Experiments with Supersonic Beams as a Source of Cold Atoms
Experiments with Supersonic Beams as a Source of Cold Atoms
Experiments with Supersonic Beams as a Source of Cold Atoms
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As the pressure in the g<strong>as</strong> reservoir is incre<strong>as</strong>ed, the mean free path decre<strong>as</strong>es<br />
accordingly. When the pressure is high enough, the mean free path will decre<strong>as</strong>e to<br />
the point that d>λ. When this condition is met, the g<strong>as</strong> enters the continuum regime<br />
near the nozzle and can be treated <strong>as</strong> a compressible fluid. The principle advantages<br />
<strong>of</strong> this regime are the greatly decre<strong>as</strong>ed temperature <strong>of</strong> the atoms in the beam, and<br />
incre<strong>as</strong>ed brightness due to higher reservoir pressures, larger nozzle diameter, and<br />
incre<strong>as</strong>ed directionality <strong>of</strong> the beam.<br />
2.1.1 Steady State G<strong>as</strong> Flow in 1D<br />
To examine what can be expected in the d>λregime, it is instructive to<br />
examine the flow <strong>of</strong> an ideal g<strong>as</strong> through p<strong>as</strong>sages <strong>with</strong> changing cross-sectional area<br />
(this is presented in detail in [8–10] and the discussion here follows the presentation<br />
in [8]). To do this effectively, some <strong>of</strong> the b<strong>as</strong>ic thermodynamic properties <strong>of</strong> ideal<br />
g<strong>as</strong>es are needed. To start <strong>with</strong>, the ideal g<strong>as</strong> law (equation 2.1) can be expressed <strong>as</strong><br />
P = ρkBT<br />
m<br />
, (2.4)<br />
where ρ is the density <strong>of</strong> the g<strong>as</strong>. Letting eint be the internal energy <strong>of</strong> the g<strong>as</strong> per unit<br />
m<strong>as</strong>s, the heat transfered to an unchanging quantity <strong>of</strong> an ideal g<strong>as</strong>, dq, at constant<br />
pressure is<br />
and the enthalpy per unit m<strong>as</strong>s is<br />
dq =deint + P d<br />
<br />
1<br />
, (2.5)<br />
ρ<br />
h = eint + P<br />
ρ = eint + kBT<br />
. (2.6)<br />
m<br />
Using equation 2.5 and equation 2.6, along <strong>with</strong> the fact that the internal energy <strong>of</strong><br />
an ideal g<strong>as</strong> depends only on the temperature, produces<br />
dq =dh− 1<br />
dP. (2.7)<br />
ρ<br />
9