) and<br />
4<br />
1<br />
a fraction .<br />
4<br />
Improper Fractions: An improper fraction is one in which the<br />
numerator is greater than the denominator.<br />
4<br />
5 is an improper fraction because the numerator (5) is greater than<br />
the denominator (4).<br />
119
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Converting Mixed <strong>Number</strong>s to Improper Fractions<br />
To convert a mixed number to an improper fraction, follow these<br />
steps:<br />
• Multiply the whole number by the denominator of the fraction.<br />
• Add the numerator of the fraction to the product found above.<br />
• Place the result over the fraction's denominator.<br />
1<br />
Example: Convert 1 to an improper fraction.<br />
4<br />
• Multiply the whole number by the denominator of the fraction:<br />
1 ● 4 = 4<br />
• Add the numerator of the fraction to the product found in Step 1:<br />
4 + 1 = 5<br />
• Place the result over the fraction's denominator:<br />
5<br />
4<br />
3<br />
On Your Own: Convert 1 to a mixed fraction.<br />
5<br />
120
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Practice: Express each time interval below in years. Express as both<br />
a fraction (reduced to lowest terms) and a decimal.<br />
Note: Be sure to covert any mixed number to an improper fraction.<br />
Months Years: Fraction Years: Decimal<br />
3 months<br />
4 months<br />
8 months<br />
27 months<br />
15 months<br />
9 months<br />
21 months<br />
1 year and 8<br />
months<br />
121
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Converting to Percents & Decimals<br />
The interest rate is expressed as a percent or as a decimal.<br />
Examples:<br />
5<br />
5% = = 0.05<br />
100<br />
8.<br />
5<br />
8½% =<br />
100<br />
= 0.085<br />
x<br />
On Your Own: Express as both a percent ( ) and a decimal.<br />
100<br />
Rate Percent Decimal<br />
12%<br />
20%<br />
3%<br />
18%<br />
9½%<br />
12½%<br />
122
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Solving Simple Interest Problems<br />
To solve simple interest problems, just apply the formula:<br />
Principle ● Rate ● Time<br />
We can abbreviate this as follows: P ● R ● T<br />
Note: Be sure to learn this formula for the CAHSEE!<br />
One Step-Problems<br />
One-step problems ask you to find the interest (in dollars and cents)<br />
earned (from an investment) or owed (on a loan). Just apply the<br />
formula for interest:<br />
One-step problems ask you to find the interest (in dollars and cents)<br />
earned (from an investment) or owed (on a loan). Just apply the<br />
formula for interest:<br />
Principle ● Rate ● Time<br />
Note: Be sure to convert all terms to their correct units:<br />
• Rate in % or decimal<br />
• Time in years<br />
Example: $500 invested for 6 months in an account paying 7%<br />
interest. How much is earned in interest?<br />
To solve, simply plug the correct values into the equation and do the<br />
computation:<br />
Principle ● Rate ● Time<br />
$500 ● 0.07 ● 0.5 = _______ OR<br />
500 ● 7_ ● 1 = ______<br />
100 2<br />
123
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Fractions and Interest Problems<br />
As we mentioned earlier, when solving interest problems, it is easier to<br />
work with improper fractions than with mixed numbers.<br />
Example: Shawn invests $4,000 at 16%. How much does he earn in<br />
15 months?<br />
Let's solve this problem by expressing 15 months as an improper<br />
fraction. (Note: It is much easier to multiply with improper fractions<br />
than with mixed numbers.)<br />
There are 12 months in 1 year; we have 15 months:<br />
15<br />
← ⎯⎯ Improper fraction: Denominator > numerator<br />
12<br />
15 5<br />
We can reduce this fraction: =<br />
12 4<br />
Now let's solve the problem:<br />
P ● R ● T<br />
4000 ● 16 ● 5 =<br />
100 4<br />
4,000 ● 4 16 ● 5 =<br />
100 41<br />
40 ● 20 = ____<br />
124
CAHSEE on Target<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
On Your Own: Plug the correct values and solve:<br />
1. $1,500 is borrowed at an interest rate of 3 percent for 20 years.<br />
How much is earned in interest?<br />
P = __________<br />
R = __________<br />
T = __________<br />
P ● R ●T = _______________________________<br />
2. $5,000 is invested for 24 months in an account paying 6% interest.<br />
How much is earned in interest.<br />
P = __________<br />
R = __________<br />
T = __________<br />
P ● R ●T = _______________________________<br />
3. Drew earns 6% in simple interest. If he invests $8,000 in a bank<br />
account, how much interest will he have earned after 18 months?<br />
Note: In each of the above questions, we are asked to find the<br />
interest earned, rather than the value of the entire investment. We will<br />
now learn to add the interest to the principle.<br />
125
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Two-Step Problems<br />
On the CAHSEE, you may be asked to find the value of the entire<br />
investment. For these problems, there is one additional step.<br />
