A solution and solid state study of niobium complexes University of ...
A solution and solid state study of niobium complexes University of ...
A solution and solid state study of niobium complexes University of ...
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Chapter 5<br />
The values <strong>of</strong> k1, k-1 <strong>and</strong> K1 (first reaction) obtained from fits <strong>of</strong> the data to Equation<br />
5.9 are given in Table 5.2. Similarly, the values for the rate constants k2 <strong>and</strong> k-2,<br />
together with the values obtained for the stability constant for the first step, K1, from<br />
fits <strong>of</strong> the data to Equation 5.12 are also given in Table 5.2.<br />
Table 5.2: Rate constants for both the fast <strong>and</strong> slow reactions.<br />
Rate Constants 15 °C 25 °C<br />
Fast Reaction<br />
35 °C 45 °C<br />
k1 (M -1 s -1 ) a<br />
96 (2) 237 (4) 574 (6) 1440 (15)<br />
k-1 (s -1 ) a<br />
0.051 (6) 0.12 (1) 0.29 (4) 0.66 (6)<br />
K1 (M -1 ) b<br />
1882 (216) 1975 (201)<br />
Slow Reaction<br />
1979 (273) 2181 (235)<br />
k2 (s -1 ) c<br />
1.51 (8) x 10 -5 3.7 (3) x 10 -5 8.0 (9) x 10 -5 15.1 (9) x 10 -5<br />
k-2 (s -1 ) c<br />
0.91 (8) x 10 -5 1.8 (4) x 10 -5 3.9 (8) x 10 -5 10.1 (8) x 10 -5<br />
K1 (M -1 ) c<br />
1356 (231) 1403 (379) 1213 (604) 1695 (303)<br />
K2 d<br />
1.6 (2) 2.0 (5) 2.1 (6) 1.5 (2)<br />
a b c d<br />
Fig. 5.7, Eq. 5.9; Fig. 5.7, Eq. 5.10; Fig. 5.8, Eq. 5.12; Fig. 5.8, Eq. 5.11<br />
It is clear from Table 5.2 <strong>and</strong> Figures 5.9 <strong>and</strong> 5.10 that the fits <strong>of</strong> the rate data are<br />
representative <strong>of</strong> the rate law, indicating specifically that the equilibrium constant for<br />
the fast, first reaction (although with large esd’s) agrees quite well with the second<br />
observed reaction which describes the total process.<br />
Figure 5.9 <strong>and</strong> Figure 5.10 shows the Eyring plots <strong>of</strong> the data in Table 5.2, to yield<br />
the activation parameters for the two steps. The Eyring equation is given as:<br />
k ΔH k ΔS<br />
ln = ≠ ln B ≠<br />
T RT h R<br />
(5.13)<br />
With ∆H ‡ = enthalpy <strong>of</strong> activation, ∆S ‡ = entropy <strong>of</strong> activation, kB = Boltzmann<br />
constant, R = gas constant <strong>and</strong> h = Planck’s constant.<br />
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