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Experiments with Supersonic Beams as a Source of Cold Atoms

Experiments with Supersonic Beams as a Source of Cold Atoms

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magnetic field will adiabatically follow the field so long <strong>as</strong> the Larmor frequency is<br />

much larger than the rate <strong>of</strong> change <strong>of</strong> the direction <strong>of</strong> the magnetic field. If this<br />

condition, expressed <strong>as</strong><br />

ωL ≫ d<br />

<br />

B<br />

,<br />

dt |B|<br />

(4.16)<br />

is met, then the equations for the Hamiltonian and for the energy shift do not depend<br />

on B, but instead will depend on | B|, which is hereafter simply referred to <strong>as</strong> B.<br />

This condition is e<strong>as</strong>ily met for most magnetic fields described in this dissertaion,<br />

and special note is made <strong>of</strong> situation where it may not be met.<br />

4.2 Magnetic Fields from Electromagnetic Coils<br />

Pulsed electromagnetic coils are used to produce the high magnetic fields nec-<br />

essary to effectively control the velocity <strong>of</strong> a supersonic beam. From the differential<br />

form <strong>of</strong> Ampère’s law<br />

∇× B = μ0 J, (4.17)<br />

where J is current density and μ0 is the permeability <strong>of</strong> free space, it is possible to<br />

derive the Biot-Savart law<br />

B = μ0<br />

<br />

I d<br />

4π C<br />

<br />

ℓ × x<br />

|x| 3 , (4.18)<br />

where I is the current and d ℓ is the infinitesimal path <strong>of</strong> the current [74] (this also<br />

<strong>as</strong>sumes a wire <strong>with</strong> zero cross-sectional area). From this, the magnetic field from<br />

a particular current path can be found. Of particular interest is the magnetic field<br />

from a circular loop <strong>of</strong> wire <strong>of</strong> radius r. The cylindrically symmetric field generated<br />

by this loop can be found exactly <strong>as</strong> [75]<br />

Bz = μ0I<br />

2π<br />

<br />

1<br />

K(k<br />

(r + ρ) 2 +(z) 2<br />

2 )+ r2 − ρ2 − z2 (r − ρ) 2 + z2 E(k2 <br />

)<br />

63<br />

(4.19)

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