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Antti Lehtinen Doppler Positioning with GPS - Matematiikan laitos

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If the measurements and other data were ideal, the positioningsolution would<br />

also be perfect. Thus setting ɛ ˙ρ = 0 indicates that ɛx = 0. Applyingthese for<br />

the equation 5.11 gives us<br />

x − xk = [G(xk)] T [G(xk)] −1 [G(xk)] T<br />

<br />

˙ρ T − ˆ˙ρ (5.12)<br />

Now subtractingthe equation 5.12 from the equation 5.11 yields<br />

ɛx = [G(xk)] T [G(xk)] −1 [G(xk)] T ɛ ˙ρ<br />

(5.13)<br />

Let us simplify things by assuming the last linearization point xk to be very close<br />

to the true position and drift x. Now the matrix G(xk) can be approximated<br />

by the <strong>Doppler</strong> geometry matrix G(x), which will be denoted G. Finally, we<br />

have an equation that approximates the effect of the measurement errors on the<br />

positioningsolution:<br />

ɛx = G T G −1 T<br />

G ɛ ˙ρ<br />

(5.14)<br />

5.2.2 <strong>Doppler</strong> Dilution of Precision<br />

The equation 5.14 can be used to calculate the error in the positioningestimate<br />

if the measurement error ɛ ˙ρ is known. Unfortunately, ɛ ˙ρ can never be known. If<br />

the error was known it could be compensated and there would be no error at all.<br />

However, one should thrive to achieve an estimate for the accuracy of the solution.<br />

Otherwise, the user cannot really trust that the solution is even near the right<br />

one. The positioningerror can be estimated by statistical methods. For that<br />

we need some knowledge or assumptions about the statistical properties of the<br />

measurement error ɛ ˙ρ. Letusassume the following:<br />

• The measurement errors are zero mean, that is their expected values are<br />

zero:<br />

E {ɛ ˙ρ} = 0 (5.15)<br />

• The measurements from different satellites have uncorrelated errors and<br />

equal variances σ 2 ˙ρ:<br />

cov(ɛ ˙ρ) =E ɛ ˙ρɛ ˙ρ T = σ 2 ⎢<br />

˙ρIn×n = ⎢<br />

⎣<br />

36<br />

⎡<br />

σ2 ˙ρ 0 ··· 0<br />

0 σ2 ˙ρ ··· 0<br />

.<br />

.<br />

...<br />

0 0 ··· σ 2 ˙ρ<br />

.<br />

⎤<br />

⎥<br />

⎦<br />

(5.16)

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