Information for Physics 1201 Midterm 2 Wednesday, March 27
Information for Physics 1201 Midterm 2 Wednesday, March 27
Information for Physics 1201 Midterm 2 Wednesday, March 27
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The Human Eye<br />
(a)<br />
(b)<br />
do = ∞, di = −( 10.0 − 2.0)<br />
= −8.0 cm<br />
1<br />
f<br />
= 1<br />
d o<br />
+ 1<br />
d i<br />
= 1<br />
∞ +<br />
1<br />
−8.0<br />
( )<br />
di = −( 8.0 − 2.0)<br />
= −6.0 cm<br />
1<br />
d o<br />
= 1<br />
f<br />
− 1<br />
d i<br />
=<br />
1<br />
( −8.0)<br />
−<br />
∴ N = 24.0 + 2.0 = 26.0 cm<br />
= −<br />
1<br />
8.0 cm<br />
We want a virtual,<br />
upright image at the<br />
person’s near point<br />
We want a virtual,<br />
upright image at the<br />
person’s far point<br />
⇒ f = −8.0 cm<br />
f < 0, diverging lens<br />
1<br />
−6.0<br />
( ) = 0.0417 cm−1 ⇒ d o = 24.0 cm<br />
Close to the normal<br />
near point of 25 cm
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