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COAL - Clpdigital.org

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48<br />

larly careful to use the full cylindrical contents<br />

of the fan as the volumetric efficiency will be abnormally<br />

high on account of not using the full<br />

cylindrical contents. All fans at low or no resistance<br />

will put-out cent per cent, of their displacement<br />

volume every minute, or every revolution<br />

when run at proper speed, but in Guibal fans<br />

proper and their many modified forms the diminution<br />

of out-put is an inverse ratio somewhat<br />

greater than the increase in the water gauge or<br />

lesistance.<br />

THE MECHANICAL EFFICIENCY<br />

of the fan is obtained by carefully ascertaining the<br />

power developed by the engine driving it, on the<br />

one hand, and the power given out by the fan in<br />

delivering air in the mine and overcoming resistance<br />

on the other hand. The proportion these<br />

two powers bear to one another is the mechanical<br />

efficiency. Thus it is we have a plant in which<br />

the engine developed 20 horse power and the fan<br />

it drives gives 60,000 cubic feet of air per minute;<br />

at one and 3-10 inch water gauge, this will give<br />

a mechanical efficiency of 62.35. The indicated<br />

horsepower of the engine is generally used in the<br />

calculations of the fan's duty and gives results<br />

against the fan by the amount of power used to<br />

overcome the resistance of the engine itself, and<br />

in the best constructed fans by the additional<br />

power lost in transmission.<br />

"One very important point in obtaining the<br />

manometrical efficiency of the fan, is the placing<br />

and reading of the water gauge and the notation of<br />

other necessary observations at a point not less<br />

than 20 feet from the inlet, if an exhaust fan and<br />

whether an exhaust or blowing fan it should be so<br />

placed that the pipe leading to the gauge be out<br />

of the flow of the air, and not within the influence<br />

of an eddy. Many eminent German authorities<br />

place the gauge pipe in a recess and place over its<br />

mouth several thicknesses of flannel in order to<br />

obtain the true statistical gauge. Long pipes<br />

and pipes of small diameter leading from fan drift<br />

to gauges placed in offices or at distant points are<br />

not to be recommended as friction or leakage may<br />

render them unreliable. Under no condition<br />

should a water gauge be placed upon the fan case.<br />

A difference of as much as 400 per cent, has been<br />

noted from this cause: the gauge showing higher<br />

reading the nearer it is placed to the center. This<br />

remark applies more particularly to single inlet<br />

fans."<br />

The manometrical efficiency of fans is found by<br />

the gauge obtained in a preceding formula divided<br />

into the gauge read, thus, by calculation a 10"<br />

water gauge is obtained, and we note a difference<br />

of 6 inches in the legs of the water gauge, then<br />

the result obtained would show a manometrical<br />

efficiency of 60 6-10 per cent.; manometrical ef­<br />

THE <strong>COAL</strong> TRADE BULLETIN.<br />

ficiency is high in many fans which are low in mechanical<br />

efficiency and still lower in volumetric<br />

efficiency.<br />

The practical application of the law and formula<br />

enumerated above is to enable us to intelligently<br />

select a fan for the duty to be performed, to blow<br />

equal quantities through equal areas in equal<br />

times. The pressure varies inversely as the<br />

fourth powers of the diameters of the orifices, and<br />

to prove the statement, let the quantity be 150,000<br />

cubic feet of air per minute, and let the pressure<br />

for an orifice 10 feet in diameter be 3 inches of<br />

water gauge, then the pressure per square foot<br />

required to blow the same volume of air per minute<br />

through an orifice 5 feet in diameter is equal<br />

to the fourth power multiplied by three inches of<br />

water gauge, equaling 448 inches water gauge.<br />

To obtain the best results from the ventilating<br />

fan the depression necessary for the entry of the<br />

air should, if possible, not exceed one pound per<br />

square foot; hence the velocity should<br />

NOT EXCEED 18 FEET PER SECOND.<br />

for by formula where V equals velocity and P equals<br />

pressure, the square root of the pressure multiplied<br />

by 18 equals the velocity in feet per second;<br />

then by using quantity the port of entry may be<br />

found by the following formula.<br />

Where Q equals quantity and D equals diameter<br />

of the port of entry, .0343 a factor proven by experiments,<br />

we have the following equation:<br />

.0343 multiplied by the square root of the quantity<br />

equals D. or in other words, the square root of the<br />

quantity multiplied by .0343 equals the diameter of<br />

the port of entry.<br />

Then by the square of the volume obtained and<br />

the resistance by which it is obtained, we are enabled<br />

to calculate the dimensions of the fan we<br />

want and what speed we must drive it to obtain<br />

a desired larger volume. For the benefit of the<br />

practical members present who have not had the<br />

opportunities of an education, we will go through<br />

the steps required to determine tip speed and<br />

increased quantities. Suppose we have a fan<br />

producing 72,000 cubic feet of air per minute at<br />

1.75 inch water gauge, and we want to increase<br />

that volume to 200,000 cubic feet per minute. Our<br />

first step would be to find the water gauge due to<br />

the increased volume. This may be found by the<br />

square of the quantities and we find that if it required<br />

1.75 inch water gauge to produce 72,000<br />

cubic feet per minute, it will require<br />

200<br />

2x1.75=13.5<br />

72<br />

water gauge to produce 200,000 cubic feet per minute,<br />

all other conditions remaining the same. In<br />

our next formula we will show how to find the tip<br />

speed from the water gauge. By an equation we

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