Antti Lehtinen Doppler Positioning with GPS - Matematiikan laitos
Antti Lehtinen Doppler Positioning with GPS - Matematiikan laitos
Antti Lehtinen Doppler Positioning with GPS - Matematiikan laitos
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Fortunately, findingthe matrix G by algebraic differentiation of the function<br />
p(ˆx) is quite straightforward. Let us consider the differentiation in detail:<br />
G = ∂p<br />
∂ ˆx =<br />
⎡<br />
⎢<br />
∂p ⎢<br />
= ⎢<br />
ˆru<br />
∂<br />
⎢<br />
ˆd<br />
⎢<br />
⎣<br />
∂p1<br />
∂ ˆru<br />
∂p1<br />
∂ ˆ ∂p2<br />
∂ ˆru<br />
d<br />
∂p2<br />
∂ ˆ .<br />
∂pn<br />
d<br />
.<br />
∂pn<br />
∂ ˆru ∂ ˆ ⎤<br />
⎥ ∈ R<br />
⎥<br />
⎦<br />
d<br />
n×4<br />
(4.23)<br />
where pi are the components of the vector function p. Usingthe Definition 3,<br />
one obtains an expression for a single component of the vector function p. This<br />
can be written as<br />
pi(ˆx) =vi • ri − ˆru<br />
ri − ˆru + ˆ d − ˙ρi<br />
(4.24)<br />
Differentiatingthe ith component of the delta range residuals function p(ˆx) partially<br />
<strong>with</strong> respect to the estimated receiver position ˆru yields<br />
∂pi<br />
∂ ˆru<br />
= ∂<br />
∂ ˆru<br />
<br />
vi • ri − ˆru<br />
ri − ˆru + ˆ d − ˙ρi<br />
<br />
(4.25)<br />
In equation 4.25 vi, ri, ˆ d and ρi are constants <strong>with</strong> respect to the estimated<br />
receiver position ˆru. Applyingthe formula (fg) ′ = f ′ g + fg ′ for differentiating<br />
products gives us<br />
∂pi<br />
∂ ˆru<br />
= vi • (ri − ˆru) ∂ 1<br />
∂ ˆru ri − ˆru +<br />
vT i ∂<br />
(ri − ˆru)<br />
ri − ˆru ∂ ˆru<br />
1<br />
= vi • (ri − ˆru)<br />
ri − ˆru 2<br />
(ri − ˆru) T<br />
ri − ˆru −<br />
vT i<br />
ri − ˆru I3×3<br />
<br />
vi<br />
=<br />
ri − ˆru • ri<br />
<br />
− ˆru ri − ˆru<br />
ri − ˆru ri − ˆru<br />
<br />
ri − ˆru<br />
−<br />
ri − ˆru • ri<br />
T − ˆru vi<br />
ri − ˆru ri − ˆru<br />
where I3×3 is 3 × 3 identity matrix.<br />
(4.26)<br />
The equation 4.26 gives the partial derivative of the delta range residuals function<br />
<strong>with</strong> respect to the receiver position estimate. The form of the equation is<br />
satisfactory for numerical computation. However, the form is not very intuitive.<br />
The right hand side of the equation 4.26 can be transformed into a geometrically<br />
more illustrative form involvingcross products. Makinguse of the vector triple<br />
28