Example: Marianne invested $5,000 in the bank at an annual interest<br />
rate of 8 ½ percent. How much will her investment be worth in two<br />
years?<br />
• Find the amount of interest earned:<br />
P ● R ● T<br />
8.<br />
5<br />
5,000 ● ● 2 = _______________________<br />
100<br />
• Add the interest to the principle to get the value of the investment:<br />
5,000 + _______ = $ ________<br />
On Your Own:<br />
1. Rachel invests $3,000 at 12%. How much will her investment be<br />
worth in 15 months?<br />
• Plug the values into the formula and compute interest earned:<br />
• Add interest to principal:<br />
3000 + ___ = ____<br />
126
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
2. Amy has a bank account that pays an annual interest rate of 7%<br />
(simple interest). If she has $7,000 in principal, how much interest<br />
will she earn this year?<br />
3. Denise earns 8% in simple interest each year. If she now has $900<br />
in her savings account, what will be the value of her savings<br />
account in six months?<br />
4. Emily has invested $15,000 at Chase Manhattan Bank. If her<br />
current rate of interest is 8%, how much interest will she have<br />
earned in nine months?<br />
5. Refer back to the previous problem. What will be the total value of<br />
Emily’s investment after nine months?<br />
127
CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Compound Interest<br />
While simple interest is paid once per year, compound interest can be<br />
paid twice a year (semi-annually), four times a year (quarterly) or<br />
even monthly!<br />
Example: Peter invests $500 in a savings account. The bank pays<br />
10% annual interest, compounded twice a year. What is the value of<br />
Peter’s investment after one year?<br />
Steps:<br />
• How much does Peter earn after 6 months? Not 10% because that<br />
is what he earns annually. 10% annual interest compounded twice<br />
a year means that half of the interest is paid after 6 months (half of<br />
the year) and the other half is paid at the end of the year. Since six<br />
months is one-half of a year, Peter only earns half of 10%, or 5%,<br />
after six months.<br />
Calculate 5% of $500: _5 ● 500 = $25.<br />
100<br />
• Add this to the principle to find the total value of his investment<br />
after six months:<br />
$500 + $25 = $525<br />
• For the next six months, Peter will earn 5% on $525. Calculate the<br />
interest:<br />
5% ● ____ = ______<br />
• Add this amount to the value of his investment after one year:<br />
______ + _____ = ________<br />
128
CAHSEE on Target<br />
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Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
CAHSEE Tip: Since the math section of the CAHSEE uses a multiple-<br />
choice format, you can automatically rule out certain choices on<br />
compound interest problems:<br />
• We know that compound interest is always greater than simple<br />
interest; therefore, you can cross out any answers that are less<br />
than or equal to the amount calculated for simple interest.<br />
• At the same time, the answer will be only slightly greater than<br />
the amount obtained under simple interest since CAHSEE compound<br />
interest problems will generally be limited to one year (the<br />
difference between the interest earned under simple and compound<br />
interest gets bigger with each year); therefore, you can cross out<br />
answers that are significantly greater than that obtained under<br />
simple interest.<br />
See if you can apply this strategy for the following two problems.<br />
1. Ellie invested $3,000 in a savings account that pays an annual<br />
interest rate of 6% compounded twice a year. How much will she<br />
have in the bank after one year?<br />
A. $3,000.00<br />
B. $3,180.00<br />
C. $3,182.70<br />
D. $3,600<br />
2. Drew has invested $10,000 at Bank of America. His current rate of<br />
interest is 5%, compounded twice a year. How much interest will he<br />
have earned in one year?<br />
A. $10, 756.25<br />
B. $10,506.25<br />
C. $10,256.25<br />
D. $10,500<br />
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CAHSEE on Target<br />
UC Davis, School/University Partnerships<br />
Student Workbook: <strong>Number</strong> <strong>Sense</strong> Strand<br />
Unit Quiz: The following questions appeared on the CAHSEE.<br />
1. Sally puts $200 in a bank account. Each year the account earns<br />
8% simple interest. How much interest will she earn in three<br />
years?<br />
A. $16.00<br />
B. $24.00<br />
C. $48.00<br />
D. $160.00<br />
2. Mr. Yee invested $2000 in a savings account that pays an annual<br />
interest rate of 4% compounded twice a year. If Mr. Yee does not<br />
deposit or withdraw any money, how much will he have in the bank<br />
after one year?<br />
A. $2,080.00<br />
B. $2,080.80<br />
C. $2,160.00<br />
D. $2,163.20<br />
Note: See if you can solve this problem by applying the multiplechoice<br />
strategy for compound interest problems.<br />
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