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WAVES AND VIBRATIONS IN INHOMOGENEOUS STRUCTURES ...

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TOPOLOGY OPTIMIZATION WITH PADÉ APPROXIMANTS 1607<br />

variables. The present paper is related to these works [15, 16] but focuses on optimization problems<br />

with a large number of design variables such as found in topology optimization.<br />

In Section 2 it is shown how the PA is computed and the validity of the approximation is demonstrated<br />

with simple examples along with a discussion of the importance of numerical precision.<br />

In Section 3 the sensitivity analysis of a PA response function with respect to a set of design<br />

variables is treated in detail. The approach is based on adjoint analysis which makes the<br />

method suitable for the case of many design variables. Two examples of topology optimization of<br />

forced vibration problems with PAs are presented in Section 4. Finally, conclusions are given in<br />

Section 5.<br />

2. FREQUENCY RESPONSES WITH PADÉ APPROXIMANTS<br />

The basis of the proposed method is the computation of the frequency response using a PA. The<br />

proposed procedure differs slightly from what appears to be the standard implementation of method<br />

(see e.g. [5]). The difference will be pointed out in the following.<br />

Time-harmonic motion of a linear damped dynamic system is governed by the discretized set<br />

of equations<br />

in which the system matrix S is defined as<br />

Su = f (2)<br />

S =− 2 M + iC + K (3)<br />

M is the mass matrix, C the damping matrix, K the stiffness matrix, and f is the loading vector.<br />

The frequency of excitation is denoted and u is a vector containing the discretized nodal values<br />

of the complex amplitude function.<br />

An approximate solution for u is now sought in the vicinity of some expansion frequency 0.<br />

The de-tuning parameter:<br />

= − 0<br />

is used to define the closeness of the excitation frequency to this expansion frequency.<br />

Equation (2) is rewritten as<br />

in which the new matrices are defined as<br />

(P0 + P1 1 + P2 2 )u = f (5)<br />

P0 = S(0) =− 2 0 M + i0C + K (6)<br />

P1 = S<br />

(0) =−20M + iC (7)<br />

P2 = 1 <br />

2<br />

2 S<br />

2 (0) =−M (8)<br />

Copyright q 2007 John Wiley & Sons, Ltd. Int. J. Numer. Meth. Engng 2007; 72:1605–1630<br />

DOI: 10.1002/nme<br />

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