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the development of poiseuille flow of a pseudoplastic fluid

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M.A.M. Al Khatib<br />

respectively. Examples <strong>of</strong> <strong>the</strong> eigenvalues for <strong>the</strong> Newtonian case are given in Table 1. These eigenvalues are <strong>the</strong><br />

same obtained by Wilson [1].<br />

Note that if we work out <strong>the</strong> same <strong>the</strong>ory for <strong>the</strong> power law model, <strong>the</strong>n θ◦ and µ◦ are given by<br />

θ◦ = k 1−1/n |y| 1−1/n and µ◦ = nθ◦,<br />

and <strong>the</strong> equation corresponding to (3.15) is given by<br />

Φ iv +(4r − 2)α 2 Φ ′′<br />

+ α 4 Φ+ 2<br />

<br />

(1 − r) Φ<br />

Y ′′′<br />

+(2r− 1)α 2 Φ ′<br />

+ r<br />

(r − 1)(Φ′′ − α<br />

Y 2 2 Φ) = 0 (3.18)<br />

where r =1/n. The scaling used here is Y = y/h, X = x/h, andu◦ = uQ/h where Q is <strong>the</strong> <strong>flow</strong> rate. By using<br />

<strong>the</strong> power series method with Φ = Y σ amY m <strong>the</strong> solution <strong>of</strong> <strong>the</strong> above equation will be given by<br />

Φ ≈ A + BY + CY r+1 + DY r+2<br />

where A, B, C, and D are constant, and σ =0, 1, r+1, and r + 2 are <strong>the</strong> four roots <strong>of</strong> <strong>the</strong> indicial equation<br />

associated with Equation (3.18). Since r is not an integer, in general, <strong>the</strong> third and fourth terms are weakly<br />

singular, as noted. And in order to satisfy <strong>the</strong> boundary conditions at <strong>the</strong> center line <strong>of</strong> <strong>the</strong> channel, that <strong>the</strong><br />

solution is odd or even, requires that ei<strong>the</strong>r A and C or B and D are zero respectively. But it would be very<br />

difficult to distinguish numerically between Y r+1 and Y r+2 because <strong>the</strong>y are generally high powers.<br />

4. RESULTS AND DISCUSSION<br />

Table 1. The Values <strong>of</strong> α for <strong>the</strong> Newtonian Case.<br />

Eigenvalue α<br />

1 2.106196 + i1.125364<br />

2 3.748838 + i1.384339<br />

3 5.356269 + i1.551574<br />

4 6.949978 + i1.671049<br />

5 8.536682 + i1.775544<br />

6 10.119259 + i1.85838<br />

The problem <strong>of</strong> this paper has been reduced to a linear two-point boundary-value problem for a fourthorder<br />

differential equation which is linearized on <strong>the</strong> assumption <strong>of</strong> small disturbance from <strong>the</strong> fully-developed<br />

parallel <strong>flow</strong>, leading to <strong>the</strong> eigenvalue equation given in (3.15). Several numerical methods have previously<br />

been used to solve eigenvalue equations. For example, Bramley and Dennis [5] calculated <strong>the</strong> eigenvalues for<br />

<strong>the</strong> stationary perturbation <strong>of</strong> Poiseuille <strong>flow</strong> (Newtonian case) by expanding Φ and its derivatives in terms <strong>of</strong><br />

Chebyshev polynomials. In fact, <strong>the</strong> same method is used by Orszag [6] to get an accurate solution <strong>of</strong> <strong>the</strong> Orr–<br />

Sommerfeld stability equation. Stocker and Duck [7] have also used <strong>the</strong> method to investigate <strong>the</strong> eigenvalues for<br />

<strong>the</strong> stationary perturbation <strong>of</strong> Couette–Poiseuille <strong>flow</strong>. While this method has proven to be accurate we adopt<br />

a more straightforward and suitable one for our equations which are more complex than those investigated by<br />

<strong>the</strong> previously mentioned authors.<br />

Equation (3.15) is solved numerically using <strong>the</strong> NAG routines D02CAF (Adams method) and C02NBF (Powell<br />

hybrid method) with <strong>the</strong> boundary conditions in (3.16), giving <strong>the</strong> eigenvalues α for different values <strong>of</strong> k.<br />

January 2006 The Arabian Journal for Science and Engineering, Volume 31, Number 1A. 107

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