A solution and solid state study of niobium complexes University of ...
A solution and solid state study of niobium complexes University of ... A solution and solid state study of niobium complexes University of ...
Chapter 5 Under pseudo-first order conditions with [acacH] >>> [Mtot], the following equation for the observed rate, kobs, can be obtained: 5.3.4 Discussion k K [acacH] k = 2 1 +k obs 1+K [ acacH] -2 1 89 (5.8) The following conclusions are made from Scheme 5.1 and the derived rate law (Eq. 5.8): The fast, first reaction (observed on the stopped-flow apparatus) can be attributed to the formation of the Nb-acacH intermediate, [Nb(Cl)2(OMe)3 (acacH)]. When this fast reaction (k1 path) is considered in isolation, the following simple, reversible equation can be derived: [ ] k =k L +k obs 1 -1 (5.9) It follows from Equation 5.9 that plots of kobs vs [acacH] should be linear with the slope = k1 and the intercept = k-1. The equilibrium constant, K1, is defined by Equation 5.10: k K = 1 1 k-1 (5.10) The fact that the slower observed reaction, producing the chelated final acac complex, yielded non-linear plots for kobs vs [acacH], indicates that the results obtained here account for the overall reaction, requiring the data to be fitted to the overall rate law (Eq. 5.8). The values of k2, k-2 and K1 should be obtained from fits of kobs vs [acacH]. The equilibrium constant, K2, can be determined from Equation 5.11: k K = 2 2 k-2 (5.11)
Chapter 5 The Stopped-flow data (fast) obtained at four different temperatures was fitted to Equation 5.9 and the UV/Vis data (slow reaction) was fitted to Equation 5.12. The results are illustrated in Figures 5.7 and 5.8 respectively. 90 1 [ ] [ ] k 2 K1 L k = +k obs 1+K L -2 45 °C 35 °C 25 °C 15 °C (5.12) Figure 5.7: Plot of kobs vs [acacH] for the fast reaction between [NbCl2(OMe)3(MeOH] and [acacH] in MeOH at different temperatures, [Nb] = 5 x 10 -5 M, λ = 330 nm. 45 °C 35 °C 25 °C 15 °C Figure 5.8: Plot of kobs vs [acac] for the slow reaction between [NbCl2(OMe)3(MeOH)] and [acacH] in MeOH at different temperatures, [Nb] = 5 x 10 -5 M, λ = 310 nm.
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Chapter 5<br />
Under pseudo-first order conditions with [acacH] >>> [Mtot], the following equation for<br />
the observed rate, kobs, can be obtained:<br />
5.3.4 Discussion<br />
k K [acacH]<br />
k =<br />
2 1<br />
+k<br />
obs 1+K [ acacH]<br />
-2<br />
1<br />
89<br />
(5.8)<br />
The following conclusions are made from Scheme 5.1 <strong>and</strong> the derived rate law (Eq.<br />
5.8):<br />
The fast, first reaction (observed on the stopped-flow apparatus) can be<br />
attributed to the formation <strong>of</strong> the Nb-acacH intermediate, [Nb(Cl)2(OMe)3<br />
(acacH)]. When this fast reaction (k1 path) is considered in isolation, the<br />
following simple, reversible equation can be derived:<br />
[ ]<br />
k =k L +k<br />
obs 1 -1<br />
(5.9)<br />
It follows from Equation 5.9 that plots <strong>of</strong> kobs vs [acacH] should be linear with<br />
the slope = k1 <strong>and</strong> the intercept = k-1. The equilibrium constant, K1, is defined<br />
by Equation 5.10:<br />
k<br />
K =<br />
1<br />
1 k-1<br />
(5.10)<br />
The fact that the slower observed reaction, producing the chelated final acac<br />
complex, yielded non-linear plots for kobs vs [acacH], indicates that the results<br />
obtained here account for the overall reaction, requiring the data to be fitted<br />
to the overall rate law (Eq. 5.8). The values <strong>of</strong> k2, k-2 <strong>and</strong> K1 should be<br />
obtained from fits <strong>of</strong> kobs vs [acacH]. The equilibrium constant, K2, can be<br />
determined from Equation 5.11:<br />
k<br />
K =<br />
2<br />
2 k-2<br />
(5.11)