Experiments with Supersonic Beams as a Source of Cold Atoms
Experiments with Supersonic Beams as a Source of Cold Atoms
Experiments with Supersonic Beams as a Source of Cold Atoms
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field. In the L − S coupling regime (<strong>as</strong> opposed to jj coupling which is more common<br />
for heavier atoms) the magnetic moment <strong>of</strong> an atom is<br />
<br />
μatom = −μB gl <br />
li + gssi = −μB gL L + gS <br />
S , (4.4)<br />
i<br />
where μB is the Bohr magneton, and gL and gS are the “g-factors” for the orbital and<br />
spin angular momenta respectively. Thus the Hamiltonian becomes<br />
HB = μB<br />
<br />
gL L + gS <br />
S · B. (4.5)<br />
The manner in which the magnetic moment is calculated depends on the ratio <strong>of</strong> this<br />
Hamiltonian to the Hamiltonian which produces the fine structure splitting.<br />
4.1.1 The Zeeman Effect<br />
If the interaction due to the Hamiltonian in equation 4.5 is much smaller<br />
than the fine structure splitting, then J will remain a good quantum number. In<br />
this regime, called the Zeeman regime, the individual orbital angular momentum<br />
vector L and the spin angular momentum vector S precess around the sum <strong>of</strong> these<br />
vectors, the total angular momentum vector J. This in turn precesses around the<br />
external magnetic field, where the projection <strong>of</strong> J in the direction <strong>of</strong> the magnetic<br />
field (quantization axis) determines the magnetic moment <strong>of</strong> the atom. In this picture,<br />
<strong>as</strong> L and S precess around J, their projections along the direction <strong>of</strong> the magnetic<br />
field are rapidly changing, meaning that these projections (Lz and Sz) arenotgood<br />
quantum numbers. However, since the projection <strong>of</strong> J along the quantization axis<br />
remains constant, the eigenvalues <strong>of</strong> the operator Jz will remain constant, making mJ<br />
a good quantum number. This situation is illustrated in figure 4.1.<br />
Since mJ is a good quantum number, but not mL and mS, the equation for<br />
the Hamiltonian (equation 4.5) must be expressed in terms <strong>of</strong> J. Thisisdoneusing<br />
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