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Experiments with Supersonic Beams as a Source of Cold Atoms

Experiments with Supersonic Beams as a Source of Cold Atoms

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Since there will be no heat exchange between the g<strong>as</strong> and the environment during the<br />

expansion, equations 2.5 and 2.7 become<br />

and<br />

0=deint + P d<br />

<br />

1<br />

, (2.8)<br />

ρ<br />

0=dh− 1<br />

dP. (2.9)<br />

ρ<br />

The specific heats at constant pressure, cP , and at constant volume, cV ,are<br />

given by cP = dh<br />

dT<br />

<br />

P and cV = deint<br />

dT<br />

<br />

V<br />

, and their ratio, γ = cP<br />

cV ,isaconstantforan<br />

ideal g<strong>as</strong> that depends only on the number <strong>of</strong> degrees <strong>of</strong> freedom <strong>of</strong> a g<strong>as</strong> molecule.<br />

Using these relations, equations 2.8 and 2.9, can be re-expressed and combined <strong>as</strong> [8]<br />

γ dρ<br />

ρ<br />

− dP<br />

P<br />

This l<strong>as</strong>t relation is <strong>of</strong> particular use in examining the g<strong>as</strong> flow.<br />

=0. (2.10)<br />

There are several conservation laws that can be used to simplify the problem<br />

<strong>of</strong> g<strong>as</strong> flow through a nozzle. Clearly, conservation <strong>of</strong> m<strong>as</strong>s applies in the flow, g<strong>as</strong><br />

particles are not being spontaneously created or annihilated. This is expressed <strong>as</strong><br />

or simplified for 1D flow <strong>as</strong><br />

dw<br />

w<br />

∇ (ρw) = 0 (2.11)<br />

+ dρ<br />

ρ<br />

+ dA<br />

A<br />

= 0 (2.12)<br />

where w is the velocity <strong>of</strong> the flow, ρ is the density <strong>of</strong> the g<strong>as</strong>, and A is the cross-<br />

sectional area <strong>of</strong> the flow. Momentum is also conserved in the flow, which is essentially<br />

an expression <strong>of</strong> Newton’s second law in the g<strong>as</strong>. Assuming no external forces on the<br />

g<strong>as</strong><br />

Dw<br />

Dt<br />

= −∇P<br />

ρ<br />

10<br />

(2.13)

